警告消息“没有匹配的信号”
A warning message “No matching signal for”
我正在使用基于 qt4
的 qt-ros
来构建应用程序。
但是有个问题signal & slot
不行
我使用的vlc-qt库提供了一个叫played的信号函数,如下面的link所示。
vlc-qt
我尝试通过创建适当的 slot
函数来连接到 QMetaObject :: connectSlotsByName
方法,但它无法使用警告 "No matching signal for".
在mainWindow.h
public Q_SLOTS:
void on_vListPlayer_played();
并在 mainWindow.cpp
void MainWindow::on_vListPlayer_played()
{
ROS_INFO("player started!------------------------------");
}
...
MainWindow::MainWindow(int argc, char** argv, QWidget *parent)
: QMainWindow(parent)
, qnode(argc,argv)
{
ui.setupUi(this); // Calling this incidentally connects all ui's triggers to on_...() callbacks in this class.
// UI Init
QWidget* mainWidget = new QWidget(this);
this->setCentralWidget(mainWidget);
mainWidget->setStyleSheet("background-color: black;");
QVBoxLayout* mainLayout = new QVBoxLayout;
mainLayout->setMargin(0);
mainLayout->setSpacing(0);
mainWidget->setLayout(mainLayout);
m_vVideoWidget = new VlcWidgetVideo;
mainLayout->addWidget(m_vVideoWidget);
m_vInstance = new VlcInstance(VlcCommon::args(), this);
m_vPlayer = new VlcMediaPlayer(m_vInstance);
m_vPlayer->setVideoWidget(m_vVideoWidget);
vListPlayer = new VlcMediaListPlayer(m_vPlayer, m_vInstance);
QObject::connect(vListPlayer, SIGNAL(played()), this, SLOT(on_vListPlayer_played()));
m_vVideoWidget->setMediaPlayer(m_vPlayer);
m_vList = new VlcMediaList(m_vInstance);
openVideoes(m_DataPath);
vListPlayer->setMediaList(m_vList);
vListPlayer->setPlaybackMode(Vlc::PlaybackMode::Repeat);
vListPlayer->mediaPlayer()->play();
...
}
在 MediaListPlayer.h(vlc-qt 库)
class VLCQT_CORE_EXPORT VlcMediaListPlayer : public QObject
{
Q_OBJECT
......
public Q_SLOTS:
void itemAt(int index);
void next();
void play();
void previous();
void stop();
Q_SIGNALS:
void played();
void nextItemSet(VlcMedia *media);
void nextItemSet(libvlc_media_t *media);
void stopped();
您正在使用 Qt Designer,生成的代码(由 ui.setupUi(this);
调用)调用 QMetaObject::connectSlotsByName(QObject *object)
。
根据 Qt documentation 这会尝试连接所有名称与以下模式匹配的插槽:void on_<object name>_<signal name>(<signal parameters>);
由于插槽 void on_vListPlayer_played()
与模式匹配,因此尝试连接它。但是失败了,因为你没有任何对象 named vListPlayer
.
对于你的情况,我建议你重命名你的插槽,这样它们就不会匹配模式并且不会自动连接。
我正在使用基于 qt4
的 qt-ros
来构建应用程序。
但是有个问题signal & slot
不行
我使用的vlc-qt库提供了一个叫played的信号函数,如下面的link所示。 vlc-qt
我尝试通过创建适当的 slot
函数来连接到 QMetaObject :: connectSlotsByName
方法,但它无法使用警告 "No matching signal for".
在mainWindow.h
public Q_SLOTS:
void on_vListPlayer_played();
并在 mainWindow.cpp
void MainWindow::on_vListPlayer_played()
{
ROS_INFO("player started!------------------------------");
}
...
MainWindow::MainWindow(int argc, char** argv, QWidget *parent)
: QMainWindow(parent)
, qnode(argc,argv)
{
ui.setupUi(this); // Calling this incidentally connects all ui's triggers to on_...() callbacks in this class.
// UI Init
QWidget* mainWidget = new QWidget(this);
this->setCentralWidget(mainWidget);
mainWidget->setStyleSheet("background-color: black;");
QVBoxLayout* mainLayout = new QVBoxLayout;
mainLayout->setMargin(0);
mainLayout->setSpacing(0);
mainWidget->setLayout(mainLayout);
m_vVideoWidget = new VlcWidgetVideo;
mainLayout->addWidget(m_vVideoWidget);
m_vInstance = new VlcInstance(VlcCommon::args(), this);
m_vPlayer = new VlcMediaPlayer(m_vInstance);
m_vPlayer->setVideoWidget(m_vVideoWidget);
vListPlayer = new VlcMediaListPlayer(m_vPlayer, m_vInstance);
QObject::connect(vListPlayer, SIGNAL(played()), this, SLOT(on_vListPlayer_played()));
m_vVideoWidget->setMediaPlayer(m_vPlayer);
m_vList = new VlcMediaList(m_vInstance);
openVideoes(m_DataPath);
vListPlayer->setMediaList(m_vList);
vListPlayer->setPlaybackMode(Vlc::PlaybackMode::Repeat);
vListPlayer->mediaPlayer()->play();
...
}
在 MediaListPlayer.h(vlc-qt 库)
class VLCQT_CORE_EXPORT VlcMediaListPlayer : public QObject
{
Q_OBJECT
......
public Q_SLOTS:
void itemAt(int index);
void next();
void play();
void previous();
void stop();
Q_SIGNALS:
void played();
void nextItemSet(VlcMedia *media);
void nextItemSet(libvlc_media_t *media);
void stopped();
您正在使用 Qt Designer,生成的代码(由 ui.setupUi(this);
调用)调用 QMetaObject::connectSlotsByName(QObject *object)
。
根据 Qt documentation 这会尝试连接所有名称与以下模式匹配的插槽:void on_<object name>_<signal name>(<signal parameters>);
由于插槽 void on_vListPlayer_played()
与模式匹配,因此尝试连接它。但是失败了,因为你没有任何对象 named vListPlayer
.
对于你的情况,我建议你重命名你的插槽,这样它们就不会匹配模式并且不会自动连接。