如何在我的程序集引导加载程序中获取用户输入?
How can I get user input in my assembly bootloader?
我正在开发程序集引导加载程序。我需要帮助获取用户的输入。我使用这样的代码在屏幕上打印(start
)。在 getInput
中,我尝试从用户那里获取输入但没有成功。那么,我该怎么做呢?
org 0x7C00
BITS 16
start:
cli ; Disable interrupts
mov si, bootMsg1 ; Point SI to message
mov ah, 0x0E ; Indicate BIOS we're going to print chars
.loop lodsb ; Loads SI to AL
or al,al ; Checks if the end of string
jz seperate
or al,al
jz halt ; Jump to halt at the end
int 0x10 ; Otherwise, call interrupt for printing the char
jmp .loop ; Next iteration of loop
...
getInput:
cli
mov ah, 08 ; Indicate BIOS to get input
int 21h
mov ah,02
mov DL,AL
int 21h
MOV AH,4Ch ; Function to exit
MOV AL,00 ; Return 00
INT 21h
halt: hlt ; CPU command to halt the execution
bootMsg1: db "Slight Bootloader 1, Welcome!",13,10 ; Message
bootMsg2: db"------------",13,10
使用Int 16h/AH=00h
.
一些输出为 Int 21h/AH=08h
.
Int 16h
has input utilities, Int 10h
has output (video) utilities.
示例。
等待用户按下一个键然后 "reboot".
BITS 16
xor ax, ax
int 16h
int 19h
TIMES 510 - ($-$$) db 0
dw 0aa55h
我正在开发程序集引导加载程序。我需要帮助获取用户的输入。我使用这样的代码在屏幕上打印(start
)。在 getInput
中,我尝试从用户那里获取输入但没有成功。那么,我该怎么做呢?
org 0x7C00
BITS 16
start:
cli ; Disable interrupts
mov si, bootMsg1 ; Point SI to message
mov ah, 0x0E ; Indicate BIOS we're going to print chars
.loop lodsb ; Loads SI to AL
or al,al ; Checks if the end of string
jz seperate
or al,al
jz halt ; Jump to halt at the end
int 0x10 ; Otherwise, call interrupt for printing the char
jmp .loop ; Next iteration of loop
...
getInput:
cli
mov ah, 08 ; Indicate BIOS to get input
int 21h
mov ah,02
mov DL,AL
int 21h
MOV AH,4Ch ; Function to exit
MOV AL,00 ; Return 00
INT 21h
halt: hlt ; CPU command to halt the execution
bootMsg1: db "Slight Bootloader 1, Welcome!",13,10 ; Message
bootMsg2: db"------------",13,10
使用Int 16h/AH=00h
.
一些输出为 Int 21h/AH=08h
.
Int 16h
has input utilities, Int 10h
has output (video) utilities.
示例。
等待用户按下一个键然后 "reboot".
BITS 16
xor ax, ax
int 16h
int 19h
TIMES 510 - ($-$$) db 0
dw 0aa55h