绕过 State 中的不变结果类型

Question

我想定义一个 State 来构建特征的具体子类型，根据 decodeFoo:

sealed trait Foo
case class Bar(s: String) extends Foo
case class Baz(i: Int) extends Foo

val int: State[Seq[Byte], Int] = State[Seq[Byte], Int] {
  case bs if bs.length >= 4 =>
    bs.drop(4) -> ByteBuffer.wrap(bs.take(4).toArray).getInt
  case _ => sys.error(s"Insufficient data remains to parse int")
}

def bytes(len: Int): State[Seq[Byte], Seq[Byte]] = State[Seq[Byte], Seq[Byte]] {
  case bs if bs.length >= len => bs.drop(len) -> bs.take(len)
  case _ => sys.error(s"Insufficient data remains to parse $len bytes")
}

val bytes: State[Seq[Byte], Seq[Byte]] = for {
  len <- int
  bs <- bytes(len)
} yield bs

val string: State[Seq[Byte], String] = bytes.map(_.toArray).map(new String(_, Charset.forName("UTF-8")))

val decodeBar: State[Seq[Byte], Bar] = string.map(Bar)
val decodeBaz: State[Seq[Byte], Baz] = int.map(Baz)

val decodeFoo: State[Seq[Byte], Foo] = int.flatMap {
  case 0 => decodeBar
  case 1 => decodeBaz
}

这不会编译，因为 State 在 cats 中定义为 type State[S, A] 并且编译器响应：

Error:(36, 15) type mismatch;
 found   : cats.data.State[Seq[Byte],FooBarBaz.this.Bar]
    (which expands to)  cats.data.IndexedStateT[cats.Eval,Seq[Byte],Seq[Byte],FooBarBaz.this.Bar]
 required: cats.data.IndexedStateT[cats.Eval,Seq[Byte],Seq[Byte],FooBarBaz.this.Foo]
Note: FooBarBaz.this.Bar <: FooBarBaz.this.Foo, but class IndexedStateT is invariant in type A.
You may wish to define A as +A instead. (SLS 4.5)
    case 0 => decodeBar

我可以通过将 decodeBar 和 decodeBaz 的定义扩展为 State[Seq[Byte], Foo] 类型来解决这个问题。这是最好的前进方式吗？或者我可以采取不同的方法来避免扩大这些类型吗？

Answer 1

Functor.widen

Functor.widen 应该可以解决问题。完整的可编译示例（带有 kind-projector）：

import cats.data.State
import cats.Functor

object FunctorWidenExample {
  locally {
    sealed trait A
    case class B() extends A

    val s: State[Unit, B] = State.pure(new B())
    val t: State[Unit, A] = Functor[State[Unit, ?]].widen[B, A](s)
  }
}

在你的情况下，它会是这样的：

val decodeFoo: State[Seq[Byte], Foo] = int.flatMap {
  case 0 => Functor[State[Seq[Byte], ?]].widen[Bar, Foo](decodeBar)
  case 1 => Functor[State[Seq[Byte], ?]].widen[Bar, Foo](decodeBaz)
}

其他可能的解决方法

（不是必须的，只是为了演示可能不太为人所知的语法）：

显式类型归属：

val decodeFoo: State[Seq[Byte], Foo] = int.flatMap {
  case 0 => decodeBar.map(x => (x: Foo))
  case 1 => decodeBaz.map(x => (x: Foo))
}

用<:<作为方法（那些东西其实是有意义的apply）：

val decodeFoo: State[Seq[Byte], Foo] = int.flatMap {
  case 0 => decodeBar.map(implicitly: Bar <:< Foo)
  case 1 => decodeBaz.map(implicitly: Baz <:< Foo)
}

绕过 State 中的不变结果类型

Getting around invariant result type in State

scala

functor

scala-cats

invariance