如何 return 对象而不是数组中的对象
how to return object instead of object in array
我正在尝试 return 由于 hasMany 关系而来自集合数组的对象的响应。
我试过return$block->where('date','=',$today)->first();
error said: Call to undefined method
App\BlockDate::addEagerConstraints()
public function block_dates()
{
return $this->hasMany(BlockDate::class);
}
public function schedule_block()
{
$today = Carbon::today()->toDateString();
$block = $this->block_dates();
return $block->where('date','=',$today)->first();
}
schedule_block()
应该 return BlockDate
的对象。如果我删除 first()
,它 return 是一个包含所需对象的数组。我只想根据关系检索对象。感谢任何帮助。
试试这个:
public function schedule_block() {
$today = Carbon::today()->toDateString();
return $this->hasOne(BlockDate::class)->where('date','=',$today);
}
我正在尝试 return 由于 hasMany 关系而来自集合数组的对象的响应。
我试过return$block->where('date','=',$today)->first();
error said: Call to undefined method App\BlockDate::addEagerConstraints()
public function block_dates()
{
return $this->hasMany(BlockDate::class);
}
public function schedule_block()
{
$today = Carbon::today()->toDateString();
$block = $this->block_dates();
return $block->where('date','=',$today)->first();
}
schedule_block()
应该 return BlockDate
的对象。如果我删除 first()
,它 return 是一个包含所需对象的数组。我只想根据关系检索对象。感谢任何帮助。
试试这个:
public function schedule_block() {
$today = Carbon::today()->toDateString();
return $this->hasOne(BlockDate::class)->where('date','=',$today);
}