oracle sql 加载程序表达式的最大大小

oracle sql loader maximum size of a expression

我有一个 ctl 文件可以使用 sqlldr,但是表达式的长度大于 258,并且是我可以在查询中获得的最小长度我不可能创建一个字符较少的查询。

我的 ctl 是:

OPTIONS (PARALLEL=TRUE, SILENT=(HEADER,FEEDBACK), ERRORS=1000000)
LOAD DATA
INFILE 'file.csv'
--BADFILE 'file.bad'
APPEND INTO TABLE table1
FIELDS TERMINATED BY "|"
TRAILING NULLCOLS
(
  id_user CONSTANT 2,
  number_user ,
  FULL_TIMESTAMP  date "YYYY-MM-DD HH24:MI:SS",
  id_date ,
  id_time ,
  pn BOUNDFILLER,
  service_name EXPRESSION "select service_name from pack_table where service_name in (select service_name from table_2 where id_number in (select id_number from table_3 WHERE id_user=2 and (id_date between to_char(to_date(:id_date,'YYYYMMDD')-1,'YYYYMMDD') and :id_date) and number_user= :number_user))",
  bill_response ,
  joined CONSTANT 0
)

Oracle 告诉我一个表达式的最大长度是 258 =(

我无法更改表格列的名称。

我的想法是使用其他表达式 BOUNDFILLER,但它对我不起作用 ='(

OPTIONS (PARALLEL=TRUE, SILENT=(HEADER,FEEDBACK), ERRORS=1000000)
LOAD DATA
INFILE '_INFILE_'
--BADFILE '_INFILE_.bad'
APPEND INTO TABLE table1
FIELDS TERMINATED BY "|"
TRAILING NULLCOLS
(
  id_user CONSTANT _MNO_,
  number_user ,
  FULL_TIMESTAMP  date "YYYY-MM-DD HH24:MI:SS",
  id_date ,
  id_time ,
  pn BOUNDFILLER,
  ic "select id_number from (select id_number from table_3 WHERE id_user=2 and (id_date between to_char(to_date(:id_date,'YYYYMMDD')-1,'YYYYMMDD') and :id_date) and number_user= :number_user order by id_date asc) where rownum=1" BOUNDFILLER,
  service_name EXPRESSION "select service_name from pack_table where service_name in (select service_name from table_2 where id_number = :ic)",
  bill_response ,
  joined CONSTANT 0
)

我不知道我能做什么。

谁能帮帮我?

谢谢

将 select 语句移至函数并使用 select myfunction(params) from dual 代替