js object flatten：深度循环Json个objects，然后把objects flatten？

Question

我的JSON对象数据：

{
    "title": "aa",
    "desc": ["i", "j", "k"],
    "cnt": {
        "head": "bb",
        "main": {
            "num1": {
                "time1": "mm",
                "time2": "kk"
            },
            "num2": "dd"
        }
    }
}

我的问题是：如何使用 JavaScript 将上面的 JSON 对象翻译成下面的对象？

{
    "title": "aa", 
    "desc": ["i", "j", "k"],
    "cnt_head": "bb",
    "cnt_main_num1_time1": "mm",
    "cnt_main_num1_time2": "kk",
    "cnt_main_num2": "dd"
}

我尝试使用 for(i in obj) {....} 但失败了！

请帮忙！

Answer 1

您基本上是在询问如何使用表示嵌套路径的键来展平嵌套对象。这里有一个小的递归函数可以做到这一点：

const flatten = (o, pre) => Object.entries(o).reduce((a, [k, v]) => (
  key = pre ? `${pre}_${k}`: k,
  {
    ...a,
    ...Object.getPrototypeOf(v) !== Object.prototype ? {[key]: v} : flatten(v, key)
  }), {});

完整片段：

const o = {
    "title": "aa",
    "desc": ["i", "j", "k"],
    "cnt": {
        "head": "bb",
        "main": {
            "num1": {
                "time1": "mm",
                "time2": "kk"
            },
            "num2": "dd"
        }
    }
};

const flatten = (o, pre) => Object.entries(o).reduce((a, [k, v]) => (
  key = pre ? `${pre}_${k}`: k,
  {
    ...a,
    ...Object.getPrototypeOf(v) !== Object.prototype ? {[key]: v} : flatten(v, key)
  }), {});

console.log(flatten(o));

js object flatten：深度循环Json个objects，然后把objects flatten？

js object flatten：Deep loop Json objects， then flatten the objects?

javascript

json

object

flatten