Pygame，我的圆圈在我将它存储在一个变量后变成了一个矩形，我该如何防止这种情况发生

Question

我需要将一个 Circle 存储在一个变量中，但是在我完成之后它变成了一个 rect

circle_1 = pygame.draw.circle(screen, (0, 0, 0), (300, 300), 30)
Print(circle_1)

打印returns

<rect(270, 270, 60, 60)>

但我无法使用它。我的圈子是预定义的，但它不会在 canvas 上显示，这是问题的示例

> import pygame, sys
> 
> 
> pygame.init() screen = pygame.display.set_mode((600, 600)) 
> predefined_circle = pygame.draw.circle(screen,(0, 0, 0),(300, 300), 30)
> 
> def update():
>     screen.fill((200, 0, 0))
>     while 1:
>         for event in pygame.event.get():
>             if event.type == pygame.QUIT: sys.exit()
>         # It shows my circle if I dirctly tip pygame.draw.circle(screen,(0, 0, 0),(300, 300), 30) into it
>         predefined_circle
>         pygame.display.update()
> 
> update()

为了让您更好地了解我正在努力实现的目标，这是我正在做的代码，但没有必要阅读，因为我已经尽力解释了它以上。请注意注释应该解释它下面的代码块所做的一切。

# Creating the canvas which can paint any wanted Object from another class
class Canvas:
# Initialising the screen and setting all needed variables
def __init__(self, painting):
    pygame.init()
    self.screen_size = (600, 600)
    self.background = (25, 255, 255)
    self.screen = pygame.display.set_mode(self.screen_size)
    self.paint = painting

# Let the user set the name of the canvas
def set_screen_name(self):
    return self.screen

# Draw the everything you want to
def update(self):
    # Paint the canvas
    self.screen.fill(self.background)
    # Make the game be quittable
    while 1:
        for event in pygame.event.get():
            if event.type == pygame.QUIT: sys.exit()

        # Draw the defined Circle and then update the Canvas
        # it only draws a circle if directly tip pygame.draw.circle(surface, color, position, radius)

        self.paint
        pygame.display.update()


# Draw any circle you like
class Cir:
# Get all the required Information's to Draw a circle
def __init__(self, canvas, what_color, position, radius, line=0):
    self.can = canvas
    self.color = what_color
    self.pos = position
    self.r = radius
    self.line = line
    self.cir = None

# Create the circle with the acquired Information's
def create(self):
    self.cir = pygame.draw.circle(self.can, self.color, self.pos, self.r, self.line)
    return self.cir


# So far there is no Surface for the Cir class
# And there is no Object that cloud be painted for the Canvas class
# I initialise a canvas instance without anything that needs to be painted
get_surface = Canvas(None)

# Now I can access set_screen_name from the Canvas class and give the surface a name
# Which the Cir class can now use as a surface
screen = get_surface.set_screen_name()

c1 = pygame.draw.circle(screen, (0,0,0), (300, 300), 30)
print(c1)

# I'm initialising a circle
init_circle = Cir(screen, (0, 255, 0), (300, 300), 30)

# Create the initialised circle
circle_1 = init_circle.create()

# Give the Canvas class the created circle
paint = Canvas(circle_1)

# Draw the circle
paint.update()

Answer 1

My circle turns to a rect.

实际上，不，不是。根据那些绘图函数的documentation，调用的目的是立即绘制东西，不是给你一个对象你可以稍后再画：

Draw several simple shapes to a Surface.

根据对您问题的分析，您似乎认为您正在存储画圆的行为，以便稍后完成。事实并非如此。相反，您所做的实际上是绘制圆并保存该绘制操作的结果 - 稍后评估结果将不会实际绘制或重绘圆。

那么，如果 draw 函数没有返回一些东西供以后绘制，那么是它返回的是什么？也可以在上述文档中找到：

The functions return a rectangle representing the bounding area of changed pixels.

换句话说，它告诉您绘图操作改变的最小矩形 - 这将是一个边长与直径相同且以同一点为中心的正方形。

显然，PyGame 的作者认为这些信息可能对某些目的有用，而不是重画圆的目的:-)

实现您想要实现的目标的一种方法是简单地使用函数来绘制 "predefined" 圆并调用它，而不是尝试求值从上次调用返回的矩形。

Pygame，我的圆圈在我将它存储在一个变量后变成了一个矩形，我该如何防止这种情况发生

Pygame, my circle turns to a rect after I stored it in a variable, how do I prevent that from happening

pygame

data-conversion