如何将 lambda 表达式编译成动态创建的 class
How to compile a lambda expression into a dynamically created class
我正在尝试使用反射发射创建 class 的扩展。
它有点管用。
var extendwith = new List<Type>();
extendwith.Add(typeof(object));
var t = Utils.DynamicInherit<BaseTest>("Extended",typeof(UtilsTest).GetMethod(nameof(Testing)), extendwith);
var instance = Activator.CreateInstance(t, new TestClass(), new { A=1 });
public class BaseTest
{
public readonly TestClass testClass;
public object IsNotNull;
public BaseTest(TestClass testClass)
{
this.testClass = testClass;
}
}
public static void Testing(BaseTest baseTest, List<object> objects)
{
foreach(var t in objects)
{
baseTest.IsNotNull = t;
}
}
这里发生的事情是,从 DynamicInherit 方法返回的类型 (t) 现在将从 BaseTest class 继承并具有包含 2 个参数(TestClass、Object)的构造函数
静态方法 Testing 将在 "constructed type" 的构造函数中调用。
使用此 IL 代码调用它。
constructorBuilder.Emit(OpCodes.Ldarg_0); //The this a referance to the created base class
constructorBuilder.Emit(OpCodes.Ldloc_0); //Reference to a List<Objects> that is passed in thorugh the constructor
constructorBuilder.Emit(OpCodes.Call, constructor); //The function to be called.. in this case the "public static void Testing(BaseTest baseTest, List<object> objects)"
这是可行的 "as expected",但我想将其更改为使用 lamda 表达式而不是静态函数。
var t = Utils.DynamicInherit<BaseTest>("Extended",(baseO, objects) => {foreach(var t in objects)
{
baseTest.IsNotNull = t;
}} ,
extendwith);
我知道我必须换行
constructorBuilder.Emit(OpCodes.Call, constructor);
但我不知道如何....
有什么建议吗???
给出
Action<BaseText,List<object>> f = (BaseTest baseO, List<object> objects) => {
foreach(var t in objects) {
baseTest.IsNotNull = t;
}
};
那么f.Method
应该就是你需要的我想:
var t = Utils.DynamicInherit<BaseTest>("Extended",f.Method, extendwith);
或者,您可以将它们全部组合起来:
var t = Utils.DynamicInherit<BaseTest>("Extended",((Action<BaseTest,List<object>>)((baseO, objects) => {foreach(var t in objects)
{
baseTest.IsNotNull = t;
}})).Method,
extendwith);
使用实用程序 class 我已经使它更容易阅读:
public static class To {
public static Func<TResult> Func<TResult>(Func<TResult> func) => func;
public static Func<T, TResult> Func<T, TResult>(Func<T, TResult> func) => func;
public static Func<T1, T2, TResult> Func<T1, T2, TResult>(Func<T1, T2, TResult> func) => func;
public static Func<T1, T2, T3, TResult> Func<T1, T2, T3, TResult>(Func<T1, T2, T3, TResult> func) => func;
public static Func<T1, T2, T3, T4, TResult> Func<T1, T2, T3, T4, TResult>(Func<T1, T2, T3, T4, TResult> func) => func;
public static Func<T1, T2, T3, T4, T5, TResult> Func<T1, T2, T3, T4, T5, TResult>(Func<T1, T2, T3, T4, T5, TResult> func) => func;
public static Func<T1, T2, T3, T4, T5, T6, TResult> Func<T1, T2, T3, T4, T5, T6, TResult>(Func<T1, T2, T3, T4, T5, T6, TResult> func) => func;
public static Func<T1, T2, T3, T4, T5, T6, T7, TResult> Func<T1, T2, T3, T4, T5, T6, T7, TResult>(Func<T1, T2, T3, T4, T5, T6, T7, TResult> func) => func;
public static Func<T1, T2, T3, T4, T5, T6, T7, T8, TResult> Func<T1, T2, T3, T4, T5, T6, T7, T8, TResult>(Func<T1, T2, T3, T4, T5, T6, T7, T8, TResult> func) => func;
public static Action<T> Action<T>(Action<T> act) => act;
public static Action<T1, T2> Action<T1, T2>(Action<T1, T2> act) => act;
public static Action<T1, T2, T3> Action<T1, T2, T3>(Action<T1, T2, T3> act) => act;
public static Action<T1, T2, T3, T4> Action<T1, T2, T3, T4>(Action<T1, T2, T3, T4> act) => act;
public static Action<T1, T2, T3, T4, T5> Action<T1, T2, T3, T4, T5>(Action<T1, T2, T3, T4, T5> act) => act;
public static Action<T1, T2, T3, T4, T5, T6> Action<T1, T2, T3, T4, T5, T6>(Action<T1, T2, T3, T4, T5, T6> act) => act;
public static Action<T1, T2, T3, T4, T5, T6, T7> Action<T1, T2, T3, T4, T5, T6, T7>(Action<T1, T2, T3, T4, T5, T6, T7> act) => act;
public static Action<T1, T2, T3, T4, T5, T6, T7, T8> Action<T1, T2, T3, T4, T5, T6, T7, T8>(Action<T1, T2, T3, T4, T5, T6, T7, T8> act) => act;
}
那么你只有:
var t = Utils.DynamicInherit<BaseTest>("Extended", To.Action((baseO, objects) => {
foreach(var t in objects) {
baseTest.IsNotNull = t;
}}).Method,
extendwith);
我正在尝试使用反射发射创建 class 的扩展。
它有点管用。
var extendwith = new List<Type>();
extendwith.Add(typeof(object));
var t = Utils.DynamicInherit<BaseTest>("Extended",typeof(UtilsTest).GetMethod(nameof(Testing)), extendwith);
var instance = Activator.CreateInstance(t, new TestClass(), new { A=1 });
public class BaseTest
{
public readonly TestClass testClass;
public object IsNotNull;
public BaseTest(TestClass testClass)
{
this.testClass = testClass;
}
}
public static void Testing(BaseTest baseTest, List<object> objects)
{
foreach(var t in objects)
{
baseTest.IsNotNull = t;
}
}
这里发生的事情是,从 DynamicInherit 方法返回的类型 (t) 现在将从 BaseTest class 继承并具有包含 2 个参数(TestClass、Object)的构造函数
静态方法 Testing 将在 "constructed type" 的构造函数中调用。 使用此 IL 代码调用它。
constructorBuilder.Emit(OpCodes.Ldarg_0); //The this a referance to the created base class
constructorBuilder.Emit(OpCodes.Ldloc_0); //Reference to a List<Objects> that is passed in thorugh the constructor
constructorBuilder.Emit(OpCodes.Call, constructor); //The function to be called.. in this case the "public static void Testing(BaseTest baseTest, List<object> objects)"
这是可行的 "as expected",但我想将其更改为使用 lamda 表达式而不是静态函数。
var t = Utils.DynamicInherit<BaseTest>("Extended",(baseO, objects) => {foreach(var t in objects)
{
baseTest.IsNotNull = t;
}} ,
extendwith);
我知道我必须换行
constructorBuilder.Emit(OpCodes.Call, constructor);
但我不知道如何.... 有什么建议吗???
给出
Action<BaseText,List<object>> f = (BaseTest baseO, List<object> objects) => {
foreach(var t in objects) {
baseTest.IsNotNull = t;
}
};
那么f.Method
应该就是你需要的我想:
var t = Utils.DynamicInherit<BaseTest>("Extended",f.Method, extendwith);
或者,您可以将它们全部组合起来:
var t = Utils.DynamicInherit<BaseTest>("Extended",((Action<BaseTest,List<object>>)((baseO, objects) => {foreach(var t in objects)
{
baseTest.IsNotNull = t;
}})).Method,
extendwith);
使用实用程序 class 我已经使它更容易阅读:
public static class To {
public static Func<TResult> Func<TResult>(Func<TResult> func) => func;
public static Func<T, TResult> Func<T, TResult>(Func<T, TResult> func) => func;
public static Func<T1, T2, TResult> Func<T1, T2, TResult>(Func<T1, T2, TResult> func) => func;
public static Func<T1, T2, T3, TResult> Func<T1, T2, T3, TResult>(Func<T1, T2, T3, TResult> func) => func;
public static Func<T1, T2, T3, T4, TResult> Func<T1, T2, T3, T4, TResult>(Func<T1, T2, T3, T4, TResult> func) => func;
public static Func<T1, T2, T3, T4, T5, TResult> Func<T1, T2, T3, T4, T5, TResult>(Func<T1, T2, T3, T4, T5, TResult> func) => func;
public static Func<T1, T2, T3, T4, T5, T6, TResult> Func<T1, T2, T3, T4, T5, T6, TResult>(Func<T1, T2, T3, T4, T5, T6, TResult> func) => func;
public static Func<T1, T2, T3, T4, T5, T6, T7, TResult> Func<T1, T2, T3, T4, T5, T6, T7, TResult>(Func<T1, T2, T3, T4, T5, T6, T7, TResult> func) => func;
public static Func<T1, T2, T3, T4, T5, T6, T7, T8, TResult> Func<T1, T2, T3, T4, T5, T6, T7, T8, TResult>(Func<T1, T2, T3, T4, T5, T6, T7, T8, TResult> func) => func;
public static Action<T> Action<T>(Action<T> act) => act;
public static Action<T1, T2> Action<T1, T2>(Action<T1, T2> act) => act;
public static Action<T1, T2, T3> Action<T1, T2, T3>(Action<T1, T2, T3> act) => act;
public static Action<T1, T2, T3, T4> Action<T1, T2, T3, T4>(Action<T1, T2, T3, T4> act) => act;
public static Action<T1, T2, T3, T4, T5> Action<T1, T2, T3, T4, T5>(Action<T1, T2, T3, T4, T5> act) => act;
public static Action<T1, T2, T3, T4, T5, T6> Action<T1, T2, T3, T4, T5, T6>(Action<T1, T2, T3, T4, T5, T6> act) => act;
public static Action<T1, T2, T3, T4, T5, T6, T7> Action<T1, T2, T3, T4, T5, T6, T7>(Action<T1, T2, T3, T4, T5, T6, T7> act) => act;
public static Action<T1, T2, T3, T4, T5, T6, T7, T8> Action<T1, T2, T3, T4, T5, T6, T7, T8>(Action<T1, T2, T3, T4, T5, T6, T7, T8> act) => act;
}
那么你只有:
var t = Utils.DynamicInherit<BaseTest>("Extended", To.Action((baseO, objects) => {
foreach(var t in objects) {
baseTest.IsNotNull = t;
}}).Method,
extendwith);