检测鼠标真实方向

Question

我的目标是在 mouseup 事件触发之前检测最后一次鼠标移动的方向。

为了避免验证小的不自主移动（例如：我用鼠标向右移动 100px 然后我停止但不由自主地向左移动 2px）我只会在鼠标指针达到最小值后确认方向与最后一个反转点的安全距离（间隙）。

这里是我的实现的简化：

var direction = "",
oldx = 0,
invert = 0,
gap = 10,
move = "",
mousemovemethod = function (e) {

    if (e.pageX < oldx) {
        if(direction == "right") invert = e.pageX;
        direction = "left";
        if(e.pageX < invert - gap) move = "left";
    } else if (e.pageX > oldx) {
        if(direction == "left") invert = e.pageX;
        direction = "right"
        if(e.pageX > invert + gap) move = "right";
    }

    document.body.innerHTML = "moving " + direction + ", last inversion point: " + invert + ", Validated movement: " + move;

    oldx = e.pageX;

}

document.addEventListener('mousemove', mousemovemethod);

这里是 fiddle

该代码有效，但在我看来它冗长且不清楚。我一直不擅长这种实现，我想知道是否有人知道处理这种机制的更优雅的方法。

欢迎大家提出建议。

Answer 1

function smooth(){
    var direction="",
    oldx = 0,
    noise=10,
    dir=0;
    mousemove=function(e){
       dir=oldx-e.pageX;
       if(Math.abs(dir)> noise){
          (dir <=0 )?direction="right":direction="left";
          oldx=e.pageX;
       }
       document.body.innerHTML = "moving " + direction;
   };
   document.addEventListener('mousemove', mousemove);
}

这个怎么样？

检测鼠标真实方向

Detect mouse real direction

javascript

mouseevent

mouse

mousemove