如何在 Java 中将 HMAC 密钥指定为十六进制
How to specify HMAC key as hexadecimal in Java
我能够使用以下代码成功获得 HMAC SHA256:
public static String getHac(String dataUno, String keyUno) throws InvalidKeyException, NoSuchAlgorithmException, UnsupportedEncodingException {
SecretKey secretKey = null;
Mac mac = Mac.getInstance("HMACSHA256");
byte[] keyBytes = keyUno.getBytes("UTF-8");
secretKey = new SecretKeySpec(keyBytes,mac.getAlgorithm());
mac.init(secretKey);
byte[] text = dataUno.getBytes("UTF-8");
System.out.println("Hex encode: " + Hex.encode(keyUno.getBytes()));
byte[] encodedText = mac.doFinal(text);
return new String(Base64.encode(encodedText)).trim();
}
产生:
HMAC: 9rH0svSCPHdbc6qUhco+nlkt2O7HE0rThV4M9Hbv5aY=
不过,我想得到这个:
HMAC:eVXBY4RZmFQcOHHZ5FMRjDLOJ8vCuVGTjy7cHN7pqfo=
我尝试了 online tool,我的代码和在线工具之间的区别似乎是我使用的是密钥类型的文本。
测试值:
字符串数据 = "5515071604000fAIkwJtkeiA:APA91bH_Pb5xB2lrmKWUst5xRuJ3joVE-sb9KoT0zXZuupIEfdHjii-cODj-JMnjyy7hFJUbIRAre9o2yaCU43KaFDmxKlhJhE36Dw0bZ2VntDUn_Zd1EJBuSyCYiUtmmkHfRvRy3hIb";
字符串键 = "fc67bb2ee0648a72317dcc42f232fc24f3964a9ebac0dfab6cf47521e121dc6e";
getHac("5515071604000fAIkwJtkeiA:APA91bH_Pb5xB2lrmKWUst5xRuJ3joVE-sb9KoT0zXZuupIEfdHjii-cODj-JMnjyy7hFJUbIRAre9o2yaCU43KaFDmxKlhJhE36Dw0bZ2VntDUn_Zd1EJBuSyCYiUtmmkHfRvRy3hIb", "fc67bb2ee0648a72317dcc42f232fc24f3964a9ebac0dfab6cf47521e121dc6e"));
我的方法的执行return
9rH0svSCPHdbc6qUhco+nlkt2O7HE0rThV4M9Hbv5aY=
(在线return与所选键类型文本相同的值)
我预计
eVXBY4RZmFQcOHHZ5FMRjDLOJ8vCuVGTjy7cHN7pqfo=
(在线returns 相同的值,选择的键类型十六进制)
假设您使用的是 Apache Commons Codec 1.11,请使用以下内容:
byte[] keyBytes = Hex.decodeHex(keyUno);
getHac 方法
您的代码稍作修改后如下所示:
public static String getHac(String dataUno, String keyUno)
throws InvalidKeyException, NoSuchAlgorithmException, UnsupportedEncodingException, DecoderException {
SecretKey secretKey;
Mac mac = Mac.getInstance("HMACSHA256");
byte[] keyBytes = Hex.decodeHex(keyUno);
secretKey = new SecretKeySpec(keyBytes, mac.getAlgorithm());
mac.init(secretKey);
byte[] text = dataUno.getBytes("UTF-8");
byte[] encodedText = mac.doFinal(text);
return new String(Base64.encodeBase64(encodedText)).trim();
}
测试
这个Java方法给出了预期的结果:
eVXBY4RZmFQcOHHZ5FMRjDLOJ8vCuVGTjy7cHN7pqfo=
我能够使用以下代码成功获得 HMAC SHA256:
public static String getHac(String dataUno, String keyUno) throws InvalidKeyException, NoSuchAlgorithmException, UnsupportedEncodingException {
SecretKey secretKey = null;
Mac mac = Mac.getInstance("HMACSHA256");
byte[] keyBytes = keyUno.getBytes("UTF-8");
secretKey = new SecretKeySpec(keyBytes,mac.getAlgorithm());
mac.init(secretKey);
byte[] text = dataUno.getBytes("UTF-8");
System.out.println("Hex encode: " + Hex.encode(keyUno.getBytes()));
byte[] encodedText = mac.doFinal(text);
return new String(Base64.encode(encodedText)).trim();
}
产生:
HMAC: 9rH0svSCPHdbc6qUhco+nlkt2O7HE0rThV4M9Hbv5aY=
不过,我想得到这个:
HMAC:eVXBY4RZmFQcOHHZ5FMRjDLOJ8vCuVGTjy7cHN7pqfo=
我尝试了 online tool,我的代码和在线工具之间的区别似乎是我使用的是密钥类型的文本。
测试值:
字符串数据 = "5515071604000fAIkwJtkeiA:APA91bH_Pb5xB2lrmKWUst5xRuJ3joVE-sb9KoT0zXZuupIEfdHjii-cODj-JMnjyy7hFJUbIRAre9o2yaCU43KaFDmxKlhJhE36Dw0bZ2VntDUn_Zd1EJBuSyCYiUtmmkHfRvRy3hIb";
字符串键 = "fc67bb2ee0648a72317dcc42f232fc24f3964a9ebac0dfab6cf47521e121dc6e";
getHac("5515071604000fAIkwJtkeiA:APA91bH_Pb5xB2lrmKWUst5xRuJ3joVE-sb9KoT0zXZuupIEfdHjii-cODj-JMnjyy7hFJUbIRAre9o2yaCU43KaFDmxKlhJhE36Dw0bZ2VntDUn_Zd1EJBuSyCYiUtmmkHfRvRy3hIb", "fc67bb2ee0648a72317dcc42f232fc24f3964a9ebac0dfab6cf47521e121dc6e"));
我的方法的执行return
9rH0svSCPHdbc6qUhco+nlkt2O7HE0rThV4M9Hbv5aY= (在线return与所选键类型文本相同的值)
我预计
eVXBY4RZmFQcOHHZ5FMRjDLOJ8vCuVGTjy7cHN7pqfo= (在线returns 相同的值,选择的键类型十六进制)
假设您使用的是 Apache Commons Codec 1.11,请使用以下内容:
byte[] keyBytes = Hex.decodeHex(keyUno);
getHac 方法
您的代码稍作修改后如下所示:
public static String getHac(String dataUno, String keyUno)
throws InvalidKeyException, NoSuchAlgorithmException, UnsupportedEncodingException, DecoderException {
SecretKey secretKey;
Mac mac = Mac.getInstance("HMACSHA256");
byte[] keyBytes = Hex.decodeHex(keyUno);
secretKey = new SecretKeySpec(keyBytes, mac.getAlgorithm());
mac.init(secretKey);
byte[] text = dataUno.getBytes("UTF-8");
byte[] encodedText = mac.doFinal(text);
return new String(Base64.encodeBase64(encodedText)).trim();
}
测试
这个Java方法给出了预期的结果:
eVXBY4RZmFQcOHHZ5FMRjDLOJ8vCuVGTjy7cHN7pqfo=