反转数据库中的最后两个数据

Question

我想反转下面查询显示的数据。 datetime_logged ASC 从 table 中获取前两个数据，而 datetime_logged DESC 获取后两个数据。就像现在一样，它打印了最后两个数据，但我想反转这些。

示例： data_temperature 数据 9.8 排在数据 10.3 之前。我想扭转这一点，所以 10.3 领先于 9.8。

SELECT data_temperature, data_address_seo, datetime_logged
FROM weather
WHERE data_address_seo = 'street-28-postal-code-city-country'
ORDER BY datetime_logged DESC
LIMIT 2

我怎样才能做到这一点？

Answer 1

使用子查询：

SELECT t.*
FROM (SELECT data_temperature, data_address_seo, datetime_logged
      FROM weather
      WHERE data_address_seo = 'street-28-postal-code-city-country'
      ORDER BY datetime_logged DESC
      LIMIT 2
     ) t
ORDER BY datetime_logged;

反转数据库中的最后两个数据

Reverse the two last data from the database

sql

reverse