如何遍历包含地图的 ArrayList?
How to loop over an ArrayList which contains a map?
目前我正在使用 rest-assured 来访问端点,然后通过 ArrayList 和 HashMap 存储任何 JSON 数据匹配。
我可以看到我收到了回复,但是当 ArrayList 包含内部 HashMap 时,我该如何循环它?
正如您从下面的 JSON 数据中看到的那样,我希望输出存储在 ArrayList 中的所有值/匹配项。
我的代码:
public void apiTest() {
String position = "Attacker";
String role = "PLAYER";
Response response = given()
.spec(footballCompetitions_requestSpecification)
.when().get(EndPoint.TEAMS + EndPoint.SQUAD);
ArrayList<Map<String, ?>> allPlayers = response.path
("squad.findAll { it.role == '%s' }.findAll { it.position == '%s' }", position, role);
示例JSON数据:
{
"id": 66,
"area": {
"id": 2072,
"name": "England"
},
"activeCompetitions": [
{
"id": 2021,
"area": {
"id": 2072,
"name": "England"
},
"name": "Premier League",
"code": "PL",
"plan": "TIER_ONE",
"lastUpdated": "2019-01-03T23:39:45Z"
},
{
"id": 2001,
"area": {
"id": 2077,
"name": "Europe"
},
"name": "UEFA Champions League",
"code": "CL",
"plan": "TIER_ONE",
"lastUpdated": "2018-12-13T18:55:02Z"
}
],
"name": "Manchester United FC",
"shortName": "Man United",
"tla": "MNU",
"crestUrl": "http://upload.wikimedia.org/wikipedia/de/d/da/Manchester_United_FC.svg",
"address": "Sir Matt Busby Way Manchester M16 0RA",
"phone": "+44 (0161) 8688000",
"website": "http://www.manutd.com",
"email": "enquiries@manutd.co.uk",
"founded": 1878,
"clubColors": "Red / White",
"venue": "Old Trafford",
"squad": [
{
"id": 3188,
"name": "David De Gea",
"position": "Goalkeeper",
"dateOfBirth": "1990-11-07T00:00:00Z",
"countryOfBirth": "Spain",
"nationality": "Spain",
"shirtNumber": 1,
"role": "PLAYER"
},
{
"id": 3331,
"name": "Marcus Rashford",
"position": "Attacker",
"dateOfBirth": "1997-10-31T00:00:00Z",
"countryOfBirth": "England",
"nationality": "England",
"shirtNumber": 10,
"role": "PLAYER"
},
{
"id": 3372,
"name": "Anthony Martial",
"position": "Attacker",
"dateOfBirth": "1995-12-05T00:00:00Z",
"countryOfBirth": "France",
"nationality": "France",
"shirtNumber": 11,
"role": "PLAYER"
},
{
"id": 3662,
"name": "Romelu Lukaku",
"position": "Attacker",
"dateOfBirth": "1993-05-13T00:00:00Z",
"countryOfBirth": "Belgium",
"nationality": "Belgium",
"shirtNumber": 9,
"role": "PLAYER"
},
首先遍历列表,然后遍历地图:
for (Map<String, ?> map : allPlayers) {
for (String key : map.keySet()) {
Object player = map.get(key);
// ...
}
}
如果您使用的是 Java 8 或更高版本,则只需先遍历 List
,然后使用 lambda 表达式在嵌套迭代中遍历 Map
:
public static void main(String[] args) {
List<Map<String, ?>> jsonList = new ArrayList<>();
Map<String, String> mapOne = new HashMap<String, String>();
mapOne.put("id", String.valueOf(66));
mapOne.put("area", "Some Area");
jsonList.add(mapOne);
jsonList.forEach(map -> {
map.forEach((key, value) -> {
System.out.println(key + ": " + value);
});
});
}
您需要注意的是 value
的 String
表示,因为它在您的代码中是 Map<String, ?>
而在我的示例中是 Map<String, String>
,直接用上面例子的System.out.println(key + ": " + value);
.
可能会出什么问题
目前我正在使用 rest-assured 来访问端点,然后通过 ArrayList 和 HashMap 存储任何 JSON 数据匹配。
我可以看到我收到了回复,但是当 ArrayList 包含内部 HashMap 时,我该如何循环它?
正如您从下面的 JSON 数据中看到的那样,我希望输出存储在 ArrayList 中的所有值/匹配项。
我的代码:
public void apiTest() {
String position = "Attacker";
String role = "PLAYER";
Response response = given()
.spec(footballCompetitions_requestSpecification)
.when().get(EndPoint.TEAMS + EndPoint.SQUAD);
ArrayList<Map<String, ?>> allPlayers = response.path
("squad.findAll { it.role == '%s' }.findAll { it.position == '%s' }", position, role);
示例JSON数据:
{
"id": 66,
"area": {
"id": 2072,
"name": "England"
},
"activeCompetitions": [
{
"id": 2021,
"area": {
"id": 2072,
"name": "England"
},
"name": "Premier League",
"code": "PL",
"plan": "TIER_ONE",
"lastUpdated": "2019-01-03T23:39:45Z"
},
{
"id": 2001,
"area": {
"id": 2077,
"name": "Europe"
},
"name": "UEFA Champions League",
"code": "CL",
"plan": "TIER_ONE",
"lastUpdated": "2018-12-13T18:55:02Z"
}
],
"name": "Manchester United FC",
"shortName": "Man United",
"tla": "MNU",
"crestUrl": "http://upload.wikimedia.org/wikipedia/de/d/da/Manchester_United_FC.svg",
"address": "Sir Matt Busby Way Manchester M16 0RA",
"phone": "+44 (0161) 8688000",
"website": "http://www.manutd.com",
"email": "enquiries@manutd.co.uk",
"founded": 1878,
"clubColors": "Red / White",
"venue": "Old Trafford",
"squad": [
{
"id": 3188,
"name": "David De Gea",
"position": "Goalkeeper",
"dateOfBirth": "1990-11-07T00:00:00Z",
"countryOfBirth": "Spain",
"nationality": "Spain",
"shirtNumber": 1,
"role": "PLAYER"
},
{
"id": 3331,
"name": "Marcus Rashford",
"position": "Attacker",
"dateOfBirth": "1997-10-31T00:00:00Z",
"countryOfBirth": "England",
"nationality": "England",
"shirtNumber": 10,
"role": "PLAYER"
},
{
"id": 3372,
"name": "Anthony Martial",
"position": "Attacker",
"dateOfBirth": "1995-12-05T00:00:00Z",
"countryOfBirth": "France",
"nationality": "France",
"shirtNumber": 11,
"role": "PLAYER"
},
{
"id": 3662,
"name": "Romelu Lukaku",
"position": "Attacker",
"dateOfBirth": "1993-05-13T00:00:00Z",
"countryOfBirth": "Belgium",
"nationality": "Belgium",
"shirtNumber": 9,
"role": "PLAYER"
},
首先遍历列表,然后遍历地图:
for (Map<String, ?> map : allPlayers) {
for (String key : map.keySet()) {
Object player = map.get(key);
// ...
}
}
如果您使用的是 Java 8 或更高版本,则只需先遍历 List
,然后使用 lambda 表达式在嵌套迭代中遍历 Map
:
public static void main(String[] args) {
List<Map<String, ?>> jsonList = new ArrayList<>();
Map<String, String> mapOne = new HashMap<String, String>();
mapOne.put("id", String.valueOf(66));
mapOne.put("area", "Some Area");
jsonList.add(mapOne);
jsonList.forEach(map -> {
map.forEach((key, value) -> {
System.out.println(key + ": " + value);
});
});
}
您需要注意的是 value
的 String
表示,因为它在您的代码中是 Map<String, ?>
而在我的示例中是 Map<String, String>
,直接用上面例子的System.out.println(key + ": " + value);
.