如何在python中使用切片运算符提取中间部分以外的字母？

Question

我试图理解以下示例的所有可能性。

  +---+---+---+---+---+---+---+---+---+
  | C | O | M | P | U | T | E | R | S |
  +---+---+---+---+---+---+---+---+---+
  0   1   2   3   4   5   6   7   8   9   
 -9  -8  -7  -6  -5  -4  -3  -2  -1 

  COMPUTERS[ 4 : 7 ]     =  UTE
  COMPUTERS[ 2 : 5 : 2 ] =  MU
  COMPUTERS[-5 : 1 :-1 ] =  UPM
  COMPUTERS[ 4 ]         =  U
  COMPUTERS[-4 :-6 :-1 ] =  TU
  COMPUTERS[ 2 :-3 : 1 ] =  MPUT
  COMPUTERS[ 2 :-3 :-1 ] =  
  COMPUTERS[   :   :-1 ] =  SRETUPMOC
  COMPUTERS[-5 :   ]     =  UTERS
  COMPUTERS[-5 : 0 :-1 ] =  UPMO
  COMPUTERS[-5 :   :-1 ] =  UPMOC
  COMPUTERS[-1 : 1 :-2 ] =  SEUM

但是我没搞懂除中间三个以外的字母怎么取

EXPECTED OUTPUT
Ex:
COMPUTERS =  COMERS (only first three and last three not the middle three letters (PUT))

谁能告诉我如何从头到尾取字母（:3 和 6:)

Answer 1

那不是一片，那是两片：

word[:3] + word[-3:]

Answer 2

您可以将副本复制到列表中，删除中间部分，然后再转换回来：

>>> computers = list('COMPUTERS')
>>> del computers[3:-3]
>>> ''.join(computers)
COMERS

Answer 3

如果你想删除字符串的中间部分你必须使用两个切片:

>>> string="COMPUTERS"
>>> string[:len(string)//3]+string[-len(string)//3:]
'COMERS'

如何在python中使用切片运算符提取中间部分以外的字母？

How to extract letters except from middle part by using slice operator in python?

python

list

slice

python-2.7