sql - ORA-00937: 不是单组函数
sql - ORA-00937: not a single-group group function
select
location,
home_team_name,
count(case when extract(year from match_date)='2018' and extract(month from match_date)=1 then 1 end) january_2018,
count(case when extract(year from match_date)='2018' and extract(month from match_date)=2 then 1 end) february_2018,
count(case when extract(year from match_date)='2018' and extract(month from match_date)=3 then 1 end) march_2018,
count(case when extract(year from match_date)='2018' then 1 end) Total
from match_results
union all
select
'total' as location,
'total' as home_team_name,
count(case when extract(month from match_date)=1 then 1 end) january_2018,
count(case when extract(month from match_date)=2 then 1 end) february_2018,
count(case when extract(month from match_date)=3 then 1 end) march_2018,
count(case when extract(year from match_date)='2018' then 1 end) Total
from match_results
group by location,home_team_name;
错误信息:ORA-00937:不是单组函数。目前 运行 这个在 oracle live SQL.
关于如何解决这个问题有什么想法吗?
当运行聚合查询时,每个非聚合列都必须出现在GROUP BY
子句中。您有两个 UNION
ed 子查询:并且只有第一个具有非聚合列(即 location
和 home_team
),但是您碰巧将 GROUP BY
子句放在第二个,因为它似乎计算总数,可能不需要一个。您可以将 GROUP BY
子句放在第一个查询而不是第二个查询中:
select
location,
home_team_name,
count(case when extract(year from match_date)='2018' and extract(month from match_date)=1 then 1 end) january_2018,
count(case when extract(year from match_date)='2018' and extract(month from match_date)=2 then 1 end) february_2018,
count(case when extract(year from match_date)='2018' and extract(month from match_date)=3 then 1 end) march_2018,
count(case when extract(year from match_date)='2018' then 1 end) Total
from match_results
group by location,home_team_name
union all
select
'total' as location,
'total' as home_team_name,
count(case when extract(month from match_date)=1 then 1 end) january_2018,
count(case when extract(month from match_date)=2 then 1 end) february_2018,
count(case when extract(month from match_date)=3 then 1 end) march_2018,
count(case when extract(year from match_date)='2018' then 1 end) Total
from match_results
;
我推荐grouping sets
:
select coalesce(location, 'Total') as location,
coalesce(home_team_name, 'Total') as home_team_name,
sum(case when match_date >= date '2018-01-01' and
match_date < date '2018-02-01'
then 1 else 0
end) as january_2018,
sum(case when match_date >= date '2018-02-01' and
match_date < date '2018-03-01'
then 1 else 0
end) as february_2018,
sum(case when match_date >= date '2018-03-01' and
match_date < date '2018-04-01'
then 1 else 0
end) as march_2018,
sum(case when match_date >= date '2018-01-01' and
match_date < date '2019-01-01'
then 1 else 0
end) as total_2018
from match_results
group by grouping sets ( (location, home_team_name), () );
即不需要重复查询。我还更改了日期比较以使用实际日期。我发现这比提取日期部分更具可读性和可维护性。
select
location,
home_team_name,
count(case when extract(year from match_date)='2018' and extract(month from match_date)=1 then 1 end) january_2018,
count(case when extract(year from match_date)='2018' and extract(month from match_date)=2 then 1 end) february_2018,
count(case when extract(year from match_date)='2018' and extract(month from match_date)=3 then 1 end) march_2018,
count(case when extract(year from match_date)='2018' then 1 end) Total
from match_results
union all
select
'total' as location,
'total' as home_team_name,
count(case when extract(month from match_date)=1 then 1 end) january_2018,
count(case when extract(month from match_date)=2 then 1 end) february_2018,
count(case when extract(month from match_date)=3 then 1 end) march_2018,
count(case when extract(year from match_date)='2018' then 1 end) Total
from match_results
group by location,home_team_name;
错误信息:ORA-00937:不是单组函数。目前 运行 这个在 oracle live SQL.
关于如何解决这个问题有什么想法吗?
当运行聚合查询时,每个非聚合列都必须出现在GROUP BY
子句中。您有两个 UNION
ed 子查询:并且只有第一个具有非聚合列(即 location
和 home_team
),但是您碰巧将 GROUP BY
子句放在第二个,因为它似乎计算总数,可能不需要一个。您可以将 GROUP BY
子句放在第一个查询而不是第二个查询中:
select
location,
home_team_name,
count(case when extract(year from match_date)='2018' and extract(month from match_date)=1 then 1 end) january_2018,
count(case when extract(year from match_date)='2018' and extract(month from match_date)=2 then 1 end) february_2018,
count(case when extract(year from match_date)='2018' and extract(month from match_date)=3 then 1 end) march_2018,
count(case when extract(year from match_date)='2018' then 1 end) Total
from match_results
group by location,home_team_name
union all
select
'total' as location,
'total' as home_team_name,
count(case when extract(month from match_date)=1 then 1 end) january_2018,
count(case when extract(month from match_date)=2 then 1 end) february_2018,
count(case when extract(month from match_date)=3 then 1 end) march_2018,
count(case when extract(year from match_date)='2018' then 1 end) Total
from match_results
;
我推荐grouping sets
:
select coalesce(location, 'Total') as location,
coalesce(home_team_name, 'Total') as home_team_name,
sum(case when match_date >= date '2018-01-01' and
match_date < date '2018-02-01'
then 1 else 0
end) as january_2018,
sum(case when match_date >= date '2018-02-01' and
match_date < date '2018-03-01'
then 1 else 0
end) as february_2018,
sum(case when match_date >= date '2018-03-01' and
match_date < date '2018-04-01'
then 1 else 0
end) as march_2018,
sum(case when match_date >= date '2018-01-01' and
match_date < date '2019-01-01'
then 1 else 0
end) as total_2018
from match_results
group by grouping sets ( (location, home_team_name), () );
即不需要重复查询。我还更改了日期比较以使用实际日期。我发现这比提取日期部分更具可读性和可维护性。