如何在 python 的循环中正确修复语法错误 'continue'

Question

I want to create a simple database, which will store and return data.

问题是 continue 似乎不起作用。一旦 function checker 中的 else statement 被执行，它就会继续打印 "try again" 并且似乎陷入僵局。

def checker(): 
#Checks if the password is strong enough
while True:
   if (p[0].isupper() and not p.isalpha() and len(p) > 7):
   print('Password Created!')
   break
#If password is not strong enough try again
else:
    print('Try Again')
    continue


#Starts main program
while True:
  database = {'dom':'yeet'}
  welcome = input('Welcome! To login press L, if you are new press R: ')
  #Login will log basically check if your info is in dictionary
  if welcome == 'L':
    for user in database.keys():
      u = input('Username: ')
      if u in user:
          for passw in database.values():
            p = input('Password: ')
            if p in passw:
               print('Welcome ' + str(u))
               break
  #Will create new user in dictionary
  elif welcome == 'R':
    u = input('Choose your username: ')
    p = input('Choose your password: ')

  #Runs checker function
    checker()

    database[u] = p
    print('Welcome ' + str(u))
    break
 else:
    continue

Answer 1

像这样重写 checker() ：您对 else 块使用了不正确的缩进，它超出了循环范围。

def checker(): 
    #Checks if the password is strong enough
    while True:
        if (p[0].isupper() and not p.isalpha() and len(p) > 7):
            print('Password Created!')
            break

        else:
            print('Try Again')
            continue

Answer 2

Python 编码的美妙之处在于您必须正确地缩进代码，牢记这一点，每个人都会自动编写漂亮的代码，并且您永远不会看到格式错误的 Python 代码。缩进你的其他部分，你很高兴。

如何在 python 的循环中正确修复语法错误 'continue'

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