在 Marshallow / SQLAlchemy Schema 上展平数据

Question

我在如何从端点之一取回数据方面遇到了一些问题 - 特别是 Marshmallow 和 SQLAlchemy。

我在鸡尾酒和配料之间有一个多对多的关系，但我也有比关系 table、ings_in_cocktail 上的外键更多的数据，例如 ounces. 当我得到 /cocktails/ 时，它 returns 是这样的：

{
  "cocktails": [
    {
      "glass": "rocks",
      "ingredients": [
        {
          "ingredient": {
            "ing_type": "liquor",
            "id": 1,
            "name": "gin"
          },
          "ounces": 20
        }
      ],
      "finish": "stirred",
      "id": 1,
      "name": "gin and tonic"
    }
  ]
}

我想做的是将 ounces 属性的传播与 ingredient 字典结合起来。

我希望数据如下所示：

{
  "cocktails": [
    {
      "glass": "rocks",
      "ingredients": [
        {
          "ing_type": "liquor",
          "id": 1,
          "name": "gin",
          "ounces": 20
        }
      ],
      "finish": "stirred",
      "id": 1,
      "name": "gin and tonic"
    }
  ]
}

在网上搜索了几个小时后，我找不到使用 Marshmallow 轻松完成此操作的方法。有没有我想念的简单方法？

代码

ingredients.py

from flask import Flask
from settings import db, ma

class Ingredient(db.Model):
    __tablename__ = 'ingredients'
    id = db.Column(db.Integer, primary_key=True)
    name = db.Column(db.String(80), nullable=False)
    ing_type = db.Column(db.String(20), nullable=False)

class IngredientSchema(ma.ModelSchema):
    class Meta:
        model = Ingredient

ings_in_cocktail.py

from flask import Flask
from settings import db, ma

from models.ingredients import Ingredient, IngredientSchema

class CocktailIngredient(db.Model):
    __tablename__ = 'ings_in_cocktail'
    ing_id = db.Column(db.Integer, db.ForeignKey('ingredients.id'), primary_key=True)
    cocktail_id = db.Column(db.Integer, db.ForeignKey('cocktails.id'), primary_key=True)
    ounces = db.Column(db.Integer, nullable=False)

    ingredient = db.relationship('Ingredient')

# Necessary for transforming sqlalchemy data into serialized JSON


class CocktailIngredientSchema(ma.ModelSchema):
    ingredient = ma.Nested(IngredientSchema, strict=True)

    class Meta:
    model = CocktailIngredient

cocktails.py

from flask import Flask
from settings import db, ma

from models.ing_in_cocktails import CocktailIngredient, CocktailIngredientSchema
from models.ingredients import Ingredient, IngredientSchema

class Cocktail(db.Model):
    __tablename__ = 'cocktails'
    id = db.Column(db.Integer, primary_key=True)
    name = db.Column(db.String(80), nullable=False)
    glass = db.Column(db.String(20), nullable=False)
    finish = db.Column(db.String(20), nullable=True)
    ingredients = db.relationship(
        'CocktailIngredient',
        # secondary='ings_in_cocktail',
        backref=db.backref('cocktails'),
        # primaryjoin=id == CocktailIngredient.cocktail_id
    )

# Necessary for transforming sqlalchemy data into serialized JSON
class CocktailSchema(ma.ModelSchema):
    # this is responsible for returning all the ingredient data on the cocktail
    ingredients = ma.Nested(CocktailIngredientSchema, many=True, strict=True)
    class Meta:
    model = Cocktail

Answer 1

您可以在 IngredientSchema

中使用方法字段

https://marshmallow.readthedocs.io/en/stable/custom_fields.html#method-fields

请检查此以了解如何在文档中使用此字段。

Answer 2

我最终是这样解决的：

class CocktailSchema(ma.ModelSchema):
    # this is responsible for returning all the ingredient data on the cocktail
    ingredients = ma.Nested(CocktailIngredientSchema, many=True, strict=True)
    ingredients = fields.Method('concat_ingredients_dicts')

    """
    at this point the ingredients field on the cocktail object looks something like this

    ingredients: [{
        ingredient: {
            name: 'white russian',
            glass: 'rocks',
            finish: 'stirred'
        },
        ounces: 2,
        action: 'muddle',
        step: 1
    }]

    what we want is to concat this data so "ingredients" just turns
    into an list of dicts
    """
    def concat_ingredients_dicts(self, obj):
        result_ingredients_list = []
        i = 0
        while i < len(list(obj.ingredients)):
            # create a dict from the fields that live in the relational table
            relational_fields_dict = {
                'ounces': obj.ingredients[i].ounces,
                'action': obj.ingredients[i].action,
                'step': obj.ingredients[i].step
            }

            # create a dict from the fields on each ingredient in the cocktail
            ingredients_dict = obj.ingredients[i].ingredient.__dict__
            ingredients_dict_extracted_values = {
                'name': ingredients_dict.get('name'),
                'type': ingredients_dict.get('ing_type'),
                'id': ingredients_dict.get('id')
            }

            # merge the two dicts together
            merged = dict()
            merged.update(ingredients_dict_extracted_values)
            merged.update(relational_fields_dict)

            # append this merged dict a result array
            result_ingredients_list.append(merged)
            i += 1
        # return the array of ingredients
        return result_ingredients_list

    class Meta:
      model = Cocktail

Answer 3

更新：我把更好的解决方案放在了底部。

您可以通过使用 Method 或 Function 字段允许父项从其子项获取数据来实现此目的。这是您需要做的：

别管 CocktailSchema。
完全摆脱 IngredientSchema（除非您还需要它做其他事情）。
在 CocktailIngredientSchema 中，用几个 Function 字段替换 Nested 字段，这些字段直接从内部 "ingredient" 对象中提取数据。

之前的模式

class IngredientSchema(ma.ModelSchema):
    class Meta:
        model = Ingredient


class CocktailIngredientSchema(ma.ModelSchema):
    ingredient = ma.Nested(IngredientSchema)

    class Meta:
        model = CocktailIngredient


class CocktailSchema(ma.ModelSchema):
    ingredients = ma.Nested(CocktailIngredientSchema, many=True)

    class Meta:
        model = Cocktail

之后的架构

class CocktailIngredientSchema(ma.ModelSchema):
    ing_type = ma.Function(lambda obj: obj.ingredient.ing_type)
    id = ma.Function(lambda obj: obj.ingredient.id)
    name = ma.Function(lambda obj: obj.ingredient.name)

    class Meta:
        model = CocktailIngredient


class CocktailSchema(ma.ModelSchema):
    ingredients = ma.Nested(CocktailIngredientSchema, many=True)

    class Meta:
        model = Cocktail

棉花糖版本 3+ 的更清洁替代品（需要 Python 3）

别管 CocktailSchema。
单独留下 IngredientSchema（而不是如上所示删除它）。
在 CocktailIngredientSchema 中，将 Nested 字段替换为几个直接从内部模式中提取数据的 Pluck 字段。

之后的架构

class IngredientSchema(ma.ModelSchema):
    class Meta:
        model = Ingredient


class CocktailIngredientSchema(ma.ModelSchema):
    ing_type = ma.Pluck(IngredientSchema, 'ing_type')
    id = ma.Pluck(IngredientSchema, 'id')
    name = ma.Pluck(IngredientSchema, 'name')

    class Meta:
        model = CocktailIngredient


class CocktailSchema(ma.ModelSchema):
    ingredients = ma.Nested(CocktailIngredientSchema, many=True)

    class Meta:
        model = Cocktail

在 Marshallow / SQLAlchemy Schema 上展平数据

Flatten data on Marshallow / SQLAlchemy Schema

python

flask

sqlalchemy

marshmallow

代码

棉花糖版本 3+ 的更清洁替代品（需要 Python 3）