合并两个 XDocument

Question

我有两个xml，我要合并一个特定的节点

这是第一个：

<ContactEmployees>
  <row>
    <Name>NAME</Name>
    <Position>Mag</Position>
    <Phone1>number</Phone1>
    <E_Mail>mail</E_Mail>
    <InternalCode>11</InternalCode>
    <Gender>gt_Undefined</Gender>
    <Active>tYES</Active>
    <FirstName>Tizio</FirstName>
    <BlockSendingMarketingContent>tNO</BlockSendingMarketingContent>
  </row>
</ContactEmployees>

这是第二个：

<ContactEmployees>
      <row>
        <CardCode>1000010</CardCode>
        <Name>NAME</Name>
        <Position>Mag</Position>
        <Phone1>number</Phone1>
        <E_Mail>mail</E_Mail>
        <InternalCode>11</InternalCode>
        <Gender>gt_Undefined</Gender>
        <Active>tYES</Active>
        <BlockSendingMarketingContent>tNO</BlockSendingMarketingContent>
      </row>
      <row>
        <CardCode>1000010</CardCode>
        <Name>Prova</Name>
        <InternalCode>2703</InternalCode>
        <PlaceOfBirth>-1</PlaceOfBirth>
        <Gender>gt_Undefined</Gender>
        <Active>tYES</Active>
        <FirstName>Prova</FirstName>
        <BlockSendingMarketingContent>tNO</BlockSendingMarketingContent>
      </row>
    </ContactEmployees>

这是我期望合并后的结果：

<ContactEmployees>
       <row>
        <Name>NAME</Name>
        <Position>Mag</Position>
        <Phone1>number</Phone1>
        <E_Mail>mail</E_Mail>
        <InternalCode>11</InternalCode>
        <Gender>gt_Undefined</Gender>
        <Active>tYES</Active>
        <FirstName>Tizio</FirstName>
        <BlockSendingMarketingContent>tNO</BlockSendingMarketingContent>
      </row>
      <row>
        <CardCode>1000010</CardCode>
        <Name>Prova</Name>
        <InternalCode>2703</InternalCode>
        <PlaceOfBirth>-1</PlaceOfBirth>
        <Gender>gt_Undefined</Gender>
        <Active>tYES</Active>
        <FirstName>Prova</FirstName>
        <BlockSendingMarketingContent>tNO</BlockSendingMarketingContent>
      </row>
    </ContactEmployees>

我努力做到IEnumerable<XElement> merge = xdoc.Root.Descendants("ContactEmployees").Concat("ContactEmployees")); xdoc 是我的所有 xml 文档，其中 "ContactEmployees" 节点是其中的一部分，但是 concat 方法生成一个具有三个节点的 xml 或将所有节点排队，我尝试了 union 但排除了第二个 xml 并且我不明白我该如何处理试图查看 InternalCode 属性的查询，因为我无法以任何方式修改它，所以它是唯一的？

-编辑- 我查看了一下情况，Internalcode可以不一样（都是一个数据库的数据），Name可以修改（Name,InternalCode,CardCode是我的table的key），所以其实我要合并修改同一行并从第二个 xml 添加新行，我不知道它有多可行

Answer 1

这是一个带有显式 foreach 循环的解决方案：

var doc = XDocument.Parse(@"<ContactEmployees>
  <row>
    <Name>NAME</Name>
    <Position>Mag</Position>
    <Phone1>number</Phone1>
    <E_Mail>mail</E_Mail>
    <InternalCode>11</InternalCode>
    <Gender>gt_Undefined</Gender>
    <Active>tYES</Active>
    <FirstName>Tizio</FirstName>
    <BlockSendingMarketingContent>tNO</BlockSendingMarketingContent>
  </row>
</ContactEmployees>");

var doc2 = XDocument.Parse(@"<ContactEmployees>
      <row>
        <CardCode>1000010</CardCode>
        <Name>NAME</Name>
        <Position>Mag</Position>
        <Phone1>number</Phone1>
        <E_Mail>mail</E_Mail>
        <InternalCode>11</InternalCode>
        <Gender>gt_Undefined</Gender>
        <Active>tYES</Active>
        <BlockSendingMarketingContent>tNO</BlockSendingMarketingContent>
      </row>
      <row>
        <CardCode>1000010</CardCode>
        <Name>Prova</Name>
        <InternalCode>2703</InternalCode>
        <PlaceOfBirth>-1</PlaceOfBirth>
        <Gender>gt_Undefined</Gender>
        <Active>tYES</Active>
        <FirstName>Prova</FirstName>
        <BlockSendingMarketingContent>tNO</BlockSendingMarketingContent>
      </row>
    </ContactEmployees>");
    
var employees = doc.Root;

var employees2 = doc2.Root;

foreach (var row2 in employees2.Elements("row"))
{
    // the following may be adapted to whatever criterion shall be used
    // to identify a record
    var id2 = row2.Element("InternalCode").Value;
    var row = employees.Elements("row").FirstOrDefault(r => r.Element("InternalCode").Value == id2);

    if (row == null)
    {
        // row not found in doc, so add it
        employees.Add(row2);
    }
    else
    {
        // row found; maybe update it, e.g.
        var nameElement2 = row2.Element("Name");
        if (nameElement2 != null)
        {
            var nameElement = row.Element("Name");
            if (nameElement == null)
                nameElement = nameElement2;
            else
                nameElement.Value = nameElement2.Value;
        }
    }
}

结果 XML 在 doc.

合并两个 XDocument

Merge two XDocument

c#

xml

linq-to-xml