从事件处理程序更改 textBox.text

Question

似乎无法在这里找到我一生的答案.. 无论如何，事件处理程序如何更改表单的 textBox.text？

private static void DataReceivedHandler(object sender, SerialDataReceivedEventArgs e)
        {
            SerialPort sp = (SerialPort)sender;
            string indata = sp.ReadExisting();
            //Do what ever you want with the data
            textBox2.Text = "test"; //alas, this doesn't work
        }

按下按钮时创建事件处理程序

private void button3_Click(object sender, EventArgs e)
        {
                    serialPort1.PortName = comboBox1.Text;
                    serialPort1.BaudRate = Convert.ToInt32(comboBox2.Text);
                    serialPort1.RtsEnable = true;
                    serialPort1.DtrEnable = true;
                    serialPort1.DataReceived += new SerialDataReceivedEventHandler(DataReceivedHandler);
                    serialPort1.Open();
                }
            }

非常感谢任何帮助

Answer 1

DataReceivedHandler方法被标记为static，所以它不能访问实例成员textBox2。删除 static 是否解决问题？

Answer 2

DataReceived 在它自己的线程上，您需要调用 GUI 才能更新文本框。

private void serialPort1_DataReceived(object sender, System.IO.Ports.SerialDataReceivedEventArgs e)
{
    string Data = serialPort1.ReadExisting();

    this.Invoke((MethodInvoker)delegate
    {
        textBox2.AppendText(Data);
    });
}

从事件处理程序更改 textBox.text

Changing textBox.text from event handler

c#

events

serial-port

handler