计算与日期时间上一行的天数差异

Question

我有一个 log_file table 是我用 Created_at 作为日期时间列创建的，我需要通过 created_at

在行之间获得天数

select id,DATE(created_at), datediff( created_at, prev_date) as diff
from (select t.*,
         (select DATE(t2.created_at)
          from log_file t2
          where t2.id = t.id and
                DATE(t2.created_at) <  DATE(t.created_at)
          order by  t2.created_at desc
          limit 1
         ) as prev_date
  from log_file t
 )  t

但它在 diff

中给我 Null

    id DATE(created_at) diff
     2 2019-01-16       NULL
     3 2019-01-19       NULL
     4 2019-01-21       NULL

Answer 1

如果您使用的 MySQL 版本早于 8+，并且您也不想使用会话变量，那么相关子查询是一种方法。

SELECT
    t1.id,
    t1.created_at,
    DATEDIFF(t1.created_at,
             (SELECT t2.created_at FROM log_file t2
              WHERE t2.created_at < t1.created_at
              ORDER BY t2.created_at DESC LIMIT 1)) AS diff
FROM log_file t1;

您的方向是正确的，但是子查询中的 WHERE 子句添加的条件不正确：

where t2.id = t.id

删除它，您当前的代码甚至可以按原样工作。

计算与日期时间上一行的天数差异

Calculate Days difference from Datetime previous row

mysql

datediff