按年月计算分隔内的连续 DRY 值

Count consecutive DRY values within separation by year-month

我有一个数据框。

dat <- read.table(text = "
YEAR  MONTH DAY PCP  SPELL 
1950   12   28   0    DRY    
1950   12   29  11.7  WET
1950   12   30   0    DRY
1950   12   31   0    DRY
1951   01   01   0    DRY
1951   01   02   0    DRY
1951   01   03  20.3  WET
", header = TRUE)

我按年和月创建组,

library(tidyverse)

groups <- dat %>% group_by(YEAR , MONTH) %>% summarise(NUM = n())

groups$ID <- 1:length(grupos$NUM)

dat %>% left_join(groups, by = c("YEAR", "MONTH"))

并应用脚本,

dfx <- data.frame(dat, svalue = NA)

dfx$svalue[1] <- ifelse(dfx$SPELL[1] == "DRY", 1, 0)

for(i in 2:nrow(dfx)) 
  dfx$svalue[i] <- ifelse(dfx$SPELL[i] == 0, dfx$svalue[i - 1] + 1, 0)

然后,我得到:

YEAR  MONTH DAY PCP  SPELL svalue
1950   12   28   0    DRY    1
1950   12   29  11.7  WET    0
1950   12   30   0    DRY    1
1950   12   31   0    DRY    2
1951   01   01   0    DRY    3 
1951   01   02   0    DRY    4
1951   01   03  20.3  WET    0

如何按年和月分隔值?
我需要得到这个:

YEAR  MONTH DAY PCP  SPELL svalue
1950   12   28   0    DRY    1
1950   12   29  11.7  WET    0
1950   12   30   0    DRY    1
1950   12   31   0    DRY    2
1951   01   01   0    DRY    1 
1951   01   02   0    DRY    2
1951   01   03  20.3  WET    0

或套用RMRAINGEN包的dw.spell,年月分离。

谢谢。

根据预期的输出,它可以通过创建另一个组来创建,该组具有在 'svalue'

上创建的逻辑向量
library(data.table)
setDT(dfx)[svalue != 0, svalue := seq_len(.N), .(cumsum(svalue == 1), YEAR, MONTH)]
dfx
#   YEAR MONTH DAY  PCP SPELL svalue
#1: 1950    12  28  0.0   DRY      1
#2: 1950    12  29 11.7   WET      0
#3: 1950    12  30  0.0   DRY      1
#4: 1950    12  31  0.0   DRY      2
#5: 1951     1   1  0.0   DRY      1
#6: 1951     1   2  0.0   DRY      2
#7: 1951     1   3 20.3   WET      0

或按 'SPELL'

run-length-id 分组
setDT(dfx)[, svalue := seq_len(.N) * (svalue != 0), .(rleid(SPELL), YEAR, MONTH)]

数据

dfx <- structure(list(YEAR = c(1950L, 1950L, 1950L, 1950L, 1951L, 1951L, 
 1951L), MONTH = c(12L, 12L, 12L, 12L, 1L, 1L, 1L), DAY = c(28L, 
 29L, 30L, 31L, 1L, 2L, 3L), PCP = c(0, 11.7, 0, 0, 0, 0, 20.3
 ), SPELL = c("DRY", "WET", "DRY", "DRY", "DRY", "DRY", "WET"), 
  svalue = c(1L, 0L, 1L, 2L, 3L, 4L, 0L)), class = "data.frame",
 row.names = c(NA, -7L))