在猫鼬中引用属性

Question

我做了一些 file.js 这样的：

文件Children.js

var mongoose = require('mongoose');
var ChildrentSchema = new mongoose.Schema
({
    name: String
});
module.exports = mongoose.model("Childrent", ChildrentSchema);`

文件Dad.js

var mongoose = require('mongoose');
var DadSchema = new mongoose.Schema
({
    name: String,
    child:
    {
        type: mongoose.Schema.Types.ObjectId,
        ref: 'Childrent'
    }
});
module.exports = mongoose.model("Dad", DadSchema);`

文件Grand.js

var mongoose = require('mongoose');
var GrandSchema = new mongoose.Schema
({
    name: String,
    childs:
    {
        type: mongoose.Schema.Types.ObjectId,
        ref: 'Dad'
    },
    <...>
});
module.exports = mongoose.model("Grand", GrandSchema);`

并在文件中 app1.js

require("./database");
var Grand = require('./Grand'),
Dad = require('./Dad'),
Childrent = require('./Childrent');
var child1 = new Childrent
({
    name: "Alex"
});
child1.save();
var dad1 = new Dad
({
    name: "Robin",
    child: child1._id
});
dad1.save();
var gran1 = new Grand
({
    name: "Paul",
    childs: dad1._id,
    <...>
})
grand1.save();`

所以我需要得到 Paul 的所有孙子，但我不知道如何在 <...>.

中编写一些代码

有人帮帮我！请！

Answer 1

这应该有效：

var gran1 = new Grand
   ({
       name: "Paul",
       childs: dad1._id,
       grandchilds: dad1.child
})

在猫鼬中引用属性

Referencing properties in mongoose

node.js

mongodb

properties

reference

family-tree