如何获取所有行值制表符?
How to get all row values tabulator?
我有 editable table 使用制表符。
一切正常,但问题是单击时无法获取所有行值 "save button"
我正在尝试的是:
$(document).ready(function() {
var tabledata = [
{id:1, name:"Oli Bob", age:"12", col:"red", dob:""},
{id:2, name:"Mary May", age:"1", col:"blue", dob:"14/05/1982"},
{id:3, name:"Christine Lobowski", age:"42", col:"green", dob:"22/05/1982"},
{id:4, name:"Brendon Philips", age:"125", col:"orange", dob:"01/08/1980"},
{id:5, name:"Margret Marmajuke", age:"16", col:"yellow", dob:"31/01/1999"},
];
var table = new Tabulator("#example-table", {
height:205,
data:tabledata,
layout:"fitColumns",
columns:[
{title:"Name", field:"name", width:150},
{title:"Age", field:"age", visible: false},
{title:"Favourite Color", field:"col"},
{title:"Date Of Birth", field:"dob", sorter:"date", align:"center"},
],
footerElement:"<button id='save' class='pull-left' title='Save'>Save</button> ",
});
$(document).on("click", "#save", function(){
/* var data = $("#example-table").tabulator("getData"); */
var data = $('#example-table').getData();
console.log('save clicked');
});
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<link href="https://unpkg.com/tabulator-tables@4.1.4/dist/css/tabulator.min.css" rel="stylesheet">
<script type="text/javascript" src="https://unpkg.com/tabulator-tables@4.1.4/dist/js/tabulator.min.js"></script>
<script type="text/javascript" src="https://cdnjs.cloudflare.com/ajax/libs/tabulator/4.1.5/js/jquery_wrapper.js"></script>
<div id="example-table"></div>
当运行时显示错误
TypeError: $.widget is not a function
当我尝试使用时:
var data = $("#example-table").tabulator("getData");
我收到这个错误:
TypeError: $(...).tabulator is not a function
使用时:
var data = $('#example-table').getData();
错误是:
TypeError: $(...).getData is not a function
当我尝试使用此方法定义 table 时:
$("#example-table").tabulator({ //table setup options });
它没有显示任何内容(空白)。
谁能告诉我怎么了?或者给我参考如何获取所有行值?
你也可以在 jsfiddle 中试试,查看 here
而不是 var data = $('#example-table').getData();
使用,var data = table.getData();
你正在做的是将 getData()
链接到 jQuery 函数,但你必须在 Tabulator table 实例上实现 getData()
,这是你的 var table
在上面创建。
希望这对您有所帮助。
谢谢!
基于我上次声明 table 内部函数的评论。
这是我在点击保存按钮时获取特定值的方法
$(document).ready(function() {
function generateGrid(){
var tabledata = [
{id:1, name:"Oli Bob", age:"12", col:"red", dob:""},
{id:2, name:"Mary May", age:"1", col:"blue", dob:"14/05/1982"},
{id:3, name:"Christine Lobowski", age:"42", col:"green", dob:"22/05/1982"},
{id:4, name:"Brendon Philips", age:"125", col:"orange", dob:"01/08/1980"},
{id:5, name:"Margret Marmajuke", age:"16", col:"yellow", dob:"31/01/1999"},
];
var table = new Tabulator("#example-table", {
height:205,
data:tabledata,
layout:"fitColumns",
columns:[
{title:"Name", field:"name", width:150},
{title:"Age", field:"age", visible: false},
{title:"Favourite Color", field:"col", editor:"input", formatter:
function (row, formatterParams){
let rowId = row.getData().id;
let color = row.getData().col;
return '<input type="text" class="txtAU" name="txtAU" id="txtAU'+rowId+'" value="' + color +'"/>';
}
},
{title:"Date Of Birth", field:"dob", sorter:"date", align:"center"},
],
footerElement:"<button id='save' class='pull-left' title='Save'>Save</button> ",
});
}
$(document).on("click", "#view", function(){
generateGrid();
$('#example-table').show();
});
$(document).on("click", "#save", function(){
var data_ = "";
var i = 1;
$("input[name='txtAU']").each(function(){
data_=data_+$(this).val()+";";
i++;
});
console.log(data_);
console.log('save clicked');
});
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<link href="https://unpkg.com/tabulator-tables@4.1.4/dist/css/tabulator.min.css" rel="stylesheet">
<script type="text/javascript" src="https://unpkg.com/tabulator-tables@4.1.4/dist/js/tabulator.min.js"></script>
<button id='view' class='pull-left' title='Save'>Show Table</button>
<div id="example-table" style="display:none"></div>
如果你想像往常一样获取所有值并声明 table,你可以使用
var data = table.getData();
喜欢 Gaurav 的回答。谢谢,希望这对某人有所帮助。
版本 4.5+ 的更新:
在 4.5+ 版本中,有一个函数可以让您在无法访问 table 变量时使用查询选择器找到 table。
http://tabulator.info/docs/4.6/options#find-table
const table = Tabulator.prototype.findTable('#example-table')[0];
const data = table.getData();
原回答:
问题是因为您在函数内声明了 table 变量,所以它的范围是有限的。
如果您在全局范围内声明它,然后在函数内分配它,那么它将在任何地方都可以访问。
//global scope
var table
//assign inside table - notice no "var"
function generateGrid(){
table = new Tabulator("#example-table", { ....
}
//you can then use it everywhere
var data = table.getData();
我有 editable table 使用制表符。
一切正常,但问题是单击时无法获取所有行值 "save button"
我正在尝试的是:
$(document).ready(function() {
var tabledata = [
{id:1, name:"Oli Bob", age:"12", col:"red", dob:""},
{id:2, name:"Mary May", age:"1", col:"blue", dob:"14/05/1982"},
{id:3, name:"Christine Lobowski", age:"42", col:"green", dob:"22/05/1982"},
{id:4, name:"Brendon Philips", age:"125", col:"orange", dob:"01/08/1980"},
{id:5, name:"Margret Marmajuke", age:"16", col:"yellow", dob:"31/01/1999"},
];
var table = new Tabulator("#example-table", {
height:205,
data:tabledata,
layout:"fitColumns",
columns:[
{title:"Name", field:"name", width:150},
{title:"Age", field:"age", visible: false},
{title:"Favourite Color", field:"col"},
{title:"Date Of Birth", field:"dob", sorter:"date", align:"center"},
],
footerElement:"<button id='save' class='pull-left' title='Save'>Save</button> ",
});
$(document).on("click", "#save", function(){
/* var data = $("#example-table").tabulator("getData"); */
var data = $('#example-table').getData();
console.log('save clicked');
});
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<link href="https://unpkg.com/tabulator-tables@4.1.4/dist/css/tabulator.min.css" rel="stylesheet">
<script type="text/javascript" src="https://unpkg.com/tabulator-tables@4.1.4/dist/js/tabulator.min.js"></script>
<script type="text/javascript" src="https://cdnjs.cloudflare.com/ajax/libs/tabulator/4.1.5/js/jquery_wrapper.js"></script>
<div id="example-table"></div>
当运行时显示错误
TypeError: $.widget is not a function
当我尝试使用时:
var data = $("#example-table").tabulator("getData");
我收到这个错误:
TypeError: $(...).tabulator is not a function
使用时:
var data = $('#example-table').getData();
错误是:
TypeError: $(...).getData is not a function
当我尝试使用此方法定义 table 时:
$("#example-table").tabulator({ //table setup options });
它没有显示任何内容(空白)。
谁能告诉我怎么了?或者给我参考如何获取所有行值?
你也可以在 jsfiddle 中试试,查看 here
而不是 var data = $('#example-table').getData();
使用,var data = table.getData();
你正在做的是将 getData()
链接到 jQuery 函数,但你必须在 Tabulator table 实例上实现 getData()
,这是你的 var table
在上面创建。
希望这对您有所帮助。 谢谢!
基于我上次声明 table 内部函数的评论。
这是我在点击保存按钮时获取特定值的方法
$(document).ready(function() {
function generateGrid(){
var tabledata = [
{id:1, name:"Oli Bob", age:"12", col:"red", dob:""},
{id:2, name:"Mary May", age:"1", col:"blue", dob:"14/05/1982"},
{id:3, name:"Christine Lobowski", age:"42", col:"green", dob:"22/05/1982"},
{id:4, name:"Brendon Philips", age:"125", col:"orange", dob:"01/08/1980"},
{id:5, name:"Margret Marmajuke", age:"16", col:"yellow", dob:"31/01/1999"},
];
var table = new Tabulator("#example-table", {
height:205,
data:tabledata,
layout:"fitColumns",
columns:[
{title:"Name", field:"name", width:150},
{title:"Age", field:"age", visible: false},
{title:"Favourite Color", field:"col", editor:"input", formatter:
function (row, formatterParams){
let rowId = row.getData().id;
let color = row.getData().col;
return '<input type="text" class="txtAU" name="txtAU" id="txtAU'+rowId+'" value="' + color +'"/>';
}
},
{title:"Date Of Birth", field:"dob", sorter:"date", align:"center"},
],
footerElement:"<button id='save' class='pull-left' title='Save'>Save</button> ",
});
}
$(document).on("click", "#view", function(){
generateGrid();
$('#example-table').show();
});
$(document).on("click", "#save", function(){
var data_ = "";
var i = 1;
$("input[name='txtAU']").each(function(){
data_=data_+$(this).val()+";";
i++;
});
console.log(data_);
console.log('save clicked');
});
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<link href="https://unpkg.com/tabulator-tables@4.1.4/dist/css/tabulator.min.css" rel="stylesheet">
<script type="text/javascript" src="https://unpkg.com/tabulator-tables@4.1.4/dist/js/tabulator.min.js"></script>
<button id='view' class='pull-left' title='Save'>Show Table</button>
<div id="example-table" style="display:none"></div>
如果你想像往常一样获取所有值并声明 table,你可以使用
var data = table.getData();
喜欢 Gaurav 的回答。谢谢,希望这对某人有所帮助。
版本 4.5+ 的更新:
在 4.5+ 版本中,有一个函数可以让您在无法访问 table 变量时使用查询选择器找到 table。 http://tabulator.info/docs/4.6/options#find-table
const table = Tabulator.prototype.findTable('#example-table')[0];
const data = table.getData();
原回答:
问题是因为您在函数内声明了 table 变量,所以它的范围是有限的。
如果您在全局范围内声明它,然后在函数内分配它,那么它将在任何地方都可以访问。
//global scope
var table
//assign inside table - notice no "var"
function generateGrid(){
table = new Tabulator("#example-table", { ....
}
//you can then use it everywhere
var data = table.getData();