使用 CreateFile 打开文件*

Question

有没有办法根据 C++ 中 WinAPI CreateFile 返回的句柄创建 stdio 的 FILE* 结构？

Answer 1

可能是这样的：

#include <Windows.h>
#include <io.h>
#include <stdio.h>
#include <stdlib.h>
#include <stdint.h>
#include <stddef.h>

// takes ownership of h_file
// caller is responsible for disposing of returned stream descriptor
[[nodiscard]] FILE *
make_stream(HANDLE const h_file)
{
     FILE * p_file{};
     int const fd{::_open_osfhandle(reinterpret_cast<::intptr_t>(h_file), _O_RDONLY)}; // transferring h_file ownerhip
     if(-1 != fd)
     {
          p_file = ::_fdopen(fd, "r"); // transferring fd ownerhip
          if(NULL != p_file)
          {
              // ok
          }
          else
          {
               if(-1 == ::_close(fd))
               {
                   ::abort();
               }
          }
     }
     else
     {
         if(FALSE == ::CloseHandle(h_file))
         {
             ::abort();
         }
     }
     return p_file;
}

使用 CreateFile 打开文件*

Open FILE* using CreateFile

c++

file

winapi

fopen

createfile