按模式返回具有逗号分隔值的行 (Oracle SQL)

Returning rows with comma-separated values by pattern (Oracle SQL)

我有一些带逗号分隔值的字段:

1,2,AA,4,Z
1,ZZ,44,A,1
1,44,33,AA,Z
4,2,Z,A,F
1.2,4,E,1,1
F,1,3.4,3,A

是否可以 select 行规则:number,number,chars, anything_values?

结果可以是:

1,2,AA,4,Z
4,2,Z,A,F
1.2,4,E,1,1

我正在尝试使用 REGEXP_LIKE:

with s as (
select '1,2,AA,4,Z'   val from dual
union all
select '1,ZZ,44,A,1'  val from dual
union all
select '1,44,33,AA,Z' val from dual
union all
select '4,2,Z,A,F'    val from dual
union all
select '1.2,4,E,1,1'  val from dual
union all
select 'F,1,3.4,3,A'  val from dual
)
select val from s where REGEXP_LIKE(val, '(^|,)[[:digit:]](,|$)');

感谢您参加 CTE。

这样的东西行吗?

  • INTER 将每个 VAL 分成行
  • LISTAGG 将它们汇总回来,按数字和字符排序

SQL> with s as (
  2  select '1,2,AA,4,Z'   val from dual
  3  union all
  4  select '1,ZZ,44,A,1'  val from dual
  5  union all
  6  select '1,44,33,AA,Z' val from dual
  7  union all
  8  select '4,2,Z,A,F'    val from dual
  9  union all
 10  select '1.2,4,E,1,1'  val from dual
 11  union all
 12  select 'F,1,3.4,3,A'  val from dual
 13  ),
 14  inter as
 15    (select s.val,
 16            regexp_substr(s.val, '[^,]+', 1, t.column_value) c_one
 17     from s, table(cast(multiset(select level from dual
 18                                 connect by level <= regexp_count(s.val, ',') + 1
 19                                ) as sys.odcinumberlist )) t
 20    )
 21  select i.val, listagg(i.c_one, ',') within group
 22                   (order by case when regexp_like(i.c_one, '^\d+|\.|\d+$') then 1
 23                                  when regexp_like(i.c_one, '^[:alpha:]+') then 2
 24                                  else 3
 25                             end) result
 26  from inter i
 27  group by i.val;

VAL          RESULT
------------ --------------------
1,2,AA,4,Z   1,2,4,AA,Z
1,44,33,AA,Z 1,33,44,AA,Z
1,ZZ,44,A,1  1,1,44,A,ZZ
1.2,4,E,1,1  1,1,1.2,4,E
4,2,Z,A,F    2,4,A,F,Z
F,1,3.4,3,A  1,3,3.4,A,F

6 rows selected.

SQL>

如果您只想 return 匹配模式 number, number, word, anything

的行,这个正则表达式应该工作 '^([0-9.]*,)([0-9.]*,)([A-Z]+)'
select val from s where REGEXP_LIKE(val, '^([0-9.]*,)([0-9.]*,)([A-Z]+)');