如何在 Java 中对角检查二维字符数组中的字符串 (Eclipse)
How to Diagonally Check String in a 2D Char Array in Java (Eclipse)
我正在获取用户输入的单词列表，并将他们的输入存储在 String[] 数组中。然后我创建了一个名为 letterGrid 的 char[][] 数组，其中填充了随机字母和用户提供的单词。然后，当 letterGrid 显示在控制台屏幕上时，用户必须输入他们想要查找的单词。然后程序将检查输入的单词是否水平、垂直或对角出现，并打印出s location. I have the checkHorizontal and checkDiagonal methods working fine, but I am having a problem at checkVertical. For example, my sample input of words was红色、橙色、黄色、绿色、蓝色、紫色、彩虹, and颜色。`下面是输出网格：
如你所见，当我输入黄色（6个字母长度）时，程序输出了这个词的位置，但随后出现了越界错误。
已编辑代码
这是应@Igor Khvostenkov 的要求的其余代码：
private String word; // This variable will be the user`s input when they chose to search for a word they have entered
private int rowLocation; // This variable will represent the row number in which the word is at
private int colLocation; // This variable will represent the column number in which the word is at
// Create a method to compare the user`s word to the elements in the letter grid
public void compare (String word) {
for (int row = 0; row < letterGrid.length - 1; row++) {
for (int col = 0; col < letterGrid[row].length - 1; col++) {
if (letterGrid[row][col] == word.charAt(0)) {
rowLocation = row;
colLocation = col;
wordContains(); // Call on method to see if the word entered by the user appears horizontally, vertically, or diagonally
}//end of if
}//end of inner for loop
}//end of outer for loop
}//end of compare(word)
// Create a method that will check the direction of the user`s word input
public void wordContains() {
checkHorizontal(); // Checking if the word appears horizontally
checkVertical(); // Checking id the word appears vertically
checkDiagonal(); // Checking if the word appears diagonally
}//end of wordContains()
// Create a method to check if the user`s word appears HORIZONTALLY in the letter grid
public void checkHorizontal() {
for (int i = 1; i < (word.length()); i++) {
if (colLocation + i > letterGrid[0].length - 1) {
return;
} else if(letterGrid[rowLocation][colLocation + i] != word.charAt(i)) {
return;
}//end of if..else if
}//end of for loop
System.out.println(word + " found horizontally at row " + rowLocation + " and column " + colLocation); // Word found!!
System.out.println();
return;
}//end of checkHorizontal()
// Create a method to check if the user`s word appears VERTICALLY in the letter grid
public void checkVertical() {
for (int i = 1; i < (word.length()); i++) {
if (rowLocation + i > letterGrid.length - 1 && colLocation + i > letterGrid[0].length) {
return;
} else if (letterGrid[rowLocation + i][colLocation] != word.charAt(i)) {
return;
}//end of if..else if
}//end of for loop
System.out.println(word + " found vertically at row " + rowLocation + " and column " + colLocation); // Word found!!
System.out.println();
}//end of checkVertical()
// Create a method to check if the user`s word appears DIAGONALLY in the letter grid
public void checkDiagonal() {
for (int i = 1; i < (word.length()); i++) {
if (colLocation + i > letterGrid[0].length - 1 || rowLocation + i > letterGrid.length - 1) {
return;
} else if (letterGrid[rowLocation + i][colLocation + i] != word.charAt(i)) {
return;
}//end of if..else if
}//end of for loop
System.out.println(word + " found diagonally at row " + rowLocation + " and column " + colLocation); // Word found!!
System.out.println("");
}//end of checkDiagonal()
我可以t seem to know why this is happening, and how I can fix this. I am not that familiar with ArrayIndexOutofBounds Exceptions as I barely go through them, but recently I have been and I一直在尝试理解问题并寻找帮助我解决问题的方法。
代码中的问题出在 checkVertical() 中的 if 条件中，行和列可以是第一个或最后一个，但您应该检查行或列。您的黄色示例由于第一个代码在第一行和第二列中找到 Y 而失败，然后继续扫描，最后，它在最后一行中找到 Y 并检查跳过的 rowLocation + i > letterGrid.length - 1 && colLocation + i > letterGrid[0].length，然后调用 else 将 1 添加到该行，结果超出了数组的范围。这应该有效：
public void checkVertical() {
for (int i = 1; i < (word.length()); i++) {
if (rowLocation + i > letterGrid.length - 1 || colLocation + i > letterGrid[0].length) {
return;
} else if (letterGrid[rowLocation + i][colLocation] != word.charAt(i)) {
return;
}//end of if..else if
}//end of for loop
System.out.println(word + " found vertically at row " + rowLocation + " and column " + colLocation); // Word found!!
System.out.println();
}//end of checkVertical()
我正在获取用户输入的单词列表，并将他们的输入存储在 String[] 数组中。然后我创建了一个名为 letterGrid 的 char[][] 数组，其中填充了随机字母和用户提供的单词。然后，当 letterGrid 显示在控制台屏幕上时，用户必须输入他们想要查找的单词。然后程序将检查输入的单词是否水平、垂直或对角出现，并打印出s location. I have the checkHorizontal and checkDiagonal methods working fine, but I am having a problem at checkVertical. For example, my sample input of words was红色、橙色、黄色、绿色、蓝色、紫色、彩虹, and颜色。`下面是输出网格：
如你所见，当我输入黄色（6个字母长度）时，程序输出了这个词的位置，但随后出现了越界错误。
已编辑代码
这是应@Igor Khvostenkov 的要求的其余代码：
private String word; // This variable will be the user`s input when they chose to search for a word they have entered
private int rowLocation; // This variable will represent the row number in which the word is at
private int colLocation; // This variable will represent the column number in which the word is at
// Create a method to compare the user`s word to the elements in the letter grid
public void compare (String word) {
for (int row = 0; row < letterGrid.length - 1; row++) {
for (int col = 0; col < letterGrid[row].length - 1; col++) {
if (letterGrid[row][col] == word.charAt(0)) {
rowLocation = row;
colLocation = col;
wordContains(); // Call on method to see if the word entered by the user appears horizontally, vertically, or diagonally
}//end of if
}//end of inner for loop
}//end of outer for loop
}//end of compare(word)
// Create a method that will check the direction of the user`s word input
public void wordContains() {
checkHorizontal(); // Checking if the word appears horizontally
checkVertical(); // Checking id the word appears vertically
checkDiagonal(); // Checking if the word appears diagonally
}//end of wordContains()
// Create a method to check if the user`s word appears HORIZONTALLY in the letter grid
public void checkHorizontal() {
for (int i = 1; i < (word.length()); i++) {
if (colLocation + i > letterGrid[0].length - 1) {
return;
} else if(letterGrid[rowLocation][colLocation + i] != word.charAt(i)) {
return;
}//end of if..else if
}//end of for loop
System.out.println(word + " found horizontally at row " + rowLocation + " and column " + colLocation); // Word found!!
System.out.println();
return;
}//end of checkHorizontal()
// Create a method to check if the user`s word appears VERTICALLY in the letter grid
public void checkVertical() {
for (int i = 1; i < (word.length()); i++) {
if (rowLocation + i > letterGrid.length - 1 && colLocation + i > letterGrid[0].length) {
return;
} else if (letterGrid[rowLocation + i][colLocation] != word.charAt(i)) {
return;
}//end of if..else if
}//end of for loop
System.out.println(word + " found vertically at row " + rowLocation + " and column " + colLocation); // Word found!!
System.out.println();
}//end of checkVertical()
// Create a method to check if the user`s word appears DIAGONALLY in the letter grid
public void checkDiagonal() {
for (int i = 1; i < (word.length()); i++) {
if (colLocation + i > letterGrid[0].length - 1 || rowLocation + i > letterGrid.length - 1) {
return;
} else if (letterGrid[rowLocation + i][colLocation + i] != word.charAt(i)) {
return;
}//end of if..else if
}//end of for loop
System.out.println(word + " found diagonally at row " + rowLocation + " and column " + colLocation); // Word found!!
System.out.println("");
}//end of checkDiagonal()
我可以t seem to know why this is happening, and how I can fix this. I am not that familiar with ArrayIndexOutofBounds Exceptions as I barely go through them, but recently I have been and I一直在尝试理解问题并寻找帮助我解决问题的方法。
代码中的问题出在 checkVertical() 中的 if 条件中，行和列可以是第一个或最后一个，但您应该检查行或列。您的黄色示例由于第一个代码在第一行和第二列中找到 Y 而失败，然后继续扫描，最后，它在最后一行中找到 Y 并检查跳过的 rowLocation + i > letterGrid.length - 1 && colLocation + i > letterGrid[0].length，然后调用 else 将 1 添加到该行，结果超出了数组的范围。这应该有效：
public void checkVertical() {
for (int i = 1; i < (word.length()); i++) {
if (rowLocation + i > letterGrid.length - 1 || colLocation + i > letterGrid[0].length) {
return;
} else if (letterGrid[rowLocation + i][colLocation] != word.charAt(i)) {
return;
}//end of if..else if
}//end of for loop
System.out.println(word + " found vertically at row " + rowLocation + " and column " + colLocation); // Word found!!
System.out.println();
}//end of checkVertical()