MySQL 8 嵌套 select 有计数

Question

SELECT mapname, 
    (SELECT count(1)+1 FROM ck_bonus b WHERE a.mapname=b.mapname AND a.runtime > b.runtime AND a.zonegroup = b.zonegroup AND b.style = %i) AS rank, 
    (SELECT count(1) FROM ck_bonus b WHERE a.mapname = b.mapname AND a.zonegroup = b.zonegroup AND b.style = %i) as total 
    FROM ck_bonus a WHERE steamid = '%s' AND style = %i;

这段代码在 MySQL8 更新之前可以正常工作，但现在出现此错误

You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near
 'rank, (SELECT count(1) FROM ck_bonus b WHERE a.mapname = b.mapname AND a.zonegro' at line 1

我遍历了 google，但找不到正确的答案。用 count() 或 count (*) 替换 count(1) 没有帮助。

此查询对于 MySQL8 应该是什么样的？

Answer 1

您在 outer & subquery 中遗漏了单引号：

SELECT mapname, 
       (SELECT count(1) FROM ck_bonus b WHERE a.mapname = b.mapname AND a.runtime > b.runtime AND a.zonegroup = b.zonegroup AND b.style = '%i') + 1 AS rnk, 
       (SELECT count(1) FROM ck_bonus b WHERE a.mapname = b.mapname AND a.zonegroup = b.zonegroup AND b.style = '%i') as total 
FROM ck_bonus a 
WHERE steamid = '%s' AND style = '%i';

我怀疑您需要 LIKE 谓词而不是 =。

Answer 2

单词rank是MySql8中的reserved word。

所以使用另一个别名，或者反引别名。

而在 MySql 8 中你可以使用 window functions

SELECT 
 mapname, 
 DENSE_RANK() OVER (PARTITION BY mapname, zonegroup, steamid, style ORDER BY runtime DESC) AS `rank`,
 COUNT(*) OVER (PARTITION BY mapname, zonegroup, steamid, style) AS total
FROM ck_bonus 
WHERE steamid = '%s' AND style = %i;

MySQL 8 嵌套 select 有计数

MySQL 8 nested select with count

mysql

sql

database

mysql-8.0