python 用户名和密码恢复系统的读取文件问题
reading file problem with python username and passowrd recovery system
这是一个恢复系统,用户可以在其中输入他们的唯一代码来恢复他们的详细信息。当输入唯一代码时,它会从文本文件中获取他们的详细信息,然后打印他们的用户名和密码。然后他们可以选择更改密码。我遇到的问题是,当我在其中输入旧密码时,它说密码不在该特定行中。文件中的格式是这样的:
(unique code) username: (username) password: (password)
global password1, password2,
check = True
while check:
hash1=input("\n"+"Enter your unique code to recover your username or password ")
with open("mount.txt","r") as file:
for line in file:
text = line.strip().split()
if hash1 in text:
print(line)
check = False
change = input("Do you want to change your password? [y,n]")
while change not in('y', 'n'):
change = input("Do you want to change your password? [y,n]")
if change == "y":
check = True
with open("mount.txt","r+") as file:
for line in file:
text = line.strip().split()
while check:
password1 = input("Enter old password ")
password2 = input("Enter new password ")
if len(password2) < 5:
print("New password is too short")
elif password1 not in text:
print("Old password is incorrect")
elif password1 in text:
s = open("mount.txt").read()
s = s.replace(password1, password2)
f = open("mount.txt", 'w')
f.write(s)
f.close()
print("Password has been successfully changed")
check = False
elif len(hash1) < 32 and (check == True):
print("Unique code not found please try again")
break
因此,当我输入唯一代码时,它显示正确的行,然后当我尝试更改密码时,它一直说密码不在该特定行中。
目前,在文本文件中的行循环时,如果hash1
不在任何行中,它会告诉你没有找到代码,并立即中断。
要解决此问题,您应该从 if hash1 in text
条件中中断或 return,然后测试 if len(hash1) < 32 and (check == True)
现在仅 运行 检查所有行后文件。
此外,假设文本是 'aslhngbadf username: bob password: alice',line.strip().split()
将是 ['aslhngbadf', 'username:', 'bob', 'password:', 'alice']
,因此检查 password1
是否在 text
中对一个人不起作用密码的字母。但是,如果您输入单词 'password:' 或 'bob'... ,它会起作用,检查是否明确匹配 if password1 == text[4]
.
最后,当您重新打开并遍历文件时,您会从文本匹配的行移回文件顶部。不要打开 mount.txt 两次。 text
仍然可用,并且与您第一次设置时相比没有变化。
这是一个恢复系统,用户可以在其中输入他们的唯一代码来恢复他们的详细信息。当输入唯一代码时,它会从文本文件中获取他们的详细信息,然后打印他们的用户名和密码。然后他们可以选择更改密码。我遇到的问题是,当我在其中输入旧密码时,它说密码不在该特定行中。文件中的格式是这样的:
(unique code) username: (username) password: (password)
global password1, password2,
check = True
while check:
hash1=input("\n"+"Enter your unique code to recover your username or password ")
with open("mount.txt","r") as file:
for line in file:
text = line.strip().split()
if hash1 in text:
print(line)
check = False
change = input("Do you want to change your password? [y,n]")
while change not in('y', 'n'):
change = input("Do you want to change your password? [y,n]")
if change == "y":
check = True
with open("mount.txt","r+") as file:
for line in file:
text = line.strip().split()
while check:
password1 = input("Enter old password ")
password2 = input("Enter new password ")
if len(password2) < 5:
print("New password is too short")
elif password1 not in text:
print("Old password is incorrect")
elif password1 in text:
s = open("mount.txt").read()
s = s.replace(password1, password2)
f = open("mount.txt", 'w')
f.write(s)
f.close()
print("Password has been successfully changed")
check = False
elif len(hash1) < 32 and (check == True):
print("Unique code not found please try again")
break
因此,当我输入唯一代码时,它显示正确的行,然后当我尝试更改密码时,它一直说密码不在该特定行中。
目前,在文本文件中的行循环时,如果hash1
不在任何行中,它会告诉你没有找到代码,并立即中断。
要解决此问题,您应该从 if hash1 in text
条件中中断或 return,然后测试 if len(hash1) < 32 and (check == True)
现在仅 运行 检查所有行后文件。
此外,假设文本是 'aslhngbadf username: bob password: alice',line.strip().split()
将是 ['aslhngbadf', 'username:', 'bob', 'password:', 'alice']
,因此检查 password1
是否在 text
中对一个人不起作用密码的字母。但是,如果您输入单词 'password:' 或 'bob'... ,它会起作用,检查是否明确匹配 if password1 == text[4]
.
最后,当您重新打开并遍历文件时,您会从文本匹配的行移回文件顶部。不要打开 mount.txt 两次。 text
仍然可用,并且与您第一次设置时相比没有变化。