如何将现有文件中的数据放入 Table

Question

我在 ComputerCraft 中有一个海龟程序，它是一个存储单元。我输入了一个项目，它应该读取一个文件来找到放置该项目的位置。如果有新项目，它会将信息添加到文件中。当我这样做时

blockTypes = {}

local file = fs.open(blockTable","r")
line = file.readAll()
table.insert(blockTypes,line)
file.close()

信息以字符串形式输入。这意味着我做不到

print(blockTypes[1][1])

并接收通常位于该位置的值。

这是我的代码：

blockAmount = 3
highestVal = {2,0,5}
blockTypes = {}
function addBlock()
    local file = fs.open("blockTable", "a")
    file.write(name)
    file.write(" = {")
    file.write(highestVal[1])
    file.write(",")
    file.write(highestVal[2])
    file.write(",")
    file.write(highestVal[3])
    file.writeLine("};")
    file.close()
end
function getBlock()
    local file = fs.open("blockTable","r")
    line = file.readAll()
    table.insert(blockTypes,line)
    file.close()
end
--This was used to test before implementing the new file system that I am trying to get to work
blockTypesOld = {
    log = {2.0,0,1};
    dirt = {2,0,2};
    cobblestone = {2,0,3};
    iron_ingot = {2,0,4};
    planks = {2,0,5};
}
pos = {0,0,0}
looking = 0
function fuel()
    if turtle.getFuelLevel() < 20 then
        turtle.select(16)
        turtle.refuel(1)
    end
end
function left()
    turtle.turnLeft()
    looking = looking - 1
    if looking < 0 then
        looking = 3
    end
end
function right()
    turtle.turnRight()
    looking = looking + 1
    if looking > 3 then
        looking = 0
    end
end
function forward()
    fuel()
        if turtle.forward() then
            if looking == 0 then
                pos[1] = pos[1] - 1
            elseif looking == 1 then
                pos[3] = pos[3] - 1 
            elseif looking == 2 then
                pos[1] = pos[1] + 1
            elseif looking == 3 then
                pos[3] = pos[3] + 1
            else
            end
        end

end
function up()
    fuel()
    turtle.up()
    pos[2] = pos[2] + 1
end
function down()
    fuel()
    turtle.down()
    pos[2] = pos[2] - 1
end
function goHome()
    while pos[3] > 0 do
        while  looking > 1 do
            left()
        end
        forward()
    end
    while  pos[2] > 0 do
        down()
    end
    while  pos[1] > 0 do
        while  looking > 0 do
            left()
        end
        forward()
    end
end
function goTo(a,b,c)
    goHome()
    while looking < 2 or looking > 2 do
        right()
    end
    for i = pos[1],a do
        forward()
    end
    while looking > 3 or looking < 3 do
        right()
    end
    for i = pos[3],c do
        forward()
    end
    for i = pos[2],b do
        up()
    end
    while looking < 2 or looking > 2 do
        left()
    end
end
while true do
    turtle.select(15)
    while not turtle.suck() do
        sleep(1)
    end
    itemDetails = turtle.getItemDetail()
    --Finding what mod item is from and removing corresponding labels--
    --EX: "minecraft:log" becomes "log"
    if itemDetails.name:match("^ae2stuff:(.+)$") then
        name = itemDetails.name:match("^ae2stuff:(.+)$")
    elseif itemDetails.name:match("^minecraft:(.+)$") then
        name = itemDetails.name:match("^minecraft:(.+)$")
    elseif itemDetails.name:match("^appliedenergistics2:(.+)$") then
        name = itemDetails.name:match("^appliedenergistics2:(.+)$")
    elseif itemDetails.name:match("^buildcraftbuilders:(.+)$") then
        name = itemDetails.name:match("^buildcraftbuilders:(.+)$")
    elseif itemDetails.name:match("^forge:(.+)$") then
        name = itemDetails.name:match("^forge:(.+)$")
    elseif itemDetails.name:match("^buildcraftenergy:(.+)$") then
        name = itemDetails.name:match("^buildcraftenergy:(.+)$")
    elseif itemDetails.name:match("^buildcraftfactory:(.+)$") then
        name = itemDetails.name:match("^buildcraftfactory:(.+)$")
    elseif itemDetails.name:match("^buildcraftsilicon:(.+)$") then
        name = itemDetails.name:match("^buildcraftsilicon:(.+)$")
    elseif itemDetails.name:match("^buildcrafttransport:(.+)$") then
        name = itemDetails.name:match("^buildcrafttransport:(.+)$")
    elseif itemDetails.name:match("^buildcraftcore:(.+)$") then
        name = itemDetails.name:match("^buildcraftcore:(.+)$")
    elseif itemDetails.name:match("^buildcraftlib:(.+)$") then
        name = itemDetails.name:match("^buildcraftlib:(.+)$")
    elseif itemDetails.name:match("^computercraft:(.+)$") then
        name = itemDetails.name:match("^computercraft:(.+)$")
    elseif itemDetails.name:match("^enderstorage:(.+)$") then
        name = itemDetails.name:match("^enderstorage:(.+)$")
    elseif itemDetails.name:match("^extracells:(.+)$") then
        name = itemDetails.name:match("^extracells:(.+)$")
    elseif itemDetails.name:match("^thermaldynamics:(.+)$") then
        name = itemDetails.name:match("^thermaldynamics:(.+)$")
    elseif itemDetails.name:match("^thermalexpansion:(.+)$") then
            name = itemDetails.name:match("^thermalexpansion:(.+)$")
    elseif itemDetails.name:match("^thermalfoundation:(.+)$") then
        name = itemDetails.name:match("^thermalfoundation:(.+)$")
    elseif itemDetails.name:match("^tconstruct:(.+)$") then
        name = itemDetails.name:match("^tconstruct:(.+)$")
    elseif itemDetails.name:match("^webdisplays:(.+)$") then
        name = itemDetails.name:match("^webdisplays:(.+)$")
    elseif itemDetails.name:match("^ironchest:(.+)$") then
        name = itemDetails.name:match("^ironchest:(.+)$")
    else
        print("ERROR MOD NOT FOUND")
    end
    getBlock()
    local elem = blockTypes[name]
    --Gets fuel from fuel chest
    right()
    turtle.select(16)
    turtle.suck(5)
    turtle.select(15)
    if elem then
    --If the item does exist, the turtle goes to it's chest and places it in the chest
        goTo(elem[1]-1, elem[2]-1, elem[3]-1)
        turtle.select(15)
        turtle.drop()
        goHome()
        right()
        turtle.select(16)
        turtle.drop()
        turtle.select(15)
        left()
    else
        --Creates information for new item--
        addBlock()
        blockAmount = blockAmount + 1
        highestVal[3] = highestVal[3] + 1
        if highestVal[3] > 5 then
            highestVal[3] = 1
            highestVal[2] = highestVal[2] + 1
        end
        if highestVal[2] > 4 then
            highestVal[2] = 0
            highestVal[1] = highestVal[1] + 2
        end
        blockTypes[blockAmount] = name
        blockTypes[name] = {highestVal[1],highestVal[2],highestVal[3]}
        local elem = blockTypes[name]
        left()
        turtle.select(15)
        turtle.drop()
        right()
        turtle.select(16)
        turtle.suck(2)
        fuel()
        turtle.drop()

        goTo(1,-1,4)
        --Crafts an Iron Chest for the New Item
        for i = 1,3 do
            turtle.select(i)
            turtle.suck(1)
        end
        turtle.select(5)
        turtle.suck(1)
        turtle.select(7)
        turtle.suck(1)
        for i = 9,11 do
            turtle.select(i)
            turtle.suck(1)
        end
        turtle.select(6)
        turtle.craft()
        goTo(1,-1,3)
        for i = 1,3 do
            turtle.select(i)
            turtle.suck(1)
        end
        turtle.select(5)
        turtle.suck(1)
        turtle.select(7)
        turtle.suck(1)
        for i = 9,11 do
            turtle.select(i)
            turtle.suck(1)
        end
        turtle.select(1)
        turtle.craft()
        goHome()
        right()
        turtle.select(16)
        turtle.suck(5)
        goTo(elem[1]-1, elem[2]-1, elem[3]-1)
        turtle.select(1)
        turtle.place()
        goHome()
    end
end

包含项目坐标的文件称为 blockTable，由以下内容组成：

--blockName = {xCoord,yCoord,zCoord};--
oak_stairs = {2.0,0.0,5.0};
iron_ingot = {2.0,0.0,4.0};
turtle = {2.0,0.0,5.0};

当我放入一个新物品时，它会注册该物品，制作一个箱子，然后放入。当我放入相同的物品时，它会直接进入箱子，而无需制作新物品。但是，当我重新启动乌龟并将相同的物品放入其中时，它会创建另一个新箱子并尝试将其放置在新物品中。我希望它即使在重新启动后也能保留其信息。我已经为这个程序苦苦挣扎了一段时间，我们将不胜感激。谢谢！

Answer 1

每次添加新块时读取/写入整个文件似乎有点混乱，特别是如果您考虑到您可能会在写入新文件的过程中重新启动 turtle 并最终丢失一半数据.

您确实有一个文件系统，那么为什么不用它呢？创建一个目录并为每个块名称写入一个新文件，然后将坐标保存在其中。这也允许您为每种块类型存储多个箱子，以防您在使用海龟挖掘地图的大块时比您预期的更早发财。

我刚刚意识到我实际上并没有回答这个问题，所以这里是：

当你有一个文件 file 时，你可以使用 file.readLine() 轻松阅读一行。这 returns 它读取为字符串的行，或者 nil 如果您在文件末尾。假设你只是在块名后面写了三个用空格分隔的坐标，你就可以将它们解析成一个 table 像这样：

local file = fs.open('chests')
local chests = {}
while true do
  local line = file.readLine()
  if line then
    local name, x, y, z = line:match("(%a+) ([%d.+-]+) ([%d.+-]+) ([%d.+-]+)")
    chests[name] = {
      tonumber(x),
      tonumber(y),
      tonumber(z)
    }
  else
    break
  end
end

将这一切封装在一个函数中以更加整洁。

旁注：

Computercraft处理文件有些不方便。在常规 Lua 中，我会这样做：

local function map(f, elem, ...)
    if elem then return f(elem), map(f, ...) end
end

local function readchests(file)
    local res = {}
    for line in io.open(file):lines() do
        local name, x, y, z = line:match("(%a+)"..(" [%d.-+]+"):rep(3))
        res[name]={map(tonumber, x, y, z)}
    end
    return res
end

如果你想保持存储数据的格式为有效的Lua代码，你可以用file.readAll()读取整个文件，在开头添加"return {"和"}" 最后加载并执行该字符串。总的来说，我不建议这样做。如果整个文件只是您可以阅读的有效 Lua 代码和运行.

就更好了

Answer 2

尽管如 DarkWiiPlayer 所述，不建议每次添加到新块时都读取文件。

要回答您的问题，您可以阅读 table 并使用 loadstring 从字符串中执行代码。

要使用您提供的文件中的现有字符串执行此操作，需要做一些额外的工作。可以通过调整文件中的字符串来删除这些额外的工作。

blockTypes = {}

line = "oak_stairs = {2.0,0.0,5.0};"
table_name = line:match("[%a_]+%s")
do_line = assert(loadstring('local ' .. line .. ' return ' .. table_name))
table = do_line();
table.insert(blockTypes,table)

这里我们使用 match 获取正在加载的 table 的名称。为 loadstring 创建一个字符串，构建 returns 和 table。执行加载的字符串，并将其插入到 blockTypes.

或者，您可以将要保存的文件调整为一个模块。

local blocktypes = {
    oak_stairs = {2.0,0.0,5.0},
    iron_ingot = {2.0,0.0,4.0},
    turtle = {2.0,0.0,5.0},
}
return blockTypes

然后你会这样加载数据：

blockTypes = require("blockTable")

如何将现有文件中的数据放入 Table

How to Put Data Into a Table From an Existing File

lua

computercraft