获取忽略口音的联系人

Question

我从 phone 中获取联系人，如下所示。我想忽略重音，例如名称 "Jérome" 将是 return 用于搜索 "jero" 或 "jéro".

 var contacts = listOf<Contact>()

        val displayNameProjection = arrayOf(ContactsContract.Contacts.PHOTO_THUMBNAIL_URI,  ContactsContract.Contacts.DISPLAY_NAME_PRIMARY)
        val whereName =  ContactsContract.Contacts.DISPLAY_NAME_PRIMARY + " LIKE ?"
        val whereNameParams = arrayOf( "%" + search + "%")
        val contactCursor = contentResolver.query(ContactsContract.Contacts.CONTENT_URI,
                displayNameProjection, whereName, whereNameParams,ContactsContract.Contacts.DISPLAY_NAME_PRIMARY)

        contactCursor?.let { cursor ->
            contacts = generateSequence { if (cursor.moveToNext()) cursor else null }
                    .take(10)
                    .map {
                        Contact( it.getString(it.getColumnIndex(ContactsContract.Contacts.DISPLAY_NAME_PRIMARY)),
                                it.getString(it.getColumnIndex(ContactsContract.Contacts.PHOTO_THUMBNAIL_URI)))
                    }
                    .toList()


            cursor.close()
        }

Answer 1

使用 CONTENT_FILTER_URI API 按姓名快速搜索联系人，这应该会自动为您处理重音符号：

String name = "jero";
Uri searchUri = Uri.withAppendedPath(Contacts.CONTENT_FILTER_URI, Uri.encode(name));
Cursor cur = getContentResolver().query(searchUri, null, null, null, null);
DatabaseUtils.dumpCursor(cur);
if (cur != null) cur.close();

获取忽略口音的联系人

Fetch contacts ignoring accents

android

locale

android-contacts

contactscontract