带条件的 PowerShell switch 语句

Question

如何在 PowerShell switch 语句中使用条件？ returns 0 下面的代码应该 return 1000.

$UsedSpaceMB = 8500

switch ($UsedSpaceMB) {
    ($UsedSpaceMB -gt 15000) { $FreeSpace = 2000 }
    ($UsedSpaceMB -in 8000..15000 ) { $FreeSpace = 1000 }
    ($UsedSpaceMB -in 1700..8000 ) { $FreeSpace = 500 }
    ($UsedSpaceMB -in 1000..1700 ) { $FreeSpace = 200 }
    ($UsedSpaceMB -in 800..1000 ) { $FreeSpace = 100 }
    ($UsedSpaceMB -lt 800 ) { $FreeSpace = 50 }
}
$FreeSpace

Answer 1

开关的语法不正确。请参阅 here 文档。

$UsedSpaceMB = 8500

switch ($UsedSpaceMB) {
    {$_ -gt 15000} { $FreeSpace = 2000 }
    {$_ -in 8000..15000 } { $FreeSpace = 1000 }
    {$_ -in 1700..8000 } { $FreeSpace = 500 }
    {$_ -in 1000..1700 } { $FreeSpace = 200 }
    {$_ -in 800..1000 } { $FreeSpace = 100 }
    {$_ -lt 800 } { $FreeSpace = 50 }
}
$FreeSpace

Answer 2

或者您可以使用 -contains

switch ($UsedSpaceMB) {
    {$_ -gt 15000} { $FreeSpace = 2000 }
    {8000..15000 -contains $_ } { $FreeSpace =1000 }
    {1700..8000 -contains $_} { $FreeSpace = 500 }
    {1000..1700 -contains $_ } { $FreeSpace = 200 }
    {800..1000 -contains $_ } { $FreeSpace = 100 }
    {$_ -lt 800 } { $FreeSpace = 50 }
}
$FreeSpace

带条件的 PowerShell switch 语句

PowerShell switch statement with conditionals

powershell

conditional