如何定义变量以排除 build.gradle.kts 中的多个传递依赖项

Question

我知道在基于 groovy 的 build.gradle 中，您可以定义多个排除项，如所述 here:

dependencies {
    def withoutStuff = { 
        exclude group: 'com.android.support', module: 'support-v4' 
        exclude group: 'com.android.support', module: 'support-v13'
        exclude group: 'com.android.support', module: 'design-v13' 
    }

    // For Material Datepicker
    compile deps.datePicker, withoutStuff
}

但是现在我们如何在基于 kotlin 的 build.gradle.kts 文件中执行此操作？

Answer 1

好的，经过大量搜索、跟踪和错误，我明白了。在依赖之上你可以定义：

val withoutStuff = fun ExternalModuleDependency.() {
    exclude(group = "com.android.support", module = "support-v4")
    exclude(group = "com.android.support", module = "support-v13")
    exclude(group = "com.android.support", module = "design-v13")
}

然后在 dependencies 块中你可以做：

dependencies {

    implementation(deps.datePicker, withoutStuff)
    ...
}

希望对其他人有所帮助，并期待其他答案。

Answer 2

或者，如果您想全局设置排除项，这可能有效：

// android {} 

configurations {
    implementation {
        exclude(group = "androidx.core", module = "app")
        exclude(group = "androidx.core", module = "core")
        exclude(group = "androidx.appcompat", module = "app")
        exclude(group = "com.google.firebase", module = "firebase-iid")
        exclude(group = "androidx.test", module = "monitor")
    }
}

// dependencies {}

灵感来自：

如何定义变量以排除 build.gradle.kts 中的多个传递依赖项

How do you define variables for excluding multiple transitive dependencies in a build.gradle.kts

gradle

kotlin

gradle-kotlin-dsl