拆分字符串（在空格或标点符号上）以获取所有数字

Question

我有一个字符串

Mystring = "123 456 789, 234, 999|567 888[222"

我想将此字符串拆分为 " " "," "|" 和 "[" 以获得列表中的所有数字

预期输出：-

List = ["123","456","789","234","999",567","888","222"]

我正在使用以下代码

Final_List = re.findall("(\d+?)[ ,|\]]",Mystring)

实际输出：

["123","456","789",234","999",567"]

我怎样才能得到这里的所有数字？

Answer 1

与其拆分字符串，不如直接获取数字：

>>> import re
>>> Mystring = "123 456 789, 234, 999|567 888[222"
>>> re.findall('\d+', Mystring)
['123', '456', '789', '234', '999', '567', '888', '222']
>>>

\d+ Python 匹配一个或多个数字（数字）。

Answer 2

import string
tbl = string.maketrans(',|[',"   ")

print(Mystring.translate(tbl)).split()
['123', '456', '789', '234', '999', '567', '888', '222']


In [29]: import string

In [30]: %%timeit
   ....: tbl = string.maketrans(',|[',"   ")
   ....: (Mystring.translate(tbl)).split()
   ....: 
1000000 loops, best of 3: 762 ns per loop

In [31]: import re

In [32]: timeit re.findall('\d+', Mystring)
100000 loops, best of 3: 2.99 µs per loop

拆分字符串（在空格或标点符号上）以获取所有数字

Split a string (on whitespace or punctuation) to get all numbers

python

regex

findall