Python 中断但 return 或存储当前值

Question

如何实现带有中断且 return中断处的值的 for 循环？

x = np.empty(1)

x[0] = 0.4

f = np.array([3,2,1,0,1,2,3])
y = np.empty(0)

for i in range(len(f)):
    if f[i+1] < f[i]:
        newx = x[i]*2
        y = np.append(y,f[i+1])
        x = np.append(x,newx)
    else:
        break

this returns y = [2,1,0] and x = [0.4,0.8,1.6,3.2] 但我希望它也 return 值 y = 1 and x = 6.4 这将是下一次迭代。

Answer 1

尝试这样的事情：

for i in range(len(f) - 1):        
    newx = x[i]*2
    y = np.append(y,f[i+1])
    x = np.append(x,newx)

    if f[i+1] > f[i]:
        break

此代码段还将在跳出循环之前追加下一次迭代。

Answer 2

尝试像这样将代码添加到您的 else 块中：

for i in range(len(f)):
    if f[i+1] < f[i]:
        newx = x[i]*2
        y = np.append(y,f[i+1])
        x = np.append(x,newx)
    else:
        y = np.append(y,f[i+1])
        x = np.append(x,newx)
        break

这可能会锻炼。

Answer 3

只需添加一个新条件。

x = np.empty(1)
x[0] = 0.4
f = np.array([3,2,1,0,1,2,3])
y = np.empty(0)
for i in range(len(f)):
    if f[i+1] < f[i]:
        newx = x[i]*2
        y = np.append(y,f[i+1])
        x = np.append(x,newx)
    elif f[i+1]>f[i] and f[i]==0:
        newx = x[i] * 2
        y = np.append(y, f[i + 1])
        x = np.append(x, newx)
    else:
        break

Python 中断但 return 或存储当前值

Python Break but return or store the current value

python

for-loop

numpy

break