如何在qt中绘制带彩色角的透明矩形？

Question

如何在qt（使用QPainter）中绘制一个带颜色角的透明矩形，如下图所示：

Answer 1

void Widget::paintEvent(QPaintEvent *) {
    draw(10,10,50,50);
}

void Widget::draw(int x,int y,int _width,int _height)
{
    QPainter p(this);
    p.setPen(QPen(Qt::red,3,Qt::SolidLine));
    p.drawLine(x,y,x +0,_height/4+y);
    p.drawLine(x,y+ _height,x + 0,_height - _height/4+y);
    p.drawLine(x,y,x +_width/4,0+y);
    p.drawLine(x,y+_height,x +_width/4,_height+y);
    p.drawLine(_width+x,y+_height,x +_width - _width/4,_height+y);
    p.drawLine(_width+x,y+_height,x +_width,_height - _height/4+y);
    p.drawLine(_width+x,y,x + _width-_width/4,0+y);
    p.drawLine(_width+x,y,_width+x,_height/4+y);
    //custom brush for rectangle
    //p.fillRect(x,y,_width,_height,QBrush(QColor(40,0,0,50)));
}

如何在qt中绘制带彩色角的透明矩形？

How to draw a transparent rectangle with colored corners in qt?

c++

qt

qpainter