嘲笑不执行模拟方法

Question

我有 class 名称 Validator 并且它有一个方法 forVote。这是我的代码。

public function test_should_set_default()
    {
        $this->mock = \Mockery::mock(Validator::class);
        $this->mock->shouldReceive('forVote')
            ->andReturnTrue();
        $this->app->instance(Validator::class,$this->mock);
        $factory = new Factory();
        $this->assertTrue($factory->setDefault());
    }

因此 Factory 调用 Processor，后者又调用 Validator。现在我想要模拟验证器运行。但是它调用了真正的方法。

我做错了什么？

Answer 1

https://laravel.com/docs/5.6/container#introduction

since the repository is injected, we are able to easily swap it out with another implementation. We are also able to easily "mock", or create a dummy implementation of the UserRepository when testing our application.

我猜你目前可能正在像这样实例化你的依赖项：

$processor = new Processor() 和 $validator = Validator::make(...);

因此，为了使用你的模拟 class，你应该使用依赖注入，这意味着你的 classes 应该通过 __construct 方法注入你的依赖。

你的 Factory class 应该是这样的：

class Factory {

   $processor;

   public function __construct(Processor $processor)
   {
       $this->processor = $processor;
   }

   public function setDefault()
   {
       $this->processor->callingValidator();
   }
}

你的 Processor 应该是这样的：

class Processor {

   $validator;

   /**
    * The Validator will resolve to your mocked class.
    *
    */
   public function __construct(Validator $validator)
   {
       $this->validator = $validator;
   }

   public function callingValidator()
   {
       $this->validator->make();
   }
}

嘲笑不执行模拟方法

Mockery not executing mock method

unit-testing

laravel-5

mockery