按照特定格式从完整地址字符串中提取城市和州

Question

我有一组地址存储为单独的字符串。以下是这些字符串的可能值：

"Staples Center, 555 Test Drive, Los Angeles, CA 98112"
"555 Test Drive, Los Angeles, CA 98112"
"Los Angeles, CA"
"Los Angeles, CA 98112"
"Los Angeles"

日期将始终遵循此格式，其中可以包含场地名称、街道地址、城市、州和邮政编码

我只想从这些字符串中动态提取城市和州：

$addresses_array = array(
    "Staples Center, 555 Test Drive, Los Angeles, CA 98112",
    "555 Test Drive, Los Angeles, CA 98112",
    "Los Angeles, CA",
    "Los Angeles, CA 98112",
    "Los Angeles"
);

foreach ($addresses_array as $address) {
    if (strpos($address, ',') !== false) {
        // extract the city and state
    }
}

鉴于地址值的模式，我可以根据逗号提取城市和州吗？

我能看到的是，城市永远是字符串中的最后一个逗号..

Answer 1

可以一起使用explode和count函数


$addresses_array = array(
    "Staples Center, 555 Test Drive, Los Angeles, CA 98112",
    "555 Test Drive, Los Angeles, CA 98112",
    "Los Angeles, CA",
    "Los Angeles, CA 98112",
    "Los Angeles"
);


foreach ($addresses_array as $address) {
    $addr = explode(",",$address);
    switch (count($addr))
    {
        case 1:
        case 2:
            echo  $addr[0];
            break;
        case 3:
            echo  $addr[1];
            break;
        case 4:
            echo  $addr[2];
            break;

    }
}

Answer 2

如果我没看错，那么您需要最后两项（如果有的话）。
使用 explode 然后内爆返回最后两个项目。

$addresses_array = array(
    "Staples Center, 555 Test Drive, Los Angeles, CA 98112",
    "555 Test Drive, Los Angeles, CA 98112",
    "Los Angeles, CA",
    "Los Angeles, CA 98112",
    "Los Angeles"
);

foreach ($addresses_array as &$address) {
    $arr = explode(", ", $address);
    $address = implode(", ", array_slice($arr, -2));
}

var_dump($addresses_array);

输出：

array(5) {
  [0]=>
  string(21) "Los Angeles, CA 98112"
  [1]=>
  string(21) "Los Angeles, CA 98112"
  [2]=>
  string(15) "Los Angeles, CA"
  [3]=>
  string(21) "Los Angeles, CA 98112"
  [4]=>
  &string(11) "Los Angeles"
}

https://3v4l.org/Gqcid

如果你不想要 zip，那么你可以在 space 上展开最后一个项目，如果 $arr 计数超过一个。

foreach ($addresses_array as &$address) {
    $arr = explode(", ", $address);
    if(count($arr) >1){
        $arr[count($arr)-1] = explode(" ", $arr[count($arr)-1])[0];
        $address = implode(", ", array_slice($arr, -2));
    }
}

输出：

array(5) {
  [0]=>
  string(15) "Los Angeles, CA"
  [1]=>
  string(15) "Los Angeles, CA"
  [2]=>
  string(15) "Los Angeles, CA"
  [3]=>
  string(15) "Los Angeles, CA"
  [4]=>
  &string(11) "Los Angeles"
}

https://3v4l.org/uKvke

按照特定格式从完整地址字符串中提取城市和州

Extract City and State from a Full Address String following Specific Format

php

strpos