画一条线 - 最大点
Drawing a Line - Maximum Point
我根据滑块画了一条斜线。
我正在尝试使线的末端 Y 坐标为某个数字(假设为 300),即使它是一个角度。
关于如何做到这一点有什么想法吗?到目前为止,这是我的生产线上的工作:
double angle = intAngle;
angle = angle * Math.PI / 180;
double length = 300;
graphics.setColor(Color.RED);
double startX = 300;
double startY = 100;
double endX = startX + length * Math.cos(angle);
double endY = startY + length * Math.sin(angle);
double end2X;
double end2Y;
double dblAngle;
double angle2;
int intAngle2;
double start2X = endX;
double start2Y = endY;
intAngle2 = 180 - intAngle;
angle2 = intAngle2;
angle2 = (angle2 * Math.PI / 180);
end2X = (start2X - length * Math.cos(angle2));
end2Y = (start2Y - length * Math.sin(angle2));
int intEndX = (int)endX;
int intEndY = (int)endY;
if(blnButton == true){
graphics.draw(new Line2D.Double(startX, startY, endX, endY));
graphics.draw(new Line2D.Double(start2X, start2Y, end2X, end2Y));
}
可能有更简单的方法,但基本上,您可以根据角度和角度的倒数(角度 - 360)计算圆上的两个点
例如,对于半径为 150 的圆,这将为您提供 300 的直线
红线是从圆心到给定天使所代表的圆上的点的线。蓝色是相反的。每行是 150 像素的行,也就是说,它们的长度是 300 像素。
这个例子是分开画的,但实际上,它们可以画成一条线
import java.awt.BorderLayout;
import java.awt.Color;
import java.awt.Dimension;
import java.awt.EventQueue;
import java.awt.Graphics;
import java.awt.Graphics2D;
import java.awt.geom.Ellipse2D;
import java.awt.geom.Line2D;
import javax.swing.JFrame;
import javax.swing.JPanel;
import javax.swing.JSlider;
import javax.swing.UIManager;
import javax.swing.UnsupportedLookAndFeelException;
import javax.swing.event.ChangeEvent;
import javax.swing.event.ChangeListener;
public class Test {
public static void main(String[] args) {
new Test();
}
public Test() {
EventQueue.invokeLater(new Runnable() {
@Override
public void run() {
try {
UIManager.setLookAndFeel(UIManager.getSystemLookAndFeelClassName());
} catch (ClassNotFoundException | InstantiationException | IllegalAccessException | UnsupportedLookAndFeelException ex) {
ex.printStackTrace();
}
JFrame frame = new JFrame("Testing");
frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
frame.add(new TestPane());
frame.pack();
frame.setLocationRelativeTo(null);
frame.setVisible(true);
}
});
}
public class TestPane extends JPanel {
public TestPane() {
setLayout(new BorderLayout());
DrawPane drawPane = new DrawPane();
add(drawPane);
JSlider slider = new JSlider(0, 100);
add(slider, BorderLayout.SOUTH);
slider.addChangeListener(new ChangeListener() {
@Override
public void stateChanged(ChangeEvent e) {
drawPane.setAngleInDegrees(360d * (slider.getValue() / 100d));
}
});
slider.setValue(0);
}
}
public class DrawPane extends JPanel {
private double angle;
@Override
public Dimension getPreferredSize() {
return new Dimension(400, 400);
}
@Override
protected void paintComponent(Graphics g) {
super.paintComponent(g);
Graphics2D g2d = (Graphics2D) g.create();
// Radius of the circle
double r = 150;
// Degrees to radians...
double radians = Math.toRadians(angle);
// The end point on the circle...
int endX = (int) Math.round(r * Math.cos(radians));
int endY = (int) Math.round(r * Math.sin(radians));
// The start point on the circle, 360 degress from the
// start angle
radians = Math.toRadians(angle - 360);
int startX = (int) Math.round(r * Math.cos(radians));
int startY = (int) Math.round(r * Math.sin(radians));
// Offset for the ellipse (center of the screen)
double x = (getWidth() / 2d) - r;
double y = (getWidth() / 2d) - r;
g2d.setColor(Color.LIGHT_GRAY);
g2d.draw(new Ellipse2D.Double(x, y, r * 2, r * 2));
// Center of the circle...
x = (getWidth() / 2d);
y = (getWidth() / 2d);
// One single line
//g2d.setColor(Color.BLACK);
//g2d.draw(new Line2D.Double(x - startX, y - startY, x + endX, y + endY));
g2d.setColor(Color.RED);
g2d.draw(new Line2D.Double(x, y, x - startX, y - startY));
g2d.setColor(Color.BLUE);
g2d.draw(new Line2D.Double(x, y, x + endX, y + endY));
g2d.dispose();
}
public void setAngleInDegrees(double value) {
if (angle != value) {
angle = Math.min(Math.max(value, 0), 360);
repaint();
}
}
}
}
或类似的东西...
我根据滑块画了一条斜线。
我正在尝试使线的末端 Y 坐标为某个数字(假设为 300),即使它是一个角度。
关于如何做到这一点有什么想法吗?到目前为止,这是我的生产线上的工作:
double angle = intAngle;
angle = angle * Math.PI / 180;
double length = 300;
graphics.setColor(Color.RED);
double startX = 300;
double startY = 100;
double endX = startX + length * Math.cos(angle);
double endY = startY + length * Math.sin(angle);
double end2X;
double end2Y;
double dblAngle;
double angle2;
int intAngle2;
double start2X = endX;
double start2Y = endY;
intAngle2 = 180 - intAngle;
angle2 = intAngle2;
angle2 = (angle2 * Math.PI / 180);
end2X = (start2X - length * Math.cos(angle2));
end2Y = (start2Y - length * Math.sin(angle2));
int intEndX = (int)endX;
int intEndY = (int)endY;
if(blnButton == true){
graphics.draw(new Line2D.Double(startX, startY, endX, endY));
graphics.draw(new Line2D.Double(start2X, start2Y, end2X, end2Y));
}
可能有更简单的方法,但基本上,您可以根据角度和角度的倒数(角度 - 360)计算圆上的两个点
例如,对于半径为 150 的圆,这将为您提供 300 的直线
红线是从圆心到给定天使所代表的圆上的点的线。蓝色是相反的。每行是 150 像素的行,也就是说,它们的长度是 300 像素。
这个例子是分开画的,但实际上,它们可以画成一条线
import java.awt.BorderLayout;
import java.awt.Color;
import java.awt.Dimension;
import java.awt.EventQueue;
import java.awt.Graphics;
import java.awt.Graphics2D;
import java.awt.geom.Ellipse2D;
import java.awt.geom.Line2D;
import javax.swing.JFrame;
import javax.swing.JPanel;
import javax.swing.JSlider;
import javax.swing.UIManager;
import javax.swing.UnsupportedLookAndFeelException;
import javax.swing.event.ChangeEvent;
import javax.swing.event.ChangeListener;
public class Test {
public static void main(String[] args) {
new Test();
}
public Test() {
EventQueue.invokeLater(new Runnable() {
@Override
public void run() {
try {
UIManager.setLookAndFeel(UIManager.getSystemLookAndFeelClassName());
} catch (ClassNotFoundException | InstantiationException | IllegalAccessException | UnsupportedLookAndFeelException ex) {
ex.printStackTrace();
}
JFrame frame = new JFrame("Testing");
frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
frame.add(new TestPane());
frame.pack();
frame.setLocationRelativeTo(null);
frame.setVisible(true);
}
});
}
public class TestPane extends JPanel {
public TestPane() {
setLayout(new BorderLayout());
DrawPane drawPane = new DrawPane();
add(drawPane);
JSlider slider = new JSlider(0, 100);
add(slider, BorderLayout.SOUTH);
slider.addChangeListener(new ChangeListener() {
@Override
public void stateChanged(ChangeEvent e) {
drawPane.setAngleInDegrees(360d * (slider.getValue() / 100d));
}
});
slider.setValue(0);
}
}
public class DrawPane extends JPanel {
private double angle;
@Override
public Dimension getPreferredSize() {
return new Dimension(400, 400);
}
@Override
protected void paintComponent(Graphics g) {
super.paintComponent(g);
Graphics2D g2d = (Graphics2D) g.create();
// Radius of the circle
double r = 150;
// Degrees to radians...
double radians = Math.toRadians(angle);
// The end point on the circle...
int endX = (int) Math.round(r * Math.cos(radians));
int endY = (int) Math.round(r * Math.sin(radians));
// The start point on the circle, 360 degress from the
// start angle
radians = Math.toRadians(angle - 360);
int startX = (int) Math.round(r * Math.cos(radians));
int startY = (int) Math.round(r * Math.sin(radians));
// Offset for the ellipse (center of the screen)
double x = (getWidth() / 2d) - r;
double y = (getWidth() / 2d) - r;
g2d.setColor(Color.LIGHT_GRAY);
g2d.draw(new Ellipse2D.Double(x, y, r * 2, r * 2));
// Center of the circle...
x = (getWidth() / 2d);
y = (getWidth() / 2d);
// One single line
//g2d.setColor(Color.BLACK);
//g2d.draw(new Line2D.Double(x - startX, y - startY, x + endX, y + endY));
g2d.setColor(Color.RED);
g2d.draw(new Line2D.Double(x, y, x - startX, y - startY));
g2d.setColor(Color.BLUE);
g2d.draw(new Line2D.Double(x, y, x + endX, y + endY));
g2d.dispose();
}
public void setAngleInDegrees(double value) {
if (angle != value) {
angle = Math.min(Math.max(value, 0), 360);
repaint();
}
}
}
}
或类似的东西...