模拟 NETWORKDAYS returns 个错误的工作日

Question

我基于在 sql 上创建了一个类似 NETWORKDAYS 的函数，在记录（BEG 和 END） 开启时 returns 正确的工作日工作日.

BEG        END         businessd
--------------------------------
01/01/2018 15/01/2018  10       

--(15 days total)-(1st jan)-(4 weekends) = 10 | correct result

但在某些情况下，如果 BEG 或 END 在周末 "stored"，则计算额外的天数：

BEG        END         businessd
--------------------------------
01/01/2018 28/01/2018  20       

--(28 days total)-(1st jan)-(4 weekends) = 19 | incorrect result

我的代码在 BEG 和 FIN 之间执行 datediff 并减去存储在 holydays table[=19= 中的周末和节日]

    SELECT e.*, 
            DATEDIFF(DAY, cast(BEG as datetime), cast(FIN as datetime))+1 --sum end date day
              -(SELECT
               (DATEDIFF(WK, cast(BEG as datetime), cast(FIN as datetime)) )
              +(CASE WHEN DATENAME(dw, cast(BEG as datetime)) = 'Sunday' THEN 1 ELSE 0 END)
              +(CASE WHEN DATENAME(dw, cast(FIN as datetime)) = 'Saturday' THEN 1 ELSE 0 END)
            ) * 2
            -(SELECT COUNT(*) FROM holydays nl
             WHERE nl.FECHA BETWEEN cast(BEG as datetime) AND cast(FIN as datetime)
            ) AS businessd,

            convert(nvarchar(6),cast(BEG as datetime),112) as iddate --new id based on fin
    FROM e
    ORDER BY original_ini,BEG

我如何处理这些情况才能正确计算工作日？

Answer 1

您可以为此使用日历 table。有了它这个操作会很轻松

您甚至可以应对银行假日

Check This and this (Calendar Table)

select * from calendar where isWorkDay = 1

会给你工作日，然后你可以像

一样进行简单的加入

select * from t
where exists 
( select 1 from calendar where isWorkDay = 1 and calendar.dt betweenn t.beg and t.end)

模拟 NETWORKDAYS returns 个错误的工作日

Simulating NETWORKDAYS returns wrong business days

sql

sql-server-2008

datediff