连接来自旋转 mysql 的结果值

Question

我试图在旋转后获得一个连接的字符串值。

目前，只有一个值并且工作正常。

查询如下：

DROP PROCEDURE IF EXISTS getAllUserLunchReport;
DELIMITER $$
CREATE DEFINER=`root`@`localhost` PROCEDURE `getAllUserLunchReport`(IN `start_date` DATETIME, IN `end_date` DATETIME)
BEGIN

SET GLOBAL group_concat_max_len=4294967295;
SET @SQL = NULL;
SET @start_date = DATE(start_date);
SET @end_date = DATE(end_date);

    SELECT
    COALESCE(GROUP_CONCAT(DISTINCT
    CONCAT(
    'SUM(CASE WHEN date = "',DATE(issuedDateTime),'" AND lunchStatus = 1 THEN (SELECT CONCAT((SELECT rate FROM lunch_rate WHERE DATE(created_on) <= date ORDER BY created_on DESC LIMIT 1), "," ,(SELECT rate FROM lunch_gbd_rate WHERE DATE(created_on) <= date ORDER BY created_on DESC LIMIT 1))) ELSE 0 END) AS `',DATE(issuedDateTime),'`'
    ) ORDER BY issuedDateTime
), '0 as `NoMatchingRows`') INTO @SQL

        FROM `lunch_status` 
        WHERE DATE(issuedDateTime) BETWEEN @start_date AND @end_date;

    SET @SQL 
    = CONCAT
    (
    '
        SELECT concat(u.firstname," ",u.lastname) as Employee, w.*
        FROM users u
        INNER JOIN
        (SELECT userId, ', @SQL, ' 
        FROM
        (
            SELECT userId, lunchStatus, DATE(issuedDateTime) as date 
            FROM `lunch_status` 
            WHERE DATE(issuedDateTime) BETWEEN "',@start_date,'" AND "',@end_date,'" 
        ) as a
        GROUP BY userId) w
        ON u.id = w.userId
        ORDER BY Employee;
    '
    );

PREPARE stmt FROM @SQL;
EXECUTE stmt;
DEALLOCATE PREPARE stmt;


END$$
DELIMITER ;

我只得到第一个值，没有我试图连接的其他值。

这是我预期的结果：

employee    |   2019-1-15  |  2019-1-16
----------------------------------------
Jack        |   30,140     |  30,140

虽然单独执行串联查询是可行的。

注意：在上面的存储过程中，如果分隔符被移除，值将被连接起来。 CONCAT((select ...), (select...)) 给出 30140.

会不会是quotes的问题，我已经试过了

仅供参考，这是 @SQL 第一次查询后的结果：

SUM(CASE WHEN date = "2019-01-15" AND lunchStatus = 1 THEN (SELECT CONCAT((SELECT rate FROM lunch_rate WHERE DATE(created_on) <= date ORDER BY created_on DESC LIMIT 1), ",", (SELECT rate FROM lunch_gbd_rate WHERE DATE(created_on) <= date ORDER BY created_on DESC LIMIT 1))) ELSE 0 END) AS `2019-01-15`,
SUM(CASE WHEN date = "2019-01-16" AND lunchStatus = 1 THEN (SELECT CONCAT((SELECT rate FROM lunch_rate WHERE DATE(created_on) <= date ORDER BY created_on DESC LIMIT 1), ",", (SELECT rate FROM lunch_gbd_rate WHERE DATE(created_on) <= date ORDER BY created_on DESC LIMIT 1))) ELSE 0 END) AS `2019-01-16`

看起来有效。

编辑：它似乎在 "integer" 值下工作正常。例如

CONCAT((SELECT rate FROM lunch_rate WHERE DATE(created_on) <= date ORDER BY created_on DESC LIMIT 1), "111" ,(SELECT rate FROM lunch_gbd_rate WHERE DATE(created_on) <= date ORDER BY created_on DESC LIMIT 1))

给出 301140.

但是对于其他字符,/./-/_，只显示第一个参数：30.

Answer 1

当您在 CONCAT 中包含 , 时，您的代码不起作用的原因是因为 CONCAT 在 SUM 中，它赢了' 能够将 30,140 解释为一个数字，它可以将 30140 解释为一个数字（因此没有分隔符你会得到一个结果）。在不知道 table 数据的更多细节和期望的结果的情况下，很难准确地说出如何解决问题，但也许您想要这样的东西：

CASE WHEN date = "2019-01-15" AND lunchStatus = 1 THEN CONCAT((SELECT SUM(rate) FROM lunch_rate WHERE DATE(created_on) <= date ORDER BY created_on DESC LIMIT 1), ",", (SELECT SUM(rate) FROM lunch_gbd_rate WHERE DATE(created_on) <= date ORDER BY created_on DESC LIMIT 1)) ELSE 0 END) AS `2019-01-15`

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