根据总数获取当前状态
Get Current Status based on Total Count
我在 mysql 查询中设置条件(if then else)时遇到问题。
简而言之,我有 3 个相互关联的表。
m_shift_schedule site_shift_schedule m_ticket
================ =================== ============
* shift_id ======> * shift_id * ticket_id
* start_time * shift_date * ticket_status
* end_time * user_id ========> * ticket_served_by
我现在的查询:
SELECT user_id
FROM site_shift_schedule
LEFT JOIN m_shift_schedule ON site_shift_schedule.shift_id = m_shift_schedule.shift_id
WHERE site_shift_schedule.shift_date = '2019-02-11';
如果我想让输出变成这样,我该怎么办?
空闲 = m_ticket.ticket_status(4 或 5 或 6)和总计数 m_ticket.ticket_served_by < 2
忙 = m_ticket.ticket_status(4 或 5 或 6)和总数 m_ticket.ticket_served_by = 2
过载 = m_ticket.ticket_status(4 或 5 或 6)和总数 m_ticket.ticket_served_by > 2
user_id Status
============================= ============
ismail.rahman.saanin@random.co Idle
lutfi.aldi.nugroho@random.co Busy
帮帮我,谢谢。 . .
您可以尝试使用 CASE WHEN Expression
和 Group By
SELECT user_id,
case when count(m_ticket.ticket_served_by)<2 then 'idle'
when count(m_ticket.ticket_served_by)=2 then 'Busy'
when count(m_ticket.ticket_served_by)>2 then 'Overload' end as status
FROM site_shift_schedule
LEFT JOIN m_shift_schedule ON site_shift_schedule.shift_id = m_shift_schedule.shift_id
left join m_ticket on site_shift_schedule.user_id=m_ticket.ticket_served_by
WHERE site_shift_schedule.shift_date = '2019-02-11' and m_ticket.ticket_status in (4,5,6)
group by user_id
我在 mysql 查询中设置条件(if then else)时遇到问题。
简而言之,我有 3 个相互关联的表。
m_shift_schedule site_shift_schedule m_ticket
================ =================== ============
* shift_id ======> * shift_id * ticket_id
* start_time * shift_date * ticket_status
* end_time * user_id ========> * ticket_served_by
我现在的查询:
SELECT user_id
FROM site_shift_schedule
LEFT JOIN m_shift_schedule ON site_shift_schedule.shift_id = m_shift_schedule.shift_id
WHERE site_shift_schedule.shift_date = '2019-02-11';
如果我想让输出变成这样,我该怎么办?
空闲 = m_ticket.ticket_status(4 或 5 或 6)和总计数 m_ticket.ticket_served_by < 2
忙 = m_ticket.ticket_status(4 或 5 或 6)和总数 m_ticket.ticket_served_by = 2
过载 = m_ticket.ticket_status(4 或 5 或 6)和总数 m_ticket.ticket_served_by > 2
user_id Status
============================= ============
ismail.rahman.saanin@random.co Idle
lutfi.aldi.nugroho@random.co Busy
帮帮我,谢谢。 . .
您可以尝试使用 CASE WHEN Expression
和 Group By
SELECT user_id,
case when count(m_ticket.ticket_served_by)<2 then 'idle'
when count(m_ticket.ticket_served_by)=2 then 'Busy'
when count(m_ticket.ticket_served_by)>2 then 'Overload' end as status
FROM site_shift_schedule
LEFT JOIN m_shift_schedule ON site_shift_schedule.shift_id = m_shift_schedule.shift_id
left join m_ticket on site_shift_schedule.user_id=m_ticket.ticket_served_by
WHERE site_shift_schedule.shift_date = '2019-02-11' and m_ticket.ticket_status in (4,5,6)
group by user_id