Scrapy > IndexError: list index out of range

Scrapy > IndexError: list index out of range

我正在尝试抓取 TripAdvisor 的一些数据。 我有兴趣了解餐厅的“价格范围/菜肴和膳食”。

所以我使用以下 xpath 将这 3 行中的每一行都提取到同一个 class 中:

response.xpath('//div[@class="restaurants-detail-overview-cards-DetailsSectionOverviewCard__categoryTitle--14zKt"]/text()').extract()[1]

我直接在 scrapy 中进行测试 shell 并且工作正常 :

scrapy shell https://www.tripadvisor.com/Restaurant_Review-g187514-d15364769-Reviews-La_Gaditana_Castellana-Madrid.html

但是当我将它集成到我的脚本中时,出现以下错误:

    Traceback (most recent call last):
  File "/usr/lib64/python3.6/site-packages/scrapy/utils/defer.py", line 102, in iter_errback
    yield next(it)
  File "/usr/lib64/python3.6/site-packages/scrapy/spidermiddlewares/offsite.py", line 29, in process_spider_output
    for x in result:
  File "/usr/lib64/python3.6/site-packages/scrapy/spidermiddlewares/referer.py", line 339, in <genexpr>
    return (_set_referer(r) for r in result or ())
  File "/usr/lib64/python3.6/site-packages/scrapy/spidermiddlewares/urllength.py", line 37, in <genexpr>
    return (r for r in result or () if _filter(r))
  File "/usr/lib64/python3.6/site-packages/scrapy/spidermiddlewares/depth.py", line 58, in <genexpr>
    return (r for r in result or () if _filter(r))
  File "/root/Scrapy_TripAdvisor_Restaurant-master/tripadvisor_las_vegas/tripadvisor_las_vegas/spiders/res_las_vegas.py", line 64, in parse_listing
    (response.xpath('//div[@class="restaurants-details-card-TagCategories__categoryTitle--o3o2I"]/text()')[1])
  File "/usr/lib/python3.6/site-packages/parsel/selector.py", line 61, in __getitem__
    o = super(SelectorList, self).__getitem__(pos)
IndexError: list index out of range

我把我的部分代码贴给你,我在下面解释:

# extract restaurant cuisine
    row_cuisine_overviewcard = \
    (response.xpath('//div[@class="restaurants-detail-overview-cards-DetailsSectionOverviewCard__categoryTitle--14zKt"]/text()')[1])
    row_cuisine_card = \
    (response.xpath('//div[@class="restaurants-details-card-TagCategories__categoryTitle--o3o2I"]/text()')[1])
    
    
    if (row_cuisine_overviewcard == "CUISINES"):
        cuisine = \
        response.xpath('//div[@class="restaurants-detail-overview-cards-DetailsSectionOverviewCard__tagText--1XLfi"]/text()')[1]
    elif (row_cuisine_card == "CUISINES"):
        cuisine = \
        response.xpath('//div[@class="restaurants-details-card-TagCategories__tagText--2170b"]/text()')[1]
    else:
        cuisine = None

在 tripAdvisor 餐厅中,有 2 种不同类型的页面,有 2 种不同的格式。 第一个带有 class 概览卡片,第二个带有 class 个卡片

所以我想检查第一个是否存在(overviewcard),如果不存在,则执行第二个(card),如果不存在,则输入“None”值。

:D 但是看起来 Python 都执行了....并且由于页面中不存在第二个,脚本停止。

会不会是缩进错误?

感谢您的帮助 此致

您的第二个选择器 (row_cuisine_card) 失败,因为页面上不存在该元素。当您随后尝试访问结果中的 [1] 时,它会抛出错误,因为结果数组为空。

假设您真的想要商品 1,试试这个

row_cuisine_overviewcard = \
(response.xpath('//div[@class="restaurants-detail-overview-cards-DetailsSectionOverviewCard__categoryTitle--14zKt"]/text()')[1])
# Here we get all the values, even if it is empty.
row_cuisine_card = \
(response.xpath('//div[@class="restaurants-details-card-TagCategories__categoryTitle--o3o2I"]/text()').getall()) 


if (row_cuisine_overviewcard == "CUISINES"):
    cuisine = \
    response.xpath('//div[@class="restaurants-detail-overview-cards-DetailsSectionOverviewCard__tagText--1XLfi"]/text()')[1]
# Here we check first if that result has more than 1 item, and then we check the value.
elif (len(row_cuisine_card) > 1 and row_cuisine_card[1] == "CUISINES"):
    cuisine = \
    response.xpath('//div[@class="restaurants-details-card-TagCategories__tagText--2170b"]/text()')[1]
else:
    cuisine = None

每当您尝试从选择器获取特定索引时,您都应该应用相同类型的安全检查。换句话说,在访问它之前确保你有一个值。

你的问题已经在你检查这一行了_

row_cuisine_card = \
    (response.xpath('//div[@class="restaurants-details-card-TagCategories__categoryTitle--o3o2I"]/text()')[1])

您正试图从网站中提取可能不存在的值。也就是说,如果

response.xpath('//div[@class="restaurants-details-card-TagCategories__categoryTitle--o3o2I"]/text()')

returns 没有或只有一个元素,则您无法访问返回列表中的第二个元素(您希望使用附加的 [1] 访问)。

我建议先将您从网站中提取的值存储到局部变量中,以便随后检查是否找到了您想要的值。我的猜测是它中断的页面没有你想要的信息。

这大概类似于以下代码:

# extract restaurant cuisine
cuisine = None
cuisine_overviewcard_sections = response.xpath('//div[@class="restaurants-detail-overview-cards-DetailsSectionOverviewCard__categoryTitle--14zKt"]/text()'
if len(cuisine_overviewcard_sections) >= 2:
    row_cuisine_overviewcard = cuisine_overviewcard_sections[1]
    cuisine_card_sections = response.xpath('//div[@class="restaurants-details-card-TagCategories__categoryTitle--o3o2I"]/text()'
    if len(cuisine_card_sections) >= 2:
        row_cuisine_card = cuisine_card_sections[1]
        if (row_cuisine_overviewcard == "CUISINES"):
            cuisine = \
            response.xpath('//div[@class="restaurants-detail-overview-cards-DetailsSectionOverviewCard__tagText--1XLfi"]/text()')[1]
        elif (row_cuisine_card == "CUISINES"):
            cuisine = \
            response.xpath('//div[@class="restaurants-details-card-TagCategories__tagText--2170b"]/text()')[1]

由于只需要一部分信息,如果第一个XPath检查已经returns正确答案,代码可以美化一下:

# extract restaurant cuisine
cuisine = None
cuisine_overviewcard_sections = response.xpath('//div[@class="restaurants-detail-overview-cards-DetailsSectionOverviewCard__categoryTitle--14zKt"]/text()'
if len(cuisine_overviewcard_sections) >= 2 and cuisine_overviewcard_sections[1] == "CUISINES":
    cuisine = \
            response.xpath('//div[@class="restaurants-detail-overview-cards-DetailsSectionOverviewCard__tagText--1XLfi"]/text()')[1]
else:
    cuisine_card_sections = response.xpath('//div[@class="restaurants-details-card-TagCategories__categoryTitle--o3o2I"]/text()'
    if len(cuisine_card_sections) >= 2 and cuisine_card_sections[1] == "CUISINES":
        cuisine = \
            response.xpath('//div[@class="restaurants-details-card-TagCategories__tagText--2170b"]/text()')[1]

这样您只在实际需要时才进行(可能很昂贵的)XPath 搜索。