使用 SSDT 创建图表以显示始终有多少工作 运行
Creating a chart with SSDT to show how many jobs are running at all times
我正在尝试绘制一个 chart/graph 来显示一天中任何给定时间有多少工作 运行，当工作开始时很容易，但想法是它应该显示它需要多长时间。
我有一个贯穿所有作业的查询，获取它们的开始时间、持续时间，如果需要的话，我已经计算了结束时间，但我似乎无法将其显示在人们的屏幕上能够去，哦，是的，这里有 5 个长期 运行 工作，none 这里。
大多数工作几乎不需要时间，但我们确实有一些工作需要几分钟，还有一些需要一夜之间完成，可能需要一个多小时。
我用来获取信息的基本代码：
WITH CTE as(
select run_duration
,cast(concat(cast(run_date as varchar(8)),' ',substring(right('00000'+cast(run_time as varchar(8)),6),1,2),':',
substring(right('000'+cast(run_time as varchar(6)),4),1,2),':',
substring(right(run_time,2),1,2))as datetime) as [starttime]
FROM msdb.dbo.sysjobhistory WITH (NOLOCK)
WHERE run_duration >0
)
SELECT 1 as [running],run_duration,starttime,DATEADD(ss,run_duration,[starttime]) AS [endTime]
FROM CTE
WHERE [starttime] > (GETUTCDATE() - 1)
ORDER BY [starttime] DESC
任何关于我应该如何处理的帮助/线索将不胜感激（如果需要，可以创建一个单独的管理员 table。
已将 link 附加到图像中，这是我所追求的一个非常粗略的想法
http://stephen-bov.co.uk/images/JobsRunning.png
谢谢
Ste
* 请参阅其他最终实施答案 *
设法让它工作，
它有点乱，但如果有人在
，这里是代码
WITH CTE AS(
SELECT run_duration, instance_ID
--,msdb.dbo.agent_datetime(run_date,run_time) as startingtime
,cast(concat(cast(run_date as varchar(8)),' ',substring(right('00000'+cast(run_time as varchar(8)),6),1,2),':',
substring(right('000'+cast(run_time as varchar(6)),4),1,2),':',
substring(right(run_time,2),1,2))as datetime) as [startingtime]
FROM msdb.dbo.sysjobhistory WITH (NOLOCK)
WHERE run_duration >0
), Pri AS
(
SELECT 1 as running,run_duration, instance_ID, startingtime
FROM CTE
WHERE [startingtime] > (GETUTCDATE() - 1)
)
SELECT distinct(p1.startingtime), count(p1.running) AS [running] FROM Pri p1
LEFT JOIN PRI p2 ON
p1.startingtime between p2.startingtime and DATEADD(ss,p2.run_duration,p2.[startingtime])
GROUP BY p1.startingtime,p1.instance_id
order by startingtime
我只关注了至少需要一秒钟才能完成的作业 运行（否则真的很乱。
当工作结束时，仍有工作要做以刷新列表，但有工作运行现在足够频繁以获得粗略视图，
新的代码改进，现在考虑了仍然是 运行 的工作，以及仍然是 运行 但在 date-1 之前开始的工作
（也运行得更快）
IF OBJECT_ID('tempdb..#jobtimes') IS NOT NULL
DROP TABLE #jobtimes
IF OBJECT_ID('tempdb..#jobhis') IS NOT NULL
DROP TABLE #jobhis
SELECT instance_ID
,(substring(right('00000'+cast(run_duration as varchar(8)),6),1,2)*60*60) +
(substring(right('000'+cast(run_duration as varchar(6)),4),1,2)*60) +
substring(right(run_duration,2),1,2)
as run_duration
,cast(concat(cast(run_date as varchar(8)),' ',substring(right('00000'+cast(run_time as varchar(8)),6),1,2),':',
substring(right('000'+cast(run_time as varchar(6)),4),1,2),':',
substring(right(run_time,2),1,2))as datetime) as [startingtime]
INTO #jobhis
FROM msdb.dbo.sysjobhistory WITH (NOLOCK)
WHERE
run_duration >0 and
step_id = 0 and
cast(run_date as varchar(8)) > (GETDATE() - 2 )
UNION
SELECT 1,datediff(second,start_execution_date,GETdate()),start_execution_date
FROM msdb.dbo.sysjobactivity with(nolock)
WHERE run_requested_date is not null
and stop_execution_date is null
and start_execution_date > GETUTCDATE()-2
SELECT 1 as running,run_duration, instance_ID, startingtime, dateadd(ms,-10,DATEADD(ss,run_duration,startingtime)) as endtime
into #jobtimes
FROM #jobhis
WHERE dateadd(ms,-10,DATEADD(ss,run_duration,startingtime)) > (GETDATE() -1)
UNION
SELECT NULL as running ,0 as run_duration, 0 as instance_ID, DATEADD(ss,run_duration,startingtime) as startingtime, NULL as endtime
FROM #jobhis
WHERE [startingtime] > (GETDATE() - 1 )
SELECT p1.startingtime,count(p2.running) as instances
FROM #jobtimes p1
LEFT JOIN #jobtimes p2 ON
p2.running =1
AND p1.startingtime between p2.startingtime and p2.endtime
WHERE p1.startingtime > (getdate()-1)
GROUP BY p1.startingtime,p1.run_duration
DROP TABLE #jobtimes
DROP TABLE #jobhis
旧答案供参考
更新能够检测每个作业的结束，因此一旦所有作业都完成，图形将下降到 0，或者只是下降到一个完成后还剩下多少，
我们每天有 27k 个作业 运行 至少需要一秒钟 运行 直接在管理工作室中进行查询大约需要一分半钟，运行 在 SSDT 中它用时不到 10 秒（不知道它是否缓存了很多信息）
WITH CTE AS(
SELECT instance_ID
,(substring(right('00000'+cast(run_duration as varchar(8)),6),1,2)*60*60) +
(substring(right('000'+cast(run_duration as varchar(6)),4),1,2)*60) +
substring(right(run_duration,2),1,2)
as run_duration
--,msdb.dbo.agent_datetime(run_date,run_time) as startingtime
,cast(concat(cast(run_date as varchar(8)),' ',substring(right('00000'+cast(run_time as varchar(8)),6),1,2),':',
substring(right('000'+cast(run_time as varchar(6)),4),1,2),':',
substring(right(run_time,2),1,2))as datetime) as [startingtime]
FROM msdb.dbo.sysjobhistory WITH (NOLOCK)
WHERE run_duration >0 and cast(run_date as varchar(8)) > (GETUTCDATE() - 2 )
), Pri AS
(
SELECT 1 as running,run_duration, instance_ID, startingtime, dateadd(ms,-10,DATEADD(ss,run_duration,startingtime)) as endtime
FROM CTE
WHERE [startingtime] > (GETUTCDATE() - 1 )
UNION
SELECT NULL as running ,0 as run_duration, 0 as instance_ID, DATEADD(ss,run_duration,startingtime) as startingtime, NULL as endtime
FROM CTE
WHERE [startingtime] > (GETUTCDATE() - 1 )
)
SELECT p1.startingtime,count(p2.running) as instances FROM Pri p1
LEFT JOIN Pri p2 ON
p2.running =1 AND p1.startingtime between p2.startingtime and p2.endtime
GROUP BY p1.startingtime,p1.run_duration
order by startingtime
希望其他任何想看这篇文章的人都会觉得有用
Ste
我正在尝试绘制一个 chart/graph 来显示一天中任何给定时间有多少工作 运行，当工作开始时很容易，但想法是它应该显示它需要多长时间。
我有一个贯穿所有作业的查询，获取它们的开始时间、持续时间，如果需要的话，我已经计算了结束时间，但我似乎无法将其显示在人们的屏幕上能够去，哦，是的，这里有 5 个长期 运行 工作，none 这里。
大多数工作几乎不需要时间，但我们确实有一些工作需要几分钟，还有一些需要一夜之间完成，可能需要一个多小时。
我用来获取信息的基本代码：
WITH CTE as(
select run_duration
,cast(concat(cast(run_date as varchar(8)),' ',substring(right('00000'+cast(run_time as varchar(8)),6),1,2),':',
substring(right('000'+cast(run_time as varchar(6)),4),1,2),':',
substring(right(run_time,2),1,2))as datetime) as [starttime]
FROM msdb.dbo.sysjobhistory WITH (NOLOCK)
WHERE run_duration >0
)
SELECT 1 as [running],run_duration,starttime,DATEADD(ss,run_duration,[starttime]) AS [endTime]
FROM CTE
WHERE [starttime] > (GETUTCDATE() - 1)
ORDER BY [starttime] DESC
任何关于我应该如何处理的帮助/线索将不胜感激（如果需要，可以创建一个单独的管理员 table。
已将 link 附加到图像中，这是我所追求的一个非常粗略的想法 http://stephen-bov.co.uk/images/JobsRunning.png
谢谢 Ste
* 请参阅其他最终实施答案 * 设法让它工作， 它有点乱，但如果有人在
，这里是代码WITH CTE AS(
SELECT run_duration, instance_ID
--,msdb.dbo.agent_datetime(run_date,run_time) as startingtime
,cast(concat(cast(run_date as varchar(8)),' ',substring(right('00000'+cast(run_time as varchar(8)),6),1,2),':',
substring(right('000'+cast(run_time as varchar(6)),4),1,2),':',
substring(right(run_time,2),1,2))as datetime) as [startingtime]
FROM msdb.dbo.sysjobhistory WITH (NOLOCK)
WHERE run_duration >0
), Pri AS
(
SELECT 1 as running,run_duration, instance_ID, startingtime
FROM CTE
WHERE [startingtime] > (GETUTCDATE() - 1)
)
SELECT distinct(p1.startingtime), count(p1.running) AS [running] FROM Pri p1
LEFT JOIN PRI p2 ON
p1.startingtime between p2.startingtime and DATEADD(ss,p2.run_duration,p2.[startingtime])
GROUP BY p1.startingtime,p1.instance_id
order by startingtime
我只关注了至少需要一秒钟才能完成的作业 运行（否则真的很乱。
当工作结束时，仍有工作要做以刷新列表，但有工作运行现在足够频繁以获得粗略视图，
新的代码改进，现在考虑了仍然是 运行 的工作，以及仍然是 运行 但在 date-1 之前开始的工作 （也运行得更快）
IF OBJECT_ID('tempdb..#jobtimes') IS NOT NULL
DROP TABLE #jobtimes
IF OBJECT_ID('tempdb..#jobhis') IS NOT NULL
DROP TABLE #jobhis
SELECT instance_ID
,(substring(right('00000'+cast(run_duration as varchar(8)),6),1,2)*60*60) +
(substring(right('000'+cast(run_duration as varchar(6)),4),1,2)*60) +
substring(right(run_duration,2),1,2)
as run_duration
,cast(concat(cast(run_date as varchar(8)),' ',substring(right('00000'+cast(run_time as varchar(8)),6),1,2),':',
substring(right('000'+cast(run_time as varchar(6)),4),1,2),':',
substring(right(run_time,2),1,2))as datetime) as [startingtime]
INTO #jobhis
FROM msdb.dbo.sysjobhistory WITH (NOLOCK)
WHERE
run_duration >0 and
step_id = 0 and
cast(run_date as varchar(8)) > (GETDATE() - 2 )
UNION
SELECT 1,datediff(second,start_execution_date,GETdate()),start_execution_date
FROM msdb.dbo.sysjobactivity with(nolock)
WHERE run_requested_date is not null
and stop_execution_date is null
and start_execution_date > GETUTCDATE()-2
SELECT 1 as running,run_duration, instance_ID, startingtime, dateadd(ms,-10,DATEADD(ss,run_duration,startingtime)) as endtime
into #jobtimes
FROM #jobhis
WHERE dateadd(ms,-10,DATEADD(ss,run_duration,startingtime)) > (GETDATE() -1)
UNION
SELECT NULL as running ,0 as run_duration, 0 as instance_ID, DATEADD(ss,run_duration,startingtime) as startingtime, NULL as endtime
FROM #jobhis
WHERE [startingtime] > (GETDATE() - 1 )
SELECT p1.startingtime,count(p2.running) as instances
FROM #jobtimes p1
LEFT JOIN #jobtimes p2 ON
p2.running =1
AND p1.startingtime between p2.startingtime and p2.endtime
WHERE p1.startingtime > (getdate()-1)
GROUP BY p1.startingtime,p1.run_duration
DROP TABLE #jobtimes
DROP TABLE #jobhis
旧答案供参考
更新能够检测每个作业的结束，因此一旦所有作业都完成，图形将下降到 0，或者只是下降到一个完成后还剩下多少，
我们每天有 27k 个作业 运行 至少需要一秒钟 运行 直接在管理工作室中进行查询大约需要一分半钟，运行 在 SSDT 中它用时不到 10 秒（不知道它是否缓存了很多信息）
WITH CTE AS(
SELECT instance_ID
,(substring(right('00000'+cast(run_duration as varchar(8)),6),1,2)*60*60) +
(substring(right('000'+cast(run_duration as varchar(6)),4),1,2)*60) +
substring(right(run_duration,2),1,2)
as run_duration
--,msdb.dbo.agent_datetime(run_date,run_time) as startingtime
,cast(concat(cast(run_date as varchar(8)),' ',substring(right('00000'+cast(run_time as varchar(8)),6),1,2),':',
substring(right('000'+cast(run_time as varchar(6)),4),1,2),':',
substring(right(run_time,2),1,2))as datetime) as [startingtime]
FROM msdb.dbo.sysjobhistory WITH (NOLOCK)
WHERE run_duration >0 and cast(run_date as varchar(8)) > (GETUTCDATE() - 2 )
), Pri AS
(
SELECT 1 as running,run_duration, instance_ID, startingtime, dateadd(ms,-10,DATEADD(ss,run_duration,startingtime)) as endtime
FROM CTE
WHERE [startingtime] > (GETUTCDATE() - 1 )
UNION
SELECT NULL as running ,0 as run_duration, 0 as instance_ID, DATEADD(ss,run_duration,startingtime) as startingtime, NULL as endtime
FROM CTE
WHERE [startingtime] > (GETUTCDATE() - 1 )
)
SELECT p1.startingtime,count(p2.running) as instances FROM Pri p1
LEFT JOIN Pri p2 ON
p2.running =1 AND p1.startingtime between p2.startingtime and p2.endtime
GROUP BY p1.startingtime,p1.run_duration
order by startingtime
希望其他任何想看这篇文章的人都会觉得有用
Ste