通过 Makefile 编译 2 个文件不起作用

Compile 2 files via Makefile doesn't work

我想一次编译两个.cpp 文件。 gstapp.cpp 正在编译,gnew.cpp 被忽略。我忽略了什么?

生成文件:

# generated from pkg-config --cflags gstreamer-0.10
CFLAGS=-pthread -I/usr/include/gstreamer-0.10 -I/usr/include/glib-2.0 -I/usr/lib/glib-2.0/include -I/usr/include/libxml2 

# generated from pkg-config --libs gstreamer-0.10
LDFLAGS=-lgstreamer-0.10 -lgobject-2.0 -lgmodule-2.0 -pthread -lgthread-2.0 -pthread -lglib-2.0 -lxml2 -lgstapp-0.10     

CFLAGS+=-I/usr/include/opencv2

# there are more, but not needed form now: -lopencv_calib3d -lopencv_contrib -lopencv_flann -lopencv_obj 
LDFLAGS+=-lstdc++ -lopencv_core -lopencv_features2d -lopencv_gpu -lopencv_highgui -lopencv_imgproc -lopencv_legacy -lopencv_ml -lopencv_nonfree -lopencv_video

gstapp: gstapp.o
    gcc $(LDFLAGS) -o $@ $<

gstapp.o: gstapp.cpp
    gcc -c $(CFLAGS) -o $@ $<

gnew: gnew.o
    gcc $(LDFLAGS) -o $@ $<

gnew.o: gnew.cpp
    gcc -c $(CFLAGS) -o $@ $<

您可能需要 all 规则来触发两者的编译。通过 运行ning make 不带参数,它将 运行 它遇到的第一个规则(例如 gstapp:)然后退出。

所以在 LDFLAGS 和 gstapp 行之间放

all: gstapp gnew

第一个(又名默认)规则将把你的两个文件作为依赖项,并在你 运行 makemake all.

时编译它们