MariaDB 比较两个表中的数字计数

Question

我正在尝试将 table 中一个值的总 COUNT 与另一个值的总 COUNT 进行比较，我只是不确定如何正确地进行比较.

如果 total_sales table 中的 SalesID 总数 COUNT 高于 total_leads 中的 fid 总数 COUNT table 然后我想输出这些值。

表格：

CREATE TABLE total_leads
    (`uid` int, `tstamp` int, `fid` int, `phone` varchar(2))
;

INSERT INTO total_leads
    (`uid`, `tstamp`, `fid`, `phone`)
VALUES
    (1, 1299795364, 1525, '""'),
    (1, 1309854563, 4031, '""'),
    (1, 1309854562, 3134, '""'),
    (5, 1280752536, 18, '""'),
    (5, 1280942244, 219, '""'),    
    (5, 1309862562, 1234, '""'),
    (5, 1480752536, 184, '""'),
    (5, 1520942244, 119, '""')
;

CREATE TABLE total_sales
    (`UserID` int, `SalesID` int, `Time` varchar(8))
;

INSERT INTO total_sales
    (`UserID`, `SalesID`, `Time`)
VALUES
    (1, 172, '12:57:43'),
    (1, 3563, '15:59:49'),
    (1, 9508, '01:46:47'),
    (5, 18935, '07:26:07'),
    (5, 19378, '08:06:41'),
    (1, 144, '11:52:41'),
    (1, 9248, '02:43:40'),
    (1, 3423, '14:54:45'),
    (5, 11935, '03:21:06'),
    (1, 1448, '05:02:24')
;

MySQL 命令：

SELECT x.uid, COUNT(*), COUNT(DISTINCT x.fid)
FROM total_leads AS x
WHERE x.uid BETWEEN 1 AND 5
GROUP BY x.uid;

SELECT ud.UserId, COUNT(*), COUNT(DISTINCT ud.SalesID)
FROM total_sales AS ud
WHERE ud.UserId BETWEEN 1 AND 5  
GROUP BY ud.UserID;

它returns (total_leads, total_sales):

 uid    COUNT(*)    COUNT(DISTINCT x.fid)
  1        3               3
  5        5               5

UserId  COUNT(*)    COUNT(DISTINCT ud.SalesID)
  1        7               7
  5        3               3

所以我希望得到如下结果：

UserId   Sales           Leads   Dif
  1        7               3      4

即使只知道哪个 UserID 有 Sales > fid 也完全没问题：

UserId  COUNT(*)    COUNT(DISTINCT ud.SalesID)
  1        7               7

Online Example.

我尝试了几种方法，例如 UNION，但只是将所有值合并在一起。

Answer 1

使用子查询连接

select uid,leadcount,salescount,salescount-leadcount as diff from 
(
SELECT x.uid, COUNT(*) leadcount, COUNT(DISTINCT x.fid)
FROM total_leads AS x
WHERE x.uid BETWEEN 1 AND 5
GROUP BY x.uid
) t1 left join 
(
SELECT ud.UserId, COUNT(*) salescount, COUNT(DISTINCT ud.SalesID)
FROM total_sales AS ud
WHERE ud.UserId BETWEEN 1 AND 5  
GROUP BY ud.UserID
) t2 on t1.uid=t2.UserId

Answer 2

试试这个代码，

 SELECT x.uid,COUNT(DISTINCT x.fid) AS leads,COUNT(DISTINCT ud.SalesID) AS 
 sales,((COUNT(DISTINCT ud.SalesID))-(COUNT(DISTINCT x.fid)))
 FROM
 total_leads AS X,total_sales AS ud WHERE x.uid=ud.UserId AND ud.UserId BETWEEN 1 AND 5 
 GROUP BY ud.UserID;

Answer 3

您可以使用以下方法来完成此操作，您可以在其中比较每个 table

的总计数

select t1.uid,t2.sales_count,t1.leads_count,
      case when t1.leads_count > t2.sales_count then t1.leads_count -t2.sales_count 
           else t2.sales_count -t1.leads_count
      end as diff
from 
(
select uid,count(fid) as leads_count
from total_leads
group by uid
)t1
inner join 
(
select UserID,count(SalesID)as sales_count
from total_sales
group by UserID
)t2 on t1.uid = t2.userid ;

MariaDB 比较两个表中的数字计数

MariaDB comparing number count from two tables

mysql

sql

mariadb

adminer