Python -> OpenCV -> 保存一张图像并结束程序

Question

我有一个 RaspberryPi 和几个 IP 摄像头，我想每 5 分钟从所有这些摄像头获取一张新图像。我有以下脚本，它打开 RTSP feed af 一直抓取图像，每秒运行 10-25。

有没有办法打开视频源并只拍摄 1 张图像？

import cv2
import time
cap = cv2.VideoCapture('rtsp://192.168.86.81:554/11') # it can be rtsp or http $

ret, frame = cap.read()
while ret:
    cv2.imwrite('images/{}.jpg'.format(time.time()), frame)
    ret, frame = cap.read()

Answer 1

这解决了我的问题。我删除了时间，因为我不需要这个。我会保留 aboce 代码以防有人想玩这个

import cv2
cap = cv2.VideoCapture('rtsp://192.168.86.81:554/11') # it can be rtsp or http stream

ret, frame = cap.read()

if cap.isOpened():
    _,frame = cap.read()
    cap.release() #releasing camera immediately after capturing picture
    if _ and frame is not None:
        cv2.imwrite('images/latest.jpg', frame)

Answer 2

import cv2
import time
from datetime import datetime
import getpass

#imagesFolder = "C:/Users/<user>/documents"

# 
imagesFolder = "C:/Users/" + getpass.getuser() + "/documents"

#cap = cv2.VideoCapture("rtsp://192.168.86.81:554/11")

# Use public RTSP Streaming for testing, but I am getting black frames!
cap = cv2.VideoCapture("rtsp://192.168.86.81:554/11")
frameRate = cap.get(5) #frame rate
count = 0


while cap.isOpened():
    start_time = time.time()

    frameId = cap.get(1)  # current frame number
    ret, frame = cap.read()

    if (ret != True):
        break

    filename = imagesFolder + "/image_" + str(datetime.now().strftime("%d-%m-%Y_%I-%M-%S_%p"))  + ".jpg"
    cv2.imwrite(filename, frame)

    # Show frame for testing
    cv2.imshow('frame', frame)
    cv2.waitKey(1)

    count += 1

    #Break loop after 5*60 minus
    if count > 5*60:
        break

    elapsed_time = time.time() - start_time

    # Wait for 60 seconds (subtract elapsed_time in order to be accurate).
    time.sleep(60 - elapsed_time)


cap.release()
print ("Done!")

cv2.destroyAllWindows()

Python -> OpenCV -> 保存一张图像并结束程序

Python -> OpenCV -> save one image and end program

python

opencv

rtsp