如何在 SQLCMD 中将数组作为变量传递

How to pass array as variable in SQLCMD

我试图在 sql 脚本中传递服务器名称,但它不起作用。 请帮助

SQL 脚本 patch_report.sql,我 运行 通过 powershell 给出错误

SELECT * from table where server in ('$(trimsqlstr)')

错误

Msg 102,level Level 15, State 1, Server DBserver, Line 1
Incorrect syntax near 'server1'.
$DB_server = 'DBserver'
$serverName = "server1
server2
server3
"
$serverName = $serverName -split "\n" | foreach {$_.ToString().TrimEnd()}
$trimsqlstr = foreach($server in $serverName){
if ($serverName.Indexof($server) -eq $($serverName.Length-1)){
"'$Server'"
} else {
"'$Server',"
}

SQLCMD.exe -v trimsqlstr = "$($trimsqlstr)" -E -S $DB_server -W -i patch_report.sql

我期待这样的结果

SELECT * from table where server in ('server1','server2','server3')

您可以使用以下代码:

$DB_server = 'DBserver'
$serverName = "server1
server2
server3
"

$serverName = $serverName -split "\n" | foreach {$_.ToString().TrimEnd()}
ForEach($server in $serverName) 
{
$serverstring = $serverstring+"'"+$server+"'"+","
}
$trimsqlstr = $serverstring.Substring(0, $serverstring.Length-4)

然后在如下查询中使用 $trimsqlstr

SELECT * from table where server in ($trimsqlstr)

接受的答案是一个很好的解决方案,我只想向您指出 -join 运算符。

-join 运算符对于将数组成员连接到字符串非常实用。

你可以这样做:

$serverNames = "server1
server2
server3
"

$serverNameArray = $serverNames -split "\n" | foreach {$_.ToString().TrimEnd()} | Where-Object {$_} | foreach {"'$_'"}
$whereClause = $serverNameArray -join ','
$selectQuery = "SELECT * from table where server in ($whereClause)"

Where-Object {$_} 正在删除空元素。