有没有办法用 preg_split 替换一些引号并省略一些引号？

Question

我正在尝试使用 preg_split()，但结果不是我期望从函数中获得的结果。

我是 php 和整个 preg_split() 场景的新手，我似乎很难理解，至少目前是这样。

$row = "EL10,40,2019-02-06,55555,2019-01-06,ar@email.com,"Text , random text , 52555885/ 48484848484",Yes,One Two,Broke,2019-01-01,000.00,0.00,0.0,0.0,0.0,0.00,0.00,0.0,VRA "Morning";

$row_expl = preg_split('/(?:[^"]*"|)\K\s*(,\s*|$)/',$row);

我希望删除逗号分隔符，同时将逗号留在引号中。

似乎一切正常，唯一的问题出现在最后。它将额外的引号添加到：VRA "Morning"。结果看起来是这样的："VRA ""Morning"""

Answer 1

正则表达式实际上是解决您的问题的错误工具。定义定界符和封闭字符的 CSV 解析器是您需要的工具。

str_getcsv('EL10,40,2019-02-06,55555,2019-01-06,ar@email.com,"Text , random text , 52555885/ 48484848484",Yes,One Two,Broke,2019-01-01,000.00,0.00,0.0,0.0,0.0,0.00,0.00,0.0,VRA "Morning')

str_getcsv 的默认分隔符是 , 并且封闭字符是 " 所以应该全部设置为默认选项。您可以在此处 http://php.net/manual/en/function.str-getcsv.php.

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有没有办法用 preg_split 替换一些引号并省略一些引号？

Is there a way to replace some quotation marks with preg_split and to leave some out?

php

preg-split