设置另一个营业时间,而不是实际时间
Set another Business hour than the time really is
我有一个日期时间维度,日期如下:
Datetime Date hour
--------------------------------------
2026-01-01 00:00:00.0000000 24
2025-12-31 23:00:00.0000000 23
2025-12-31 22:00:00.0000000 22
2025-12-31 21:00:00.0000000 21
2025-12-31 20:00:00.0000000 20
2025-12-31 19:00:00.0000000 19
2025-12-31 18:00:00.0000000 18
2025-12-31 17:00:00.0000000 17
2025-12-31 16:00:00.0000000 16
2025-12-31 15:00:00.0000000 15
2025-12-31 14:00:00.0000000 14
2025-12-31 13:00:00.0000000 13
2025-12-31 12:00:00.0000000 12
2025-12-31 11:00:00.0000000 11
2025-12-31 10:00:00.0000000 10
2025-12-31 09:00:00.0000000 9
2025-12-31 08:00:00.0000000 8
2025-12-31 07:00:00.0000000 7
2025-12-31 06:00:00.0000000 6
2025-12-31 05:00:00.0000000 5
2025-12-31 04:00:00.0000000 4
2025-12-31 03:00:00.0000000 3
2025-12-31 02:00:00.0000000 2
2025-12-31 01:00:00.0000000 1
由于系统时间的原因,我需要将我的工作时间从 6 点开始,但我该怎么做?我可以创建一个带有硬编码值的 temptable 并加入,但必须有更简单的方法吗?
想要的结果:
Datetime Date hour
--------------------------------------
2026-01-01 00:00:00.0000000 19
2025-12-31 23:00:00.0000000 18
2025-12-31 22:00:00.0000000 17
2025-12-31 21:00:00.0000000 16
2025-12-31 20:00:00.0000000 15
2025-12-31 19:00:00.0000000 14
2025-12-31 18:00:00.0000000 13
2025-12-31 17:00:00.0000000 12
2025-12-31 16:00:00.0000000 11
2025-12-31 15:00:00.0000000 10
2025-12-31 14:00:00.0000000 9
2025-12-31 13:00:00.0000000 8
2025-12-31 12:00:00.0000000 7
2025-12-31 11:00:00.0000000 6
2025-12-31 10:00:00.0000000 5
2025-12-31 09:00:00.0000000 4
2025-12-31 08:00:00.0000000 3
2025-12-31 07:00:00.0000000 2
2025-12-31 06:00:00.0000000 1
2025-12-31 05:00:00.0000000 24
2025-12-31 04:00:00.0000000 23
2025-12-31 03:00:00.0000000 22
2025-12-31 02:00:00.0000000 21
2025-12-31 01:00:00.0000000 20
And for any questions about why I dont hold a DateDimension and a
TimeDimension. This cannot forefill my requirements since I have many
more business rules on my datetime dimensions
鉴于您的 [Date hour]
列已经计算完毕,您可以尝试使用模数进行更新:
UPDATE yourTable
SET [Date hour] = 1 + ([Date hour] + 18) % 24;
更好的长期解决方案可能是根据原始日期时间信息将日期小时列设为计算列。请参阅@Larnu 的答案以了解执行此操作的一种方法。
猜测...
UPDATE YourTable
SET [Date hour] = IIF(DATEPART(HOUR,DATEADD(HOUR, -5, [datetime])) = 0,24,DATEPART(HOUR,DATEADD(HOUR, -5, [datetime]));
我有一个日期时间维度,日期如下:
Datetime Date hour
--------------------------------------
2026-01-01 00:00:00.0000000 24
2025-12-31 23:00:00.0000000 23
2025-12-31 22:00:00.0000000 22
2025-12-31 21:00:00.0000000 21
2025-12-31 20:00:00.0000000 20
2025-12-31 19:00:00.0000000 19
2025-12-31 18:00:00.0000000 18
2025-12-31 17:00:00.0000000 17
2025-12-31 16:00:00.0000000 16
2025-12-31 15:00:00.0000000 15
2025-12-31 14:00:00.0000000 14
2025-12-31 13:00:00.0000000 13
2025-12-31 12:00:00.0000000 12
2025-12-31 11:00:00.0000000 11
2025-12-31 10:00:00.0000000 10
2025-12-31 09:00:00.0000000 9
2025-12-31 08:00:00.0000000 8
2025-12-31 07:00:00.0000000 7
2025-12-31 06:00:00.0000000 6
2025-12-31 05:00:00.0000000 5
2025-12-31 04:00:00.0000000 4
2025-12-31 03:00:00.0000000 3
2025-12-31 02:00:00.0000000 2
2025-12-31 01:00:00.0000000 1
由于系统时间的原因,我需要将我的工作时间从 6 点开始,但我该怎么做?我可以创建一个带有硬编码值的 temptable 并加入,但必须有更简单的方法吗?
想要的结果:
Datetime Date hour
--------------------------------------
2026-01-01 00:00:00.0000000 19
2025-12-31 23:00:00.0000000 18
2025-12-31 22:00:00.0000000 17
2025-12-31 21:00:00.0000000 16
2025-12-31 20:00:00.0000000 15
2025-12-31 19:00:00.0000000 14
2025-12-31 18:00:00.0000000 13
2025-12-31 17:00:00.0000000 12
2025-12-31 16:00:00.0000000 11
2025-12-31 15:00:00.0000000 10
2025-12-31 14:00:00.0000000 9
2025-12-31 13:00:00.0000000 8
2025-12-31 12:00:00.0000000 7
2025-12-31 11:00:00.0000000 6
2025-12-31 10:00:00.0000000 5
2025-12-31 09:00:00.0000000 4
2025-12-31 08:00:00.0000000 3
2025-12-31 07:00:00.0000000 2
2025-12-31 06:00:00.0000000 1
2025-12-31 05:00:00.0000000 24
2025-12-31 04:00:00.0000000 23
2025-12-31 03:00:00.0000000 22
2025-12-31 02:00:00.0000000 21
2025-12-31 01:00:00.0000000 20
And for any questions about why I dont hold a DateDimension and a TimeDimension. This cannot forefill my requirements since I have many more business rules on my datetime dimensions
鉴于您的 [Date hour]
列已经计算完毕,您可以尝试使用模数进行更新:
UPDATE yourTable
SET [Date hour] = 1 + ([Date hour] + 18) % 24;
更好的长期解决方案可能是根据原始日期时间信息将日期小时列设为计算列。请参阅@Larnu 的答案以了解执行此操作的一种方法。
猜测...
UPDATE YourTable
SET [Date hour] = IIF(DATEPART(HOUR,DATEADD(HOUR, -5, [datetime])) = 0,24,DATEPART(HOUR,DATEADD(HOUR, -5, [datetime]));