SQL : 获取一列中的最小值和最大值

Question

我有一个 employee table 有名字和工资。

我想打印这 2 列，其中只有 2 条记录，即我收入最高和最低的员工的姓名。

它应该看起来像这样：

Name      Salary  
------------------
James       800  
Samanth    3000

下面的代码不是我想要的，我想要 2 列中的最小值和最大值，每个值有 2 个名称

SELECT 
    name, MIN(salary), MAX(salary)
FROM
    employee

Answer 1

有多种方法可以做到这一点。这只是其中之一。如果他们有相同的 min/max 薪水

，它也可能给出超过 2 条记录

声明@min int, @max int select @min=min(工资),@max=max(工资) 来自 YourTable

SELECT 姓名，来自 YourTable 的工资 where Salary=@min OR Salary=@max

Answer 2

我用的就是这种方式。你可以这样做

DECLARE @minsalary varchar(60)
set @minsalary = (select top 1 concat(Name, ' ', salary) from employee where salary= (select min(salary) from employee) 
)

DECLARE @maxsalary varchar(60)
set @maxsalary = (select top 1 concat(Name, ' ', salary) from employee where salary= (select max(salary) from employee) 
)

select concat(@maxsalary, ' ', @minsalary)

Answer 3

最佳方法取决于数据库，但以下使用标准 SQL：

select max(case when seqnum_asc = 1 then salary end) as min_salary,
       max(case when seqnum_asc = 1 then name end) as min_salary_name,
       max(case when seqnum_desc = 1 then salary end) as max_salary,
       max(case when seqnum_desc = 1 then name end) as max_salary_name      
from (select e.*,
             row_number() over (order by salary asc) as seqnum_asc,
             row_number() over (order by salary desc) as seqnum_desc
      from employee e
     ) e;

Answer 4

如果您正在使用 mysql

，您可以执行以下操作

按薪水第 1 分组所有用户
使用'order by limit 1'
与第 2 步相同以获得最高薪水
联合他们

即使超过 1 个人有 max/min 薪水

，这也能解决问题

SELECT * 
FROM   ( 
                SELECT   group_concat(NAME) AS names , 
                         salary , 
                         'minimum' AS remarks 
                FROM     employee 
                GROUP BY salary 
                ORDER BY salary limit 1)tmp 
UNION ALL 
SELECT * 
FROM   ( 
                SELECT   group_concat(NAME) AS names , 
                         salary , 
                         'maximum' AS remarks 
                FROM     employee 
                GROUP BY salary 
                ORDER BY salary DESC limit 1
    )tmp1

示例输出

names       salary  remarks
tom,jolly   10      minimum
sally     10001   maximum

Answer 5

你可以试试这个。示例输出。

name      MAX(salary)   MIN(salary)
George    9200          9200
James     5000           100
Kanye     3200          3200
Nicole    4500          4500
Samanth   3000          2300
Umut      1500           250
Vladimir  2300           330

示例table 值

id  name      salary
 1  James        800
 2  Samanth     3000
 3  Umut        1500
 4  Umut         250
 5  Nicole      4500
 6  George      9200
 7  Kanye       3200
 8  Vladimir    2300
 9  Vladimir    1000
10  Vladimir     330
11  James       5000
12  James        100
13  Samanth     2300

SELECT name, MAX(salary), MIN(salary) FROM employee GROUP BY name;

Answer 6

我终于想出了一个简单的代码来满足我的需求。

select emp_name, salary
from employees
where salary = (select max(salary) from employees)
union all
select emp_name, salary
from employees
where salary = (select min(salary) from employees);

我不知道 Union。谢谢大家的贡献

Answer 7

您可以使用子查询来做到这一点：

SELECT first_name, salary FROM employees
WHERE salary IN ((SELECT MAX (salary) FROM employees), (SELECT MIN (salary) FROM employees))

SQL : 获取一列中的最小值和最大值

SQL : get Min and Max value in one column

sql

groupwise-maximum