如何在 Scala 中创建自定义赋值运算符
How to create custom assignment operator in Scala
我正在尝试创建一个行为类似于 Int 的自定义数据类型,但具有某些特定的行为和类型(例如,它必须是正数,它必须符合我们数据库的 'integer' 类型等)。
为了使其更友好 class,我想要自定义赋值运算符等,例如我希望所有工作都具有以下内容:
val g: GPID = 1 // create a GPID type with value 1
val g: GPID = 1L // take assignment from a Long (and downcast into Int)
if (g == 1) ... // test the value of GPID type against an Int(1)
这是我目前所拥有的,但我没有得到预期的行为:
case class GPID(value: Int) extends MappedTo[Int] {
require(value >= 1, "GPID must be a positive number")
require(value <= GPDataTypes.integer._2, s"GPID upper bound is ${GPDataTypes.integer._2}")
def this(l: Long) = this(l.toInt)
def GPID = value
def GPID_=(i: Int) = new GPID(i)
def GPID_=(l: Long) = new GPID(l.toInt)
override def toString: String = value.toString
override def hashCode:Int = value
override def equals(that: Any): Boolean =
that match {
case that: Int => this.hashCode == that.hashCode
case that: Long => this.hashCode == that.hashCode
case _ => false
}
}
object GPID {
implicit val writesGPID = new Writes[GPID] {
def writes(g: GPID): JsValue = {
Json.obj(
"GPID" -> g.value
)
}
}
implicit val reads: Reads[GPID] = (
(__ \ "GPID").read[GPID]
)
def apply(l: Long) = new GPID(l.toInt)
implicit def gpid2int(g: GPID): Int = hashCode
implicit def gpid2long(g: GPID): Long = hashCode.toLong
}
我遇到的问题是:
赋值无效,例如:
val g: GPID = 1
隐式转换不起作用,例如:
val i: Int = g
任何帮助将不胜感激...之前没有构建过这样的自定义类型,所以覆盖赋值和隐式转换对我来说是新的...
object TestInt extends App {
class GPID(val value: Int) {
require(value >= 1, "GPID must be a positive number")
require(value <= 10, s"GPID upper bound is 10")
override def equals(that: Any) = value.equals(that)
override def toString = value.toString
// add more methods here (pimp my library)
}
implicit def fromInt(value: Int) = new GPID(value)
implicit def fromInt(value: Long) = new GPID(value.toInt) //possible loss of precision
val g: GPID = 1
val g2: GPID = 1L
if (g == 1)
println("ONE: " + g)
else
println("NOT ONE: " + g)
}
打印:
ONE: 1
我正在尝试创建一个行为类似于 Int 的自定义数据类型,但具有某些特定的行为和类型(例如,它必须是正数,它必须符合我们数据库的 'integer' 类型等)。
为了使其更友好 class,我想要自定义赋值运算符等,例如我希望所有工作都具有以下内容:
val g: GPID = 1 // create a GPID type with value 1
val g: GPID = 1L // take assignment from a Long (and downcast into Int)
if (g == 1) ... // test the value of GPID type against an Int(1)
这是我目前所拥有的,但我没有得到预期的行为:
case class GPID(value: Int) extends MappedTo[Int] {
require(value >= 1, "GPID must be a positive number")
require(value <= GPDataTypes.integer._2, s"GPID upper bound is ${GPDataTypes.integer._2}")
def this(l: Long) = this(l.toInt)
def GPID = value
def GPID_=(i: Int) = new GPID(i)
def GPID_=(l: Long) = new GPID(l.toInt)
override def toString: String = value.toString
override def hashCode:Int = value
override def equals(that: Any): Boolean =
that match {
case that: Int => this.hashCode == that.hashCode
case that: Long => this.hashCode == that.hashCode
case _ => false
}
}
object GPID {
implicit val writesGPID = new Writes[GPID] {
def writes(g: GPID): JsValue = {
Json.obj(
"GPID" -> g.value
)
}
}
implicit val reads: Reads[GPID] = (
(__ \ "GPID").read[GPID]
)
def apply(l: Long) = new GPID(l.toInt)
implicit def gpid2int(g: GPID): Int = hashCode
implicit def gpid2long(g: GPID): Long = hashCode.toLong
}
我遇到的问题是:
赋值无效,例如:
val g: GPID = 1
隐式转换不起作用,例如:
val i: Int = g
任何帮助将不胜感激...之前没有构建过这样的自定义类型,所以覆盖赋值和隐式转换对我来说是新的...
object TestInt extends App {
class GPID(val value: Int) {
require(value >= 1, "GPID must be a positive number")
require(value <= 10, s"GPID upper bound is 10")
override def equals(that: Any) = value.equals(that)
override def toString = value.toString
// add more methods here (pimp my library)
}
implicit def fromInt(value: Int) = new GPID(value)
implicit def fromInt(value: Long) = new GPID(value.toInt) //possible loss of precision
val g: GPID = 1
val g2: GPID = 1L
if (g == 1)
println("ONE: " + g)
else
println("NOT ONE: " + g)
}
打印:
ONE: 1